Problem 88

Question

Factor each polynomial. $$16 x^{2} y^{2} z^{2}+32 x^{2} y z^{2}+24 x^{2} y z$$

Step-by-Step Solution

Verified
Answer
The factored form of the polynomial \(16 x^{2} y^{2} z^{2}+32 x^{2} y z^{2}+24 x^{2} y z\) is \(8x^{2}y z(2y z + 4z + 3)\).
1Step 1: Identify the common factors
Firstly, identify the greatest common factor (GCF) in each term of the polynomial. In \(16 x^{2} y^{2} z^{2}\), \(32 x^{2} y z^{2}\), and \(24 x^{2} y z\), the GCF is \(8x^{2}yz\).
2Step 2: Divide each term by their GCF
The next step is to divide each term in the expression by the identified GCF. So the terms become \(2y^{1}z^{1}\), \(4 z^{1}\) and \(3\) respectively.
3Step 3: Write the final factored form
Now that we have factored out the GCF and simplified each term, the final factored form of the polynomial is the GCF multiplied by the simplified expressions. Hence the factored form of the polynomial is \(8x^{2}y z(2y z + 4z + 3)\).