Chapter 11

Beginning and Intermediate Algebra · 325 exercises

Problem 1

An equation in the form \(a x^{2}+b x+c=0,\) where \(a, b,\) and \(c\) are real numbers and \(a \neq 0,\) is \(\mathrm{a}(\mathrm{n})\) _________ equation, also called a(n) ________ degree equation. The greatest degree of the variable is _____.

4 step solution

Problem 1

Which step is an appropriate way to begin solving the quadratic equation \(2 x^{2}-4 x=9\) by completing the square? A. Add 4 to each side. B. Factor the left side as \(2 x(x-2)\) C. Factor the left side as \(x(2 x-4)\). D. Divide each side by 2 .

3 step solution

Problem 2

Which of the following are quadratic equations? A. \(x+2 y=0\) B. \(x^{2}-8 x+16=0\) C. \(2 x^{2}-5 x=3\) D. \(x^{3}+x^{2}+4=0\)

5 step solution

Problem 2

What is the first step in solving a formula like \(g w^{2}=2 r\) for \(w ?\)

2 step solution

Problem 2

Which step is an appropriate way to begin solving the quadratic equation \(x^{2}+12 x=13\) by completing the square? A. Add 36 to each side. B. Subtract 13 from each side. C. Divide each side by \(x\). D. Add 6 to each side.

3 step solution

Problem 3

A student solved \(5 x^{2}-5 x+1=0\) incorrectly as follows. $$ \begin{array}{l} x=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(5)(1)}}{2(5)} \\ x=\frac{5 \pm \sqrt{5}}{10} \\ x=\frac{1}{2} \pm \sqrt{5} \end{array} $$

7 step solution

Problem 3

How can we determine the number of \(x\) -intercepts of the graph of a quadratic function without graphing the function?

4 step solution

Problem 3

Match each quadratic function in Column I with the description of the parabola that is its graph in Column II. I (a) \(f(x)=(x-4)^{2}-2\) (b) \(f(x)=(x-2)^{2}-4\) (c) \(f(x)=(x+4)^{2}+2\) (d) \(f(x)=-(x-4)^{2}-2\) (e) \(f(x)=-(x-2)^{2}-4\) (f) \(f(x)=-(x-4)^{2}+2\) II A. Vertex \((2,-4),\) opens down B. Vertex \((2,-4),\) opens up C. Vertex \((4,-2),\) opens down D. Vertex \((4,-2),\) opens up E. Vertex \((4,2),\) opens down F. Vertex \((-4,2),\) opens up

3 step solution

Problem 3

Which quadratic equation is in standard form? A. \(x^{2}=25\) B. \(3 x^{2}-x=4\) C. \((x-5)^{2}=16\) D. \(x^{2}-x-2=0\)

6 step solution

Problem 3

Based on the discussion and examples of this section, give the first step to solve each equation. Do not actually solve. \(\left(x^{2}+x\right)^{2}-8\left(x^{2}+x\right)+12=0\)

2 step solution

Problem 4

Give the correct solution set. A student incorrectly claimed that the equation \(2 x^{2}-5=0\) cannot be solved using the quadratic formula because there is no first-degree x-term.

5 step solution

Problem 4

For the quadratic function \(f(x)=a(x-h)^{2}+k,\) in what quadrant is the vertex if the values of \(h\) and \(k\) are as follows? (a) \(h>0, k>0\) (b) \(h>0, k<0\) (c) \(h<0, k>0\) (d) \(h<0, k<0\) Consider the value of \(a\), and make the correct choice. (e) If \(a>0,\) then the graph opens (up/down). (f) If \(a<0,\) then the graph opens (up/down). (g) If \(|a|>1,\) then the graph is (narrower / wider) than the graph of \(f(x)=x^{2}\). (h) If \(0<|a|<1,\) then the graph is (narrower / wider) than the graph of \(f(x)=x^{2}\).

5 step solution

Problem 4

The equation \(x^{2}=-9\) has solutions that (are/are not) real numbers. These solutions involve the imaginary unit \(i,\) which is defined as \(i=\) ________ Thus, \(i^{2}=\) ____________ For any positive real number \(a\), we have \(\sqrt{-a}=\) __________.

4 step solution

Problem 4

Why is it particularly important to check all proposed solutions to an applied problem against the information in the original problem?

