Chapter 12

Algebra 1: Concepts and Skills · 626 exercises

Problem 6

Simplify the expression. $$ \sqrt{3} \cdot \sqrt{8} $$

3 step solution

Problem 6

Evaluate the function for x 0, 1, 2, 3, and 4. Round your answers to the nearest tenth. $$y=6 \sqrt{x}-3$$

5 step solution

Problem 7

State the basic axiom of algebra that is represented. $$ y+0=y $$

3 step solution

Problem 7

Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypotenuse. $$ b=11, c=61 $$

5 step solution

Problem 7

Determine whether the points are vertices of a right triangle. $$ (-2,0),(-1,0),(1,7) $$

3 step solution

Problem 7

Find the midpoint of the line segment with the given endpoints. \((0,0),(0,10)\)

3 step solution

Problem 7

Evaluate the expression without using a calculator. $$ 9^{3 / 2} $$

3 step solution

Problem 7

Solve the equation. Check for extraneous solutions. $$ 6=\sqrt{x} $$

3 step solution

Problem 7

Simplify the expression. $$ (3+\sqrt{7})^{2} $$

3 step solution

Problem 7

Evaluate the function for x 0, 1, 2, 3, and 4. Round your answers to the nearest tenth. $$y=\sqrt{x+2}$$

7 step solution

Problem 8

State the basic axiom of algebra that is represented. $$ x+(-x)=0 $$

2 step solution

Problem 8

Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypotenuse. $$ a=12, b=35 $$

4 step solution

Problem 8

Determine whether the points are vertices of a right triangle. $$ (2,0),(-2,2),(-3,-5) $$

3 step solution

Problem 8

Find the term that should be added to the expression to create a perfect square trinomial. $$ x^{2}+24 x $$

3 step solution

Problem 8

Find the midpoint of the line segment with the given endpoints. \((2,1),(14,6)\)

3 step solution

Problem 8

Evaluate the expression without using a calculator. $$ \sqrt[3]{343} $$

2 step solution

Problem 8

Solve the equation. Check for extraneous solutions. $$ \sqrt{x}=1 $$

3 step solution

Problem 8

Simplify the expression. $$ \sqrt{3}(5 \sqrt{3}-2 \sqrt{6}) $$

3 step solution

Problem 8

Evaluate the function for x 0, 1, 2, 3, and 4. Round your answers to the nearest tenth. $$y=\sqrt{4 x-1}$$

5 step solution

Problem 9

Copy and complete the proof of the statement: For all real numbers a and b, \((a+b)-b=a\) $$ \begin{aligned} (a+b)-b &=(a+b)+(-b) \\ &=a+[b+(-b)] \\ &=a+0 \\ &=a \end{aligned} $$ Definition of subtraction. Associative property of addition ? _____ ? _____

3 step solution

Problem 9

Solve \(x^{2}-3 x=8\) by completing the square. Solve the equation by using the quadratic formula. Which method did you find easier?

3 step solution

Problem 9

Find the midpoint of the line segment with the given endpoints. Then show that the midpoint is the same distance from each given point. \((-2,0),(6,2)\)

2 step solution

Problem 9

Evaluate the expression without using a calculator. $$ (\sqrt{81})^{3} $$

2 step solution

Problem 9

Solve the equation. Check for extraneous solutions. $$ \sqrt{x}+6=0 $$

3 step solution

Problem 9

Simplify the expression. $$ \frac{4}{\sqrt{13}} $$

3 step solution

Problem 9

Find the domain and the range of the function. $$y=5 \sqrt{x}$$

2 step solution

Problem 10

Prove the theorem. Use the basic axioms of algebra and the definition of subtraction given in Example 1. If \(a\) and \(b\) are real numbers, then \(a-b=-b+a\)

3 step solution

Problem 10

Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (2,0),(8,-3) $$

3 step solution

Problem 10

Solve the quadratic equation by completing the square. $$ x^{2}-2 x-18=0 $$

3 step solution

Problem 10

Find the midpoint of the line segment with the given endpoints. Then show that the midpoint is the same distance from each given point. \((-2,2)(2,-10)\)

3 step solution

Problem 10

Rewrite the expression using rational exponent notation. $$ \sqrt{14} $$

5 step solution

Problem 10

Simplify the expression. $$ \frac{3}{8-\sqrt{10}} $$

3 step solution

Problem 10

Solve the equation. Check for extraneous solutions. $$ \sqrt{x}-20=0 $$

3 step solution

Problem 10

Find the domain and the range of the function. $$y=\sqrt{x}$$

2 step solution

Problem 11

Prove the theorem. Use the basic axioms of algebra and the definition of subtraction given in Example 1. If \(a, b,\) and \(c\) are real numbers, then \((a-b) c=a c-b c\)

4 step solution

Problem 11

Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (2,-8),(-3,3) $$

4 step solution

Problem 11

Solve the quadratic equation by completing the square. $$ x^{2}+10 x-10=0 $$

4 step solution

Problem 11

Find the midpoint of the line segment with the given endpoints. Then show that the midpoint is the same distance from each given point. \((2,6),(4,2)\)

3 step solution

Problem 11

Rewrite the expression using rational exponent notation. $$ \sqrt[3]{11} $$

3 step solution

Problem 11

Solve the equation. Check for extraneous solutions. $$ \sqrt{4 x}-1=3 $$

4 step solution

Problem 11

Simplify the expression. $$ \frac{6}{\sqrt{10}} $$

3 step solution

Problem 11

Find the domain and the range of the function. $$y=\sqrt{x}-10$$

2 step solution

Problem 12

MAKING A CONJECTURE A student proposes the following conjecture: The sum of the first n odd integers is \(\mathrm{n}^{2}\). She gives four examples: \(1=1^{2}, 1+3=4=2^{2}, 1+3+5=9=3^{2},\) and \(1+3+5+7=16=4^{2} .\) Do the examples prove her conjecture? Explain. Do you think the conjecture is true?

3 step solution

Problem 12

Explain how you can use the converse of the Pythagorean theorem to tell whether three given lengths can be sides of a right triangle.

3 step solution

Problem 12

Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (3,-2),(0,3) $$

3 step solution

Problem 12

Solve the quadratic equation by completing the square. $$ x^{2}+8 x=-3 $$

4 step solution

Problem 12

Find the midpoint of the line segment with the given endpoints. Then show that the midpoint is the same distance from each given point. \((-6,0),(-10,-2)\)

3 step solution

Problem 12

Rewrite the expression using rational exponent notation. $$ (\sqrt[3]{5})^{2} $$

3 step solution

Problem 12

Solve the equation. Check for extraneous solutions. $$ x=\sqrt{x+12} $$

5 step solution

Problem 12

Find the domain and the range of the function. $$y=\sqrt{x}+6$$

2 step solution

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