Chapter 9
Mathematics for IIT JEE Main and Advanced Differential Calculus Algebra Trigonometry · 307 exercises
Problem 107
Find the three numbers constituting a G.P. if it is known that the sum of the numbers is equal to 26 and that when 1,6 and 3 are added to them respectively, the new numbers are obtained which from an A.P.
4 step solution
Problem 108
Three numbers from a G.P. If the 3rd term is decreased by 64 , then the numbers thus obtained will constitute an A.P. If the second term of this A.P. is decreased by 8 , a G.P. will be formed again. Determine the numbers.
4 step solution
Problem 109
Find the numbers \(a, b, c\) between 2 and 18 such that (i) their sum is 25 (ii) the numbers \(2, a, b\) are consecutive terms of an A.P and (iii) the numbers \(b, c, 18\) are consecutive terms of a G.P.
5 step solution
Problem 110
In a G.P. if the \((m+n)\) th term be \(p\) and \((m-n)\) th term be \(q\), then prove that its \(m\) th term is \(\sqrt{p q}\).
5 step solution
Problem 111
The first and second terms of a GP are \(x^{-4}\) and \(x^{n}\) respectively. If \(x^{52}\) is the eight term of the same progression, then find \(n\).
7 step solution
Problem 112
If \(p, q, r\) are in AP, then show that \(p t h, q t h\) and \(r t h\) terms of any GP are in GP.
6 step solution
Problem 113
If \(a, b, c\) are in AP, \(b-a, c-b\) and \(a\) are in GP, then find \(a: b: c\).
3 step solution
Problem 114
If the roots of \(\left(a^{2}+b^{2}\right) x^{2}-2 b(a+c) x+\left(b^{2}+c^{2}\right)\) are equal then show that \(a, b, c\) are in GP.
5 step solution
Problem 115
Let \(\left\\{a_{n}\right\\}\) be a GP such that \(\frac{a_{4}}{a_{6}}=\frac{1}{4}\) and \(a_{2}+a_{5}=216\). Then find \(a_{1}\).
3 step solution
Problem 116
The \(r\) th, \(s\) th and \(t\) th terms of a certain G.P. are \(R, S\) and \(T\) respectively. Prove that \(R^{s-t} \cdot S^{t-r} \cdot T^{r-s}=1\).
3 step solution
Problem 117
The fourth, seventh and tenth terms of a GP are \(p, q, r\) respectively, then show that \(q^{2}=p r\).
4 step solution
Problem 118
If \(x, y, z\) be respectively the \(p t h, q\) th and \(r\) th terms of a G.P., then prove that \((q-r) \log x+(r-p) \log y+(p-q) \log z=0\)
4 step solution
Problem 119
If the \(p\) th, \(q\) th, \(r\) th terms of an A.P. are in G.P. show that common ratio of the G.P. is \(\frac{q-r}{p-q}\).
3 step solution
Problem 120
If \(a, b, c, d\) be in G.P., prove that i. \(\left(a^{2}+a c+c^{2}\right)\left(b^{2}+b d+d^{2}\right)=(a b+b c+c d)^{2}\); ii. \(\left(a^{2}+b^{2}+c^{2}\right)\left(b^{2}+c^{2}+d^{2}\right)=(a b+b c+c d)^{2}\).
2 step solution
Problem 121
If \(a, b, c\) be in G.P., then prove that \(\frac{a^{2}+a b+b^{2}}{b c+c a+a b}=\frac{b+a}{c+b}\).
4 step solution
Problem 122
If \(a, b, c\) are three distinct real numbers in G.P. and \(a+b+c=x b\), then prove that either \(x<-1\) or \(x>3\).
4 step solution
Problem 123
Find all the numbers \(x\) and \(y\) and such that \(x, x+2 y, 2 x+y\) from an A.P. while the numbers \((y+1)^{2}\), \(x y+5,(x+1)^{2}\) form a G.P. Write down the progressions.
4 step solution
Problem 124
If \(a, b, c, x\) are all real numbers, and \(\left(a^{2}+b^{2}\right) x^{2}-2 b(a+c) x+\left(b^{2}+c^{2}\right)=0\) then show that \(a, b, c\) are in G.P., and \(x\) is their common ratio.
6 step solution
Problem 125
If \(a^{\frac{1}{x}}=b^{\frac{1}{y}}=c^{\frac{1}{z}}\) and \(a, b, c\) be in G.P. then prove that \(x, y, z\) are in A.P.
5 step solution
Problem 126
If \(a, b, c\) be in G.P. then prove that \(\log a^{n}, \log b^{n}, \log c^{n}\) are in A.P.