5 step solution

Problem 5

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ x^{2}-8 x+15=0 $$

6 step solution

Problem 5

Identify the vertex of each parabola. $$ f(x)=-3 x^{2} $$

3 step solution

Problem 5

Match each equation in Column I with the correct description of its solution in Column II. I (a) \(x^{2}=12\) (b) \(x^{2}=-16\) (c) \(x^{2}=\frac{25}{36}\) (d) \(x^{2}=100\) II A. Two nonreal complex B. Two integer solutions solutions C. Two irrational solutions D. Two rational solutions that are not integers

4 step solution

Problem 5

Which equations have a graph that is a vertical parabola? A horizontal parabola? A. \(y=-x^{2}+20 x+80\) B. \(x=2 y^{2}+6 y+5\) C. \(x+1=(y+2)^{2}\) D. \(f(x)=(x-4)^{2}\)

3 step solution

Problem 6

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ x^{2}+3 x-28=0 $$

4 step solution

Problem 6

A student incorrectly solved the following equation as shown. $$ \begin{array}{r} x^{2}-x-2=4 \\ (x-2)(x+1)=4 \\ x-2=4 \text { or } x+1=4 \\ x=6 \quad \text { or } \quad x=3 \end{array} $$ Solve correctly and give the solution set.

5 step solution

Problem 6

Identify the vertex of each parabola. $$ f(x)=-4 x^{2} $$

5 step solution

Problem 7

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 6 x^{2}+11 x-10=0 $$

6 step solution

Problem 7

A student solving \(x^{2}=81\) wrote the solution set incorrectly as \(\\{9\\} .\) Her teacher did not give her full credit. The student argued that because \(9^{2}=81,\) her answer had to be correct. Give the correct solution set.

6 step solution

Problem 7

Identify the vertex of each parabola. $$ f(x)=\frac{1}{3} x^{2} $$

5 step solution

Problem 7

Solve each equation. Check the solutions. \(\frac{14}{x}=x-5\)

5 step solution

Problem 7

Find the vertex of each parabola. $$ f(x)=x^{2}+8 x+10 $$

4 step solution

Problem 8

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 8 x^{2}+10 x-3=0 $$

5 step solution

Problem 8

When solving a quadratic equation, a student obtained the solutions \(x=\frac{3+2 \sqrt{5}}{2}\) or \(x=\frac{3-2 \sqrt{5}}{2}\) and he wrote the solution set incorrectly as \(\\{3 \pm \sqrt{5}\\}\). Give the correct solution set.

3 step solution

Problem 8

Identify the vertex of each parabola. $$ f(x)=\frac{1}{2} x^{2} $$

3 step solution

Problem 8

Solve each equation. Check the solutions. \(\frac{-12}{x}=x+8\)

4 step solution

Problem 8

Find the vertex of each parabola. $$ f(x)=x^{2}+10 x+23 $$

3 step solution

Problem 9

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 4 x^{2}+12 x+9=0 $$

5 step solution

Problem 9

Solve using the zero-factor property. $$ x^{2}-x-56=0 $$

5 step solution

Problem 9

Identify the vertex of each parabola. $$ f(x)=x^{2}+4 $$

3 step solution

Problem 9

Solve each equation. Check the solutions. \(-\frac{3}{x}-\frac{28}{x^{2}}=0\)

6 step solution

Problem 9

Find the vertex of each parabola. $$ f(x)=-2 x^{2}+4 x-5 $$

4 step solution

Problem 10

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 16 x^{2}+40 x+25=0 $$

6 step solution

Problem 10

Solve using the zero-factor property. $$ x^{2}-2 x-99=0 $$

5 step solution

Problem 10

Identify the vertex of each parabola. $$ f(x)=x^{2}-4 $$

4 step solution

Problem 10

Solve each equation. Check the solutions. \(4-\frac{7}{r}-\frac{2}{r^{2}}=0\)

4 step solution

Problem 10

Find the vertex of each parabola. $$ f(x)=-3 x^{2}+12 x-8 $$

4 step solution

Problem 11

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 36 x^{2}-12 x+1=0 $$

5 step solution

Problem 11

Solve using the zero-factor property. $$ x^{2}-8 x+15=0 $$

4 step solution

Problem 11

Identify the vertex of each parabola. $$ f(x)=(x-1)^{2} $$

3 step solution

Problem 11

Solve each equation. Check the solutions. \(3-\frac{1}{t}=\frac{2}{t^{2}}\)

5 step solution

Problem 11

Find the vertex of each parabola. $$ f(x)=x^{2}+x-7 $$

4 step solution

Problem 11

Solve each formula for the specified variable. (Leave \(\pm\) in the answers as needed.) See Examples I and 2. \(I=\frac{k s}{d^{2}}\) for \(d\)

3 step solution

Problem 12

Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 9 x^{2}-6 x+1=0 $$

6 step solution

Problem 12

Solve using the zero-factor property. $$ x^{2}-6 x+5=0 $$

4 step solution

Problem 12

Identify the vertex of each parabola. $$ f(x)=(x+3)^{2} $$

3 step solution

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Chapter 11 - Beginning and Intermediate Algebra Solutions | StudyQuestionHub