Chapter 3

University Calculus: Early Transcendentals · 633 exercises

Problem 6

Find \(d y / d x\). $$y=x^{2} \cot x-\frac{1}{x^{2}}$$

3 step solution

Problem 6

Give the positions \(s=f(t)\) of a body moving on a coordinate line, with \(s\) in meters and \(t\) in seconds. a. Find the body's displacement and average velocity for the given time interval. b. Find the body's speed and acceleration at the endpoints of the interval. c. When, if ever, during the interval does the body change direction? $$s=\frac{25}{t+5}, \quad-4 \leq t \leq 0$$

4 step solution

Problem 6

Find the first and second derivatives. $$y=\frac{x^{3}}{3}+\frac{x^{2}}{2}+e^{-x}$$

7 step solution

Problem 6

Using the definition, calculate the derivatives of the functions in Exercises \(1-6 .\) Then find the values of the derivatives as specified. $$r(s)=\sqrt{2 s+1} ; \quad r^{\prime}(0), r^{\prime}(1), r^{\prime}(1 / 2)$$

5 step solution

Problem 7

If \(x^{2}+y^{2}=25\) and \(d x / d t=-2,\) then what is \(d y / d t\) when \(x=3\) and \(y=-4 ?\)

4 step solution

Problem 7

Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=x^{2}+2 x, \quad a=0.1$$

5 step solution

Problem 7

Let \(f(x)=x^{3}-3 x^{2}-1, x \geq 2 .\) Find the value of \(d f^{-1} / d x\) at the point \(x=-1=f(3)\).

4 step solution

Problem 7

In Exercises \(1-8,\) given \(y=f(u)\) and \(u=g(x),\) find \(d y / d x=\) \(f^{\prime}(g(x)) g^{\prime}(x)\). $$y=\tan u, \quad u=\pi x^{2}$$

5 step solution

Problem 7

Use implicit differentiation to find \(d y / d x\). $$y^{2}=\frac{x-1}{x+1}$$

4 step solution

Problem 7

Find \(d y / d x\). $$f(x)=\sin x \tan x$$

6 step solution

Problem 7

At time \(t\), the position of a body moving along the s-axis is \(s=t^{3}-6 t^{2}+9 t\) m. a. Find the body's acceleration each time the velocity is zero. b. Find the body's speed each time the acceleration is zero. c. Find the total distance traveled by the body from \(t=0\) to \(t=2\)

7 step solution

Problem 7

Find the first and second derivatives. $$w=3 z^{-2}-\frac{1}{z}$$

3 step solution

Problem 7

Find the indicated derivatives. $$\frac{d y}{d x}\( if \)y=2 x^{3}$$

3 step solution

Problem 8

If \(x^{2} y^{3}=4 / 27\) and \(d y / d t=1 / 2,\) then what is \(d x / d t\) when \(x=2 ?\)

9 step solution

Problem 8

Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=x^{-1}, \quad a=0.9$$

4 step solution

Problem 8

Let \(f(x)=x^{2}-4 x-5, x>2 .\) Find the value of \(d f^{-1} / d x\) at the point \(x=0=f(5)\).

8 step solution

Problem 8

In Exercises \(1-8,\) given \(y=f(u)\) and \(u=g(x),\) find \(d y / d x=\) \(f^{\prime}(g(x)) g^{\prime}(x)\). $$y=-\sec u, \quad u=\frac{1}{x}+7 x$$

4 step solution

Problem 8

Use implicit differentiation to find \(d y / d x\). $$x^{3}=\frac{2 x-y}{x+3 y}$$

7 step solution

Problem 8

Find \(d y / d x\). $$g(x)=\frac{\cos x}{\sin ^{2} x}$$

9 step solution

Problem 8

At time \(t \geq 0,\) the velocity of a body moving along the horizontal \(s\) -axis is \(v=t^{2}-4 t+3\) a. Find the body's acceleration each time the velocity is zero. b. When is the body moving forward? Backward? c. When is the body's velocity increasing? Decreasing?

5 step solution

Problem 8

Find the first and second derivatives. $$s=-2 r^{-1}+\frac{4}{t^{2}}$$

5 step solution

Problem 8

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. $$y=\frac{1}{x^{2}}, \quad(-1,1)$$

4 step solution

Problem 9

Find the values. $$\sin \left(\cos ^{-1}\left(\frac{\sqrt{2}}{2}\right)\right)$$

4 step solution

Problem 9

If \(L=\sqrt{x^{2}+y^{2}}, d x / d t=-1,\) and \(d y / d t=3,\) find \(d L / d t\) when \(x=5\) and \(y=12\).

