Problem 12
Question
Find the midpoint of the line segment with the given endpoints. Then show that the midpoint is the same distance from each given point. \((-6,0),(-10,-2)\)
Step-by-Step Solution
Verified Answer
The midpoint of the line segment having endpoints (-6,0) and (-10,-2) is (-8, -1), and this point is equidistant from the two given points, with the distance between the midpoint and each endpoint being \(\sqrt{5}\).
1Step 1: Find the Midpoint
The midpoint formula is \((\frac{{x_1 + x_2}}{2}, \frac{{y_1 + y_2}}{2})\), applied to our given data points \((-6,0)\) and \((-10,-2)\), the midpoint is calculated as \(\left(\frac{{-6 + -10}}{2}, \frac{{0 + -2}}{2}\right)\). This results in a midpoint of \((-8,-1)\).
2Step 2: Calculate Distances
The distance formula is \(d = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\). To verify that the midpoint is equidistant from the two endpoints, calculate the distance between the midpoint \((-8,-1)\) and each of the given points. Distance between the midpoint and the point \((-6,0)\) is calculated as \(d1 = \sqrt{{(-8 - -6)^2 + (-1 - 0)^2}}\), yielding \(d1 = \sqrt{5}\). Distance between the midpoint and the point \((-10,-2)\) is calculated as \(d2 = \sqrt{{(-8 - -10)^2 + (-1 - -2)^2}}\), yielding \(d2 = \sqrt{5}\).
3Step 3: Conclusion
As observed, both distances \(d1\) and \(d2\) are equal. Therefore, the midpoint \(M\), found to be \((-8,-1)\), is indeed equidistant from both given points \((-6,0)\) and \((-10,-2)\).
Key Concepts
Coordinate GeometryDistance FormulaMidpoint of a Line Segment
Coordinate Geometry
In the fascinating world of mathematics, coordinate geometry, also known as analytic geometry, is a powerful branch that allows us to analyze geometric shapes and relationships through a system of coordinates. It is essentially a merge of algebra and geometry where points are placed on a grid called the coordinate plane. This grid is defined by a horizontal axis, known as the X-axis, and a vertical axis, dubbed the Y-axis.
Each point on this plane is represented by a pair of numerical values \( (x, y) \) that correspond to its horizontal and vertical positions, respectively. By using these coordinates, we can plot points, draw line segments, and figure out all sorts of calculations such as distances, midpoints, and more.
Each point on this plane is represented by a pair of numerical values \( (x, y) \) that correspond to its horizontal and vertical positions, respectively. By using these coordinates, we can plot points, draw line segments, and figure out all sorts of calculations such as distances, midpoints, and more.
Distance Formula
The distance formula is a fundamental tool in coordinate geometry that enables us to calculate the precise distance between two points in a plane. It's rooted in the Pythagorean Theorem, a principle you might recall from studying right triangles.
Given two points, \( A(x_1, y_1) \) and \( B(x_2, y_2) \), the distance between them is expressed as \( d = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \). This formula reveals the direct line distance 'as the crow flies' and not considering any physical barriers that may exist on a real-world map. It's a crucial concept that students need to grasp for a variety of applications within mathematics, physics, and beyond.
Given two points, \( A(x_1, y_1) \) and \( B(x_2, y_2) \), the distance between them is expressed as \( d = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \). This formula reveals the direct line distance 'as the crow flies' and not considering any physical barriers that may exist on a real-world map. It's a crucial concept that students need to grasp for a variety of applications within mathematics, physics, and beyond.
Midpoint of a Line Segment
Understanding the midpoint of a line segment is vital in dividing any given segment into two equal parts. The midpoint formula \( (\frac{{x_1 + x_2}}{2}, \frac{{y_1 + y_2}}{2}) \) takes the average of the x-coordinates and y-coordinates of the endpoints to find the center point. It's like finding the heart of the segment, equally accessible from both ends.
For instance, if we have endpoints \( A(-6, 0) \) and \( B(-10, -2) \) as in the given problem, we apply the formula to obtain the midpoint \( M(-8, -1) \). This point is not only central in its placement but holds the characteristic of being the same distance from each of the endpoints. The beauty of the midpoint is that it provides a simple yet profound way to understand symmetric relationships in geometry.
For instance, if we have endpoints \( A(-6, 0) \) and \( B(-10, -2) \) as in the given problem, we apply the formula to obtain the midpoint \( M(-8, -1) \). This point is not only central in its placement but holds the characteristic of being the same distance from each of the endpoints. The beauty of the midpoint is that it provides a simple yet profound way to understand symmetric relationships in geometry.
Other exercises in this chapter
Problem 12
Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (3,-2),(0,3) $$
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Solve the quadratic equation by completing the square. $$ x^{2}+8 x=-3 $$
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Rewrite the expression using rational exponent notation. $$ (\sqrt[3]{5})^{2} $$
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Solve the equation. Check for extraneous solutions. $$ x=\sqrt{x+12} $$
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