Problem 3
Question
How can we determine the number of \(x\) -intercepts of the graph of a quadratic function without graphing the function?
Step-by-Step Solution
Verified Answer
Use the discriminant \(b^2 - 4ac\). If it's >0, there are 2 x-intercepts; if it's 0, there is 1 x-intercept; if it's <0, there are no x-intercepts.
1Step 1: Understand the quadratic function
A quadratic function is generally written as: \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. The x-intercepts are the points where the graph intersects the x-axis.
2Step 2: Set the function equal to zero
To find the x-intercepts, set the quadratic function equal to zero: \(ax^2 + bx + c = 0\). This equation is called the quadratic equation.
3Step 3: Use the quadratic formula
The quadratic formula \(x = \frac{-b \, ± \, \sqrt{b^2 - 4ac}}{2a}\) is used to find the roots (x-intercepts) of the quadratic equation.
4Step 4: Determine the discriminant
Identify the discriminant \(b^2 - 4ac\) within the quadratic formula. The value of the discriminant indicates the number of x-intercepts: - If \(b^2 - 4ac > 0\), there are two distinct real x-intercepts.- If \(b^2 - 4ac = 0\), there is exactly one real x-intercept (the vertex touches the x-axis).- If \(b^2 - 4ac < 0\), there are no real x-intercepts (the graph does not touch the x-axis).
Key Concepts
x-interceptsquadratic equationdiscriminant
x-intercepts
In a quadratic function, the x-intercepts are the points where the graph intersects the x-axis.
These are the solutions to the equation when the function equals zero.
You can imagine x-intercepts as the 'roots' or 'zeros' of the quadratic equation.
To find x-intercepts, we first set the quadratic function, which is usually in the form of:
\( f(x) = ax^2 + bx + c \) equal to zero: \( ax^2 + bx + c = 0 \). These x-values where the function equals zero are your x-intercepts.
These are the solutions to the equation when the function equals zero.
You can imagine x-intercepts as the 'roots' or 'zeros' of the quadratic equation.
To find x-intercepts, we first set the quadratic function, which is usually in the form of:
\( f(x) = ax^2 + bx + c \) equal to zero: \( ax^2 + bx + c = 0 \). These x-values where the function equals zero are your x-intercepts.
quadratic equation
The quadratic equation is a second-degree polynomial equation in a single variable x.
Its standard form is written as: \( ax^2 + bx + c = 0 \). Here, 'a', 'b', and 'c' are constants, with 'a' ≠ 0.
Solving the quadratic equation helps us find the roots or x-intercepts.
One common and powerful method to solve it is using the quadratic formula: \( x = \frac{-b \, ± \, \sqrt{b^2 - 4ac}}{2a} \).
The solutions to this formula are where the quadratic graph touches or crosses the x-axis.
Its standard form is written as: \( ax^2 + bx + c = 0 \). Here, 'a', 'b', and 'c' are constants, with 'a' ≠ 0.
Solving the quadratic equation helps us find the roots or x-intercepts.
One common and powerful method to solve it is using the quadratic formula: \( x = \frac{-b \, ± \, \sqrt{b^2 - 4ac}}{2a} \).
The solutions to this formula are where the quadratic graph touches or crosses the x-axis.
discriminant
The discriminant is a component of the quadratic formula and is given by the expression \( b^2 - 4ac \).
The discriminant helps determine the nature and number of the roots of the quadratic equation.
By examining the discriminant, we can understand whether the quadratic function has:
The discriminant tells us a lot with only one calculation, providing essential insight even before we graph the function.
The discriminant helps determine the nature and number of the roots of the quadratic equation.
By examining the discriminant, we can understand whether the quadratic function has:
- Two distinct real x-intercepts (if \( b^2 - 4ac > 0 \) )
- One real x-intercept (if \( b^2 - 4ac = 0 \) ) < li>No real x-intercepts (if \( b^2 - 4ac < 0 \) )
The discriminant tells us a lot with only one calculation, providing essential insight even before we graph the function.
Other exercises in this chapter
Problem 2
Which step is an appropriate way to begin solving the quadratic equation \(x^{2}+12 x=13\) by completing the square? A. Add 36 to each side. B. Subtract 13 from
View solution Problem 3
A student solved \(5 x^{2}-5 x+1=0\) incorrectly as follows. $$ \begin{array}{l} x=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(5)(1)}}{2(5)} \\ x=\frac{5 \pm \sqrt{5}}{10}
View solution Problem 3
Match each quadratic function in Column I with the description of the parabola that is its graph in Column II. I (a) \(f(x)=(x-4)^{2}-2\) (b) \(f(x)=(x-2)^{2}-4
View solution Problem 3
Which quadratic equation is in standard form? A. \(x^{2}=25\) B. \(3 x^{2}-x=4\) C. \((x-5)^{2}=16\) D. \(x^{2}-x-2=0\)
View solution