Chapter 6

Introductory Algebra for College Students · 696 exercises

Problem 88

What is a quadratic equation?

3 step solution

Problem 88

Without actually factoring and without multiplying the given factors, explain why the following factorization is not correct: $$x^{2}+46 x+513=(x-27)(x-19)$$

3 step solution

Problem 88

Factor using the formula for the sum or difference of two cubes. $$x^{3} y^{3}-27$$

3 step solution

Problem 88

Factor each polynomial. $$16 x^{2} y^{2} z^{2}+32 x^{2} y z^{2}+24 x^{2} y z$$

3 step solution

Problem 88

Factor completely. $$-10 x^{2} y^{4}+14 x y^{4}+12 y^{4}$$

5 step solution

Problem 89

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$3 a^{2}+27 a b+54 b^{2}$$

4 step solution

Problem 89

Explain how to solve \(x^{2}+6 x+8=0\) using factoring and the zero-product principle.

3 step solution

Problem 89

Factor using the formula for the sum or difference of two cubes. $$27 y^{4}+8 y$$

3 step solution

Problem 89

Factor each polynomial. $$x^{3}-4+3 x^{3} y-12 y$$

2 step solution

Problem 89

Factor completely. $$30(y+1) x^{2}+10(y+1) x-20(y+1)$$

5 step solution

Problem 90

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$3 a^{2}+15 a b+18 b^{2}$$

4 step solution

Problem 90

If \((x+2)(x-4)=0\) indicates that \(x+2=0\) or \(x-4=0,\) explain why \((x+2)(x-4)=6\) does not mean \(x+2=6\) or \(x-4=6 .\) Could we solve the equation using \(x+2=3\) and \(x-4=2\) because \(3 \cdot 2=6 ?\)

5 step solution

Problem 90

Factor each polynomial. $$x^{3}-5+2 x^{3} y-10 y$$

2 step solution

Problem 90

Factor completely. $$6(y+1) x^{2}+33(y+1) x+15(y+1)$$

4 step solution

Problem 91

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$48 x^{4} y-3 x^{2} y$$

5 step solution

Problem 91

Determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. It's easy to factor \(x^{2}+x+1\) because of the relatively small numbers for the constant term and the coefficient of \(x\)

4 step solution

Problem 91

Factor each polynomial. $$4 x^{5}(x+1)-6 x^{3}(x+1)-8 x^{2}(x+1)$$

3 step solution

Problem 91

a. Factor \(2 x^{2}-5 x-3\) b. Use the factorization in part (a) to factor $$2(y+1)^{2}-5(y+1)-3$$ Then simplify each factor.

3 step solution

Problem 92

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$16 a^{3} b^{2}-4 a b^{2}$$

4 step solution

Problem 92

Determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. I factor \(x^{2}+b x+c\) by finding two numbers that have a product of \(c\) and a sum of \(b\)

4 step solution

Problem 92

Factor each polynomial. $$8 x^{5}(x+2)-10 x^{3}(x+2)-2 x^{2}(x+2)$$

3 step solution

Problem 92

Factor using the formula for the sum or difference of two cubes. $$128-250 y^{3}$$

3 step solution

Problem 92

a. Factor \(3 x^{2}+5 x-2\) b. Use the factorization in part (a) to factor$$3(y+1)^{2}+5(y+1)-2$$ Then simplify each factor.

2 step solution

Problem 93

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$16 a^{2}-32 a b+12 b^{2}$$

5 step solution

Problem 93

Determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. Because some trinomials are prime, some quadratic equations cannot be solved by factoring.

3 step solution

Problem 93

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. One factor of \(x^{2}+x+20\) is \(x+5\)

4 step solution

Problem 93

Factor each polynomial. $$3 x^{5}-3 x^{4}+x^{3}-x^{2}+5 x-5$$

3 step solution

Problem 93

Factor using the formula for the sum or difference of two cubes. $$64 x^{3}+27 y^{3}$$

3 step solution

Problem 93

Divide \(3 x^{3}-11 x^{2}+12 x-4\) by \(x-2\) Use the quotient to factor \(3 x^{3}-11 x^{2}+12 x-4\) completely.

3 step solution

Problem 94

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$16 a^{2}-32 a b+12 b^{2}$$

6 step solution

Problem 94

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. A trinomial can never have two identical factors.

3 step solution

Problem 94

Factor each polynomial. $$7 x^{5}-7 x^{4}+x^{3}-x^{2}+3 x-3$$

3 step solution

Problem 94

Factor using the formula for the sum or difference of two cubes. $$8 x^{3}+27 y^{3}$$

3 step solution

Problem 94

Divide \(2 x^{3}+x^{2}-13 x+6\) by \(x-2\) Use the quotient to factor \(2 x^{3}+x^{2}-13 x+6\) completely.

2 step solution

Problem 95

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$7 x^{5} y-7 x y^{5}$$

6 step solution

Problem 95

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. One factor of \(y^{2}+5 y-24\) is \(y-3\)

3 step solution

Problem 95

Factor using the formula for the sum or difference of two cubes. $$125 x^{3}-64 y^{3}$$

3 step solution

Problem 96

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$3 x^{4} y^{2}-3 x^{2} y^{2}$$

3 step solution

Problem 96

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. \(x^{2}+4=(x+2)(x+2)\)

4 step solution

Problem 96

Factor using the formula for the sum or difference of two cubes. $$125 x^{3}-y^{3}$$

3 step solution

Problem 97

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$10 x^{3} y-14 x^{2} y^{2}+4 x y^{3}$$

3 step solution

Problem 97

Find all positive integers \(b\) so that the trinomial can be factored. \(x^{2}+b x+15\)

3 step solution

Problem 97

An explosion causes debris to rise vertically with an initial velocity of 64 feet per second. The polynomial \(64 x-16 x^{2}\) describes the height of the debris above the ground, in feet, after \(x\) seconds. a. Find the height of the debris after 3 seconds. b. Factor the polynomial. c. Use the factored form of the polynomial in part (b) to find the height of the debris after 3 seconds. Do you get the same answer as you did in part (a)? If so, does this prove that your factorization is correct? Explain.

3 step solution

Problem 97

Factor completely. (Hint on Exercises \(97-102\) : Factors contain rational numbers.) $$25 x^{2}-\frac{4}{49}$$

2 step solution

Problem 97

Explain how to factor \(2 x^{2}-x-1\).

6 step solution

Problem 98

Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$18 x^{3} y+57 x^{2} y^{2}+30 x y^{3}$$

4 step solution

Problem 98

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. Both 0 and \(-\pi\) are solutions of the equation \(x(x+\pi)=0\)

2 step solution

Problem 98

An explosion causes debris to rise vertically with an initial velocity of 72 feet per second. The polynomial \(72 x-16 x^{2}\) describes the height of the debris above the ground, in feet, after \(x\) seconds. a. Find the height of the debris after 4 seconds. b. Factor the polynomial. c. Use the factored form of the polynomial in part (b) to find the height of the debris after 4 seconds. Do you get the same answer as you did in part (a)? If so, does this prove that your factorization is correct? Explain

4 step solution

Problem 98

Factor completely. (Hint on Exercises \(97-102\) : Factors contain rational numbers.) $$16 x^{2}-\frac{9}{25}$$

3 step solution

Problem 98

Why is it a good idea to factor out the GCF first and then use other methods of factoring? Use \(3 x^{2}-18 x+15\) as an example. Discuss what happens if one first uses trial and error to factor as two binomials rather than first factoring out the GCF.

4 step solution

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