3 step solution
Problem 127
If the \(m\) th, \(n\) th, and \(p\) th terms of an A.P. and G.P. be equal and be respectively \(x, y\) and \(z\), then prove that \(x^{y-z} \cdot y^{z-x} \cdot z^{x-y}=1\)
7 step solution
Problem 128
If \(a, b, c\) are in G.P. and \(x, y\) respectively be arithmetic means between \(a, b\) and \(b, c\), then prove that \(\frac{a}{x}+\frac{c}{y}=2\) and \(\frac{1}{x}+\frac{1}{y}=\frac{2}{b}\)
4 step solution
Problem 129
If \(a, b, c\) be distinct positive and in G.P. and \(\log _{c} a, \log _{b} c, \log _{a} b\) be in A.P. then show that the common difference of this A.P. is \(\frac{3}{2}\).
4 step solution
Problem 130
Prove that the three successive terms of a G.P. will form the sides of a
triangle if the common ratio \(r\) satisfies the inequality
\(\frac{1}{2}(\sqrt{5}-1)
4 step solution
Problem 131
The fifth term of a G.P. is 81 whereas its second term is 24 . Find the series and sum of its first eight terms.
4 step solution
Problem 132
The sum of first three of a G.P. is to the sum of the first six terms as \(125: 152\). Find the common ratio of the G.P.
8 step solution
Problem 133
For a sequence \(\left\\{a_{n}\right\\}, a_{1}=2\) and \(\frac{a_{n+1}}{a_{n}}=\frac{1}{3}\). Then find the value of \(\sum_{r=1}^{20} a_{r}\).
4 step solution
Problem 134
Find the value of \(9^{\frac{1}{3}} \cdot 9^{\frac{1}{9}} \cdot 9^{\frac{1}{27}} \ldots \ldots \ldots .\) upto \(\infty\).
5 step solution
Problem 135
Find the value of \(x^{\frac{1}{2}} \cdot x^{\frac{1}{4}} \cdot x^{\frac{1}{8}} \cdot x^{\frac{1}{16}} \ldots \ldots\)
3 step solution
Problem 136
If \(S=1+2+4+8+16+32+\ldots \ldots \infty\), then \(S\) is a positive number. Multiply both sides by 2 , then it is found that \(2 S=S-1\) which leads to conclusion \(S=-1\) which is certainly negative. Do you agree with the conclusion? Your answer should be supported by explanation.
3 step solution
Problem 137
The first term of an infinite G.P. is 1 and any term is equal to the sum of all the succeeding terms. Find the series.
3 step solution
Problem 138
The sum of first two terms of an infinite G.P. is 5 and each term is three times the sum of succeeding terms. Find the series.
4 step solution
Problem 139
Sum of a certain number of terms of the series \(\frac{2}{9}-\frac{1}{3}+\frac{1}{2}-\cdots \cdots\) is \(\frac{55}{72}\). Find the number.
4 step solution
Problem 140
How many terms of the series \(1,4,16, \ldots\) must be taken to have their sum equal to 341 ?
4 step solution
Problem 141
In a G.P. sum of \(n\) terms is 255 , the last term is 128 and common ratio is 2 . Find \(n\).
5 step solution
Problem 142
In an increasing G.P., the sum of the first and the last term is 66, the product of the second and the last but one term is 128 , and the sum of all the terms is 126 . How many terms are there in the progression?
3 step solution
Problem 143
In a G.P. sum of \(n\) terms is 364 , first term is 1 and the common ratio is 3 . Find \(n\).
3 step solution
Problem 144
Express the recurring decimal \(0.125125125 \ldots \ldots\) as a rational number.
5 step solution
Problem 145
Find the value of \(0.1 \overline{23}\) regarding it as a geometric series.
8 step solution
Problem 146
Find the value of \(0.4 \overline{23}\).
4 step solution
Problem 147
Find the value of \(2 . \overline{357}\)
4 step solution
Problem 148
After striking a floor a certain ball rebounds \(\frac{4}{5}\) th of the height from which it has fallen. Find the total distance that it travels before coming to rest, if it is gently dropped from a height of 120 meters.
3 step solution
Problem 149
A ball is dropped from a height of \(48 \mathrm{ft}\). and rebounds two-third of the distance it falls. If it continues to fall and rebound in this way, how far will it travel before coming to rest?
4 step solution
Problem 150
A GP consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying odd places, then find the common ratio.
5 step solution
Problem 151
If in an infinite GP, first term is equal to 10 times the sum of all successive terms, then find its common
4 step solution
Problem 152
If second term of a GP is 2 and the sum of its infinite terms is 8 , then find its first term.
5 step solution
Problem 153
Find the sum of the term of an infinitely decreasing G.P. in which all the terms are positive, the first term is 4, and the difference between the third and fifth term is equal to \(\frac{32}{81}\).
4 step solution
Problem 154
The sum of an infinite geometric progression is 2 and the sum of the geometric progression made from the cube of the terms of this infinite series is 24 . Then find the series.
5 step solution
Problem 155
If the sum of an infinite GP be 3 and the sum of squares of its term is also 3 , then find its first term and common ratio.
5 step solution
Problem 156
The length of a side of a square is \(a\) meters. A second square is formed by joining the middle points of this square. Then a third square is formed by joining the middle points of the second square and so on. The process is carried on ad-infinitum. Find the sum of the areas of the squares.
5 step solution