4 step solution

Problem 9

Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=2 x^{2}+3 x-3, \quad a=-0.9$$

6 step solution

Problem 9

Suppose that the differentiable function \(y=f(x)\) has an inverse and that the graph of \(f\) passes through the point (2,4) and has a slope of \(1 / 3\) there. Find the value of \(d f^{-1} / d x\) at \(x=4\).

3 step solution

Problem 9

In Exercises \(9-22,\) write the function in the form \(y=f(u)\) and \(u=g(x) .\) Then find \(d y / d x\) as a function of \(x\). $$y=(2 x+1)^{5}$$

6 step solution

Problem 9

Use implicit differentiation to find \(d y / d x\). $$x=\sec y$$

4 step solution

Problem 9

Find \(d y / d x\). $$y=x e^{-x} \sec x$$

6 step solution

Problem 9

The equations for free fall at the surfaces of Mars and Jupiter ( \(s\) in meters, \(t\) in seconds) are \(s=1.86 t^{2}\) on Mars and \(s=11.44 t^{2}\) on Jupiter. How long does it take a rock falling from rest to reach a velocity of \(27.8 \mathrm{m} / \mathrm{sec}\) (about \(100 \mathrm{km} / \mathrm{h}\) ) on each planet?

3 step solution

Problem 9

Find the first and second derivatives. $$y=6 x^{2}-10 x-5 x^{-2}$$

5 step solution

Problem 9

Find the indicated derivatives. $$\frac{d s}{d t}\( if \)s=\frac{t}{2 t+1}$$

6 step solution

Problem 9

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. $$y=x^{3}, \quad(-2,-8)$$

4 step solution

Problem 10

Find the values. $$\sec \left(\cos ^{-1} \frac{1}{2}\right)$$

3 step solution

Problem 10

If \(r+s^{2}+v^{3}=12, d r / d t=4,\) and \(d s / d t=-3,\) find \(d v / d t\) when \(r=3\) and \(s=1\).

5 step solution

Problem 10

Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=1+x, \quad a=8.1$$

4 step solution

Problem 10

Suppose that the differentiable function \(y=g(x)\) has an inverse and that the graph of \(g\) passes through the origin with slope 2 Find the slope of the graph of \(g^{-1}\) at the origin.

3 step solution

Problem 10

In Exercises \(9-22,\) write the function in the form \(y=f(u)\) and \(u=g(x) .\) Then find \(d y / d x\) as a function of \(x\). $$y=(4-3 x)^{9}$$

6 step solution

Problem 10

Use implicit differentiation to find \(d y / d x\). $$x y=\cot (x y)$$

5 step solution

Problem 10

Find \(d y / d x\). $$y=(\sin x+\cos x) \sec x$$

5 step solution

Problem 10

A rock thrown vertically upward from the surface of the moon at a velocity of \(24 \mathrm{m} / \mathrm{sec}\) (about \(86 \mathrm{km} / \mathrm{h})\) reaches a height of \(s=24 t-0.8 t^{2} \mathrm{m}\) in \(t\) sec. a. Find the rock's velocity and acceleration at time \(t .\) (The acceleration in this case is the acceleration of gravity on the moon.) b. How long does it take the rock to reach its highest point? c. How high does the rock go? d. How long does it take the rock to reach half its maximum height? e. How long is the rock aloft?

5 step solution

Problem 10

Find the first and second derivatives. $$y=4-2 x-x^{-3}$$

4 step solution

Problem 10

Find the indicated derivatives. $$\frac{d v}{d t}\( if \)v=t-\frac{1}{t}$$

5 step solution

Problem 10

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together. $$y=\frac{1}{x^{3}}, \quad\left(-2,-\frac{1}{8}\right)$$

5 step solution

Problem 11

Find the values. $$\tan \left(\sin ^{-1}\left(-\frac{1}{2}\right)\right)$$

4 step solution

Problem 11

If the original 24 m edge length \(x\) of a cube decreases at the rate of \(5 \mathrm{m} / \mathrm{min},\) when \(x=3 \mathrm{m}\) at what rate does the cube's a. surface area change? b. volume change?

4 step solution

Problem 11

Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=\sqrt[3]{x}, \quad a=8.5$$

6 step solution

Problem 11

In Exercises \(9-22,\) write the function in the form \(y=f(u)\) and \(u=g(x) .\) Then find \(d y / d x\) as a function of \(x\). $$y=\left(1-\frac{x}{7}\right)^{-7}$$

6 step solution

Problem 11

Use implicit differentiation to find \(d y / d x\). $$x+\tan (x y)=0$$

3 step solution

Problem 11

Find \(d y / d x\). $$y=\frac{\cot x}{1+\cot x}$$

6 step solution

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