Problem 9
Question
Identify the vertex of each parabola. $$ f(x)=x^{2}+4 $$
Step-by-Step Solution
Verified Answer
The vertex of the parabola is (0, 4).
1Step 1: Understanding the vertex form of a parabola
The general form of a quadratic function is given by \[ f(x) = ax^2 + bx + c \]However, the vertex form of a quadratic function is \[ f(x) = a(x-h)^2 + k \]where ( h, k) is the vertex of the parabola.
2Step 2: Compare the given function to the vertex form
The given function is \[ f(x) = x^2 + 4 \]By comparing it to the vertex form \[ f(x) = a(x-h)^2 + k \]we can see that there is no (x-h) term in our function, meaning h = 0 and k = 4.
3Step 3: Identify the vertex
From the comparison in Step 2, it can be concluded that the vertex ( h, k) is (0, 4).Hence, the vertex of the given parabola is at the point (0, 4).
Key Concepts
quadratic functionvertex form
quadratic function
A quadratic function is a type of polynomial function specifically for degree 2 equations. This means any equation where the highest power of the variable, usually denoted as x, is squared. The standard form of a quadratic function is represented as \( f(x) = ax^2 + bx + c \). Quadratic functions are important in algebra because they describe the shape of a parabola when graphed.
Some key features of a quadratic function include:
Some key features of a quadratic function include:
- The coefficient 'a' determines the direction of the parabola. If 'a' is positive, the parabola opens upwards, and if 'a' is negative, it opens downwards.
- The highest or lowest point of the parabola is called the vertex.
- The axis of symmetry is a vertical line that passes through the vertex, dividing the parabola into two mirror images.
- The parabola may or may not intersect the x-axis, and at most it can intersect at two points called the roots or solutions.
vertex form
The vertex form of a quadratic function is a way of writing the equation so that the vertex is easily identifiable. The vertex form is given by \( f(x) = a(x-h)^2 + k \), where \( (h, k) \) is the vertex of the parabola.
This format is particularly useful in easily locating the vertex without performing complex calculations. In the vertex form:
This format is particularly useful in easily locating the vertex without performing complex calculations. In the vertex form:
- \
Other exercises in this chapter
Problem 9
Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 4 x^{2}+12 x+9=0 $$
View solution Problem 9
Solve using the zero-factor property. $$ x^{2}-x-56=0 $$
View solution Problem 9
Solve each equation. Check the solutions. \(-\frac{3}{x}-\frac{28}{x^{2}}=0\)
View solution Problem 9
Find the vertex of each parabola. $$ f(x)=-2 x^{2}+4 x-5 $$
View solution