Problem 12
Question
Identify the vertex of each parabola. $$ f(x)=(x+3)^{2} $$
Step-by-Step Solution
Verified Answer
The vertex is \(-3, 0\).
1Step 1: Identify the form of the function
The given function is in the form \(f(x) = (x + 3)^2\). This is a standard form of a parabola \(f(x) = (x - h)^2 + k\) where the vertex is \((h, k)\).
2Step 2: Compare the given function with standard form
In the given function \(f(x) = (x + 3)^2\), compare it with the standard form \(f(x) = (x - h)^2 + k\) to determine the values of \h\ and \k\. Here, \h = -3\ and \k = 0\.
3Step 3: Determine the vertex
The vertex of the parabola \(f(x) = (x + 3)^2\) is at the point \(-3, 0\).
Key Concepts
Vertex FormCompleting the SquareGraphing Parabolas
Vertex Form
The vertex form of a parabola is very useful for identifying key features like the vertex. In its simplest terms, the vertex form of a parabola equation is written as: \(f(x) = a(x - h)^2 + k\). Here, \( (h, k) \) is the vertex of the parabola.
This form shows how the parabola is shifted from the origin. A positive or negative shift of \( h \) moves the parabola along the x-axis, while \( k \) moves it along the y-axis.
For instance, in the function \( f(x) = (x + 3)^2 \), we can see that it matches the vertex form if we rewrite it as \( f(x) = (x - (-3))^2 + 0 \).
Therefore, its vertex is at \( (-3, 0) \).
Summarizing: The vertex form helps us to quickly determine the vertex and understand the parabola's transformation.
This form shows how the parabola is shifted from the origin. A positive or negative shift of \( h \) moves the parabola along the x-axis, while \( k \) moves it along the y-axis.
For instance, in the function \( f(x) = (x + 3)^2 \), we can see that it matches the vertex form if we rewrite it as \( f(x) = (x - (-3))^2 + 0 \).
Therefore, its vertex is at \( (-3, 0) \).
Summarizing: The vertex form helps us to quickly determine the vertex and understand the parabola's transformation.
Completing the Square
Completing the square is a technique used to manipulate a quadratic equation into its vertex form. This makes it easier to identify the vertex and graph the parabola.
To complete the square, you'll want to transform a standard quadratic equation like \( ax^2 + bx + c \) into the form \( a(x - h)^2 + k \).
Here’s a step-by-step guide:
For example, starting from \( x^2 + 6x + 8 \), completing the square gives us \( (x + 3)^2 - 1 \). The vertex here would be \( (-3, -1) \).
This method is a powerful tool for transforming and understanding quadratics.
To complete the square, you'll want to transform a standard quadratic equation like \( ax^2 + bx + c \) into the form \( a(x - h)^2 + k \).
Here’s a step-by-step guide:
- Start with the quadratic in its standard form.
- Isolate the x-terms by factoring out \( a \) if it's not equal to 1.
- Add and subtract the square of half the coefficient of the x-term inside the parenthesis.
- Simplify to get the vertex form.
For example, starting from \( x^2 + 6x + 8 \), completing the square gives us \( (x + 3)^2 - 1 \). The vertex here would be \( (-3, -1) \).
This method is a powerful tool for transforming and understanding quadratics.
Graphing Parabolas
Graphing parabolas involves plotting their key features on a coordinate plane, and the vertex is one of the most important features.
Here are the main steps for graphing a parabola:
For example, with the function \( f(x) = (x + 3)^2 \), the vertex is at \( (-3, 0) \), and since \( a = 1 \), it opens upwards. Plotting several points near the vertex, you can sketch the parabola's U-shape.
This approach helps in understanding the relationship between the algebraic expression and its graph.
Here are the main steps for graphing a parabola:
- Identify the vertex using the vertex form \( f(x) = a(x - h)^2 + k \).
- Determine the direction of the parabola. If \( a > 0 \), it opens upwards; if \( a < 0 \), it opens downwards.
- Plot additional points by choosing x-values and calculating their corresponding y-values.
- Draw the axis of symmetry through the vertex. This is a vertical line at \( x = h \).
For example, with the function \( f(x) = (x + 3)^2 \), the vertex is at \( (-3, 0) \), and since \( a = 1 \), it opens upwards. Plotting several points near the vertex, you can sketch the parabola's U-shape.
This approach helps in understanding the relationship between the algebraic expression and its graph.
Other exercises in this chapter
Problem 12
Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 9 x^{2}-6 x+1=0 $$
View solution Problem 12
Solve using the zero-factor property. $$ x^{2}-6 x+5=0 $$
View solution Problem 12
Solve each equation. Check the solutions. \(1+\frac{2}{x}=\frac{3}{x^{2}}\)
View solution Problem 12
Find the vertex of each parabola. $$ f(x)=x^{2}-x+5 $$
View solution