Problem 7
Question
Find the first and second derivatives. $$w=3 z^{-2}-\frac{1}{z}$$
Step-by-Step Solution
Verified Answer
First derivative: \( -6z^{-3} + z^{-2} \); Second derivative: \( 18z^{-4} - 2z^{-3} \).
1Step 1: Rewrite the function for easier differentiation
We have the function \( w = 3z^{-2} - \frac{1}{z} \). Rewriting \( \frac{1}{z} \) in exponential form gives \( z^{-1} \). Now the function is \( w = 3z^{-2} - z^{-1} \).
2Step 2: Differentiate to find the first derivative
Use the power rule \( \frac{d}{dz}z^n = nz^{n-1} \) to differentiate. For \( 3z^{-2} \), the derivative is \( -6z^{-3} \), and for \( -z^{-1} \), the derivative is \( z^{-2} \). The first derivative is \( \frac{dw}{dz} = -6z^{-3} + z^{-2} \).
3Step 3: Differentiate again to find the second derivative
Differentiate the first derivative \( \frac{dw}{dz} = -6z^{-3} + z^{-2} \). For \( -6z^{-3} \), the derivative is \( 18z^{-4} \), and for \( z^{-2} \), the derivative is \( -2z^{-3} \). The second derivative is \( \frac{d^2w}{dz^2} = 18z^{-4} - 2z^{-3} \).
Key Concepts
Understanding DerivativesThe Power RuleExploring the Second Derivative
Understanding Derivatives
A derivative is a key concept in calculus, often thought of as a tool that measures how a function changes as its input changes. It provides the rate at which one quantity changes relative to another. When you have a function, say with variable \( z \), its derivative tells you the slope of the tangent to the function at any point on its graph.
- The first derivative of a function is particularly useful because it describes the function's rate of change or its velocity.
- This can indicate where the function is increasing or decreasing.
- For the given function \( w = 3z^{-2} - z^{-1} \), the first derivative \( \frac{dw}{dz} \) reveals the function's behavior with respect to \( z \).
The Power Rule
The power rule is a straightforward way to find derivatives of functions with terms in the form \( z^n \). This rule states:
For any function \( z^n \), \( \frac{d}{dz}z^n = nz^{n-1} \).
It's a fast and effective method that allows us to tackle polynomial functions and power functions with ease.
For any function \( z^n \), \( \frac{d}{dz}z^n = nz^{n-1} \).
It's a fast and effective method that allows us to tackle polynomial functions and power functions with ease.
- In our example, we applied the power rule to each term individually.
- For \( 3z^{-2} \), we multiply \( -2 \) by \( 3 \), giving \( -6z^{-3} \).
- Similarly, for \( -z^{-1} \), multiplying by \( -1 \) results in \( z^{-2} \).
Exploring the Second Derivative
The second derivative provides even more insights into a function's behavior. It is the derivative of the first derivative, giving us the rate of change of the rate of change. This can help identify points of inflection and the concavity of the graph.
- If the second derivative is positive, the function is concave up, resembling a cup \( \cup \).
- If it's negative, the function is concave down, resembling a cap \( \cap \).
- In our exercise, we take the first derivative \( -6z^{-3} + z^{-2} \) and differentiate each term again.
- The derivative of \( -6z^{-3} \) is \( 18z^{-4} \).
- The derivative of \( z^{-2} \) is \( -2z^{-3} \).
Other exercises in this chapter
Problem 7
Find \(d y / d x\). $$f(x)=\sin x \tan x$$
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At time \(t\), the position of a body moving along the s-axis is \(s=t^{3}-6 t^{2}+9 t\) m. a. Find the body's acceleration each time the velocity is zero. b. F
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Find the indicated derivatives. $$\frac{d y}{d x}\( if \)y=2 x^{3}$$
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If \(x^{2} y^{3}=4 / 27\) and \(d y / d t=1 / 2,\) then what is \(d x / d t\) when \(x=2 ?\)
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