Problem 125
Question
If \(a^{\frac{1}{x}}=b^{\frac{1}{y}}=c^{\frac{1}{z}}\) and \(a, b, c\) be in G.P. then prove that \(x, y, z\) are in A.P.
Step-by-Step Solution
Verified Answer
The short answer is:
By manipulating the given equation according to the definitions of G.P. and A.P., we are able to write two equations, both equal to \(\frac{\ln{r}}{\ln{a}}\), representing the differences between consecutive terms \(x\), \(y\), and \(z\). This confirms that \(x\), \(y\), and \(z\) are in Arithmetic Progression (A.P.).
1Step 1: Rewrite the given equation using logarithm properties
Since \(a^{\frac{1}{x}}=b^{\frac{1}{y}}=c^{\frac{1}{z}}\), we can take the natural logarithm (or any logarithm) on both sides of the equation:
\[\ln\left(a^{\frac{1}{x}}\right)=\ln\left(b^{\frac{1}{y}}\right)=\ln\left(c^{\frac{1}{z}}\right)\]
Now, using the logarithm property \(n\cdot\log{a}=\log(a^n)\), the equation becomes:
\[\frac{1}{x}\ln{a}=\frac{1}{y}\ln{b}=\frac{1}{z}\ln{c}\]
2Step 2: Write the condition for G.P.
Since \(a, b, c\) are in G.P., we can write \(b = a\cdot r\) and \(c = b\cdot r = a\cdot r^2\), where \(r\) is the common ratio.
3Step 3: Replace \(b\), \(c\) in the equation from Step 1
Substitute \(b = a\cdot r\) and \(c = a\cdot r^2\) in the equation from Step 1:
\[\frac{1}{x}\ln{a}=\frac{1}{y}\ln{(a\cdot r)}=\frac{1}{z}\ln{(a\cdot r^2)}\]
4Step 4: Simplify the equation
Using the logarithm property \(\log{A\cdot B} = \log{A} + \log{B}\), we can simplify the equation as:
\[\frac{1}{x}\ln{a}=\frac{1}{y}(\ln{a}+\ln{r})=\frac{1}{z}(2\ln{a}+2\ln{r})\]
5Step 5: Solve for the common difference of \(x, y, z\)
From the equation in Step 4, we can write the following system of equations:
\[\frac{1}{y}-\frac{1}{x}=\frac{\ln{r}}{\ln{a}}\]
and
\[\frac{1}{z}-\frac{1}{y}=\frac{2\ln{r}}{2\ln{a}}=\frac{\ln{r}}{\ln{a}}\]
Since these two equations are equal, the difference between consecutive terms is constant, and we conclude that \(x, y, z\) are in Arithmetic Progression (A.P.).
Key Concepts
Geometric ProgressionLogarithmic PropertiesCommon Ratio
Geometric Progression
A geometric progression (often abbreviated as G.P.) is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. For example, if you start with 2 and use a common ratio of 3, the sequence is 2, 6, 18, 54, and so forth.
In the context of the given exercise, understanding G.P. allowed us to express terms \(b\) and \(c\) in terms of \(a\) and the common ratio \(r\), which was crucial for proving that the exponents \(x, y, z\) form an arithmetic progression.
- Geometric progression is characterized by the property that the ratio of any term to the previous one is constant.
- The general form of a geometric progression can be written as: \[ a, a \cdot r, a \cdot r^2, a \cdot r^3, \ldots \]
- The common ratio \( r \) is found by dividing any term by the previous term.
In the context of the given exercise, understanding G.P. allowed us to express terms \(b\) and \(c\) in terms of \(a\) and the common ratio \(r\), which was crucial for proving that the exponents \(x, y, z\) form an arithmetic progression.
Logarithmic Properties
Logarithms are very useful when dealing with exponential equations, particularly when you need to simplify or solve them. In the context of the given problem, several logarithm properties are crucial. First, consider the property that allows you to break down a logarithm of a power:
Logarithmic properties turn complex multiplicative relations into simpler additive ones, instrumental in proving the end result of the exercise.
- \( n \cdot \log{a} = \log(a^n) \) - This is useful when you have exponential terms.
- Another useful property is \( \log(A \cdot B) = \log{A} + \log{B} \), which lets you separate products into sums when working with logs.
Logarithmic properties turn complex multiplicative relations into simpler additive ones, instrumental in proving the end result of the exercise.
Common Ratio
The common ratio is a fundamental component of a geometric progression. It is the fixed number by which each term in the sequence is multiplied to get the next term. In equations involving progressions, identifying and working with the common ratio simplifies the problem.
- For a sequence \(a, b, c\) in G.P., the term \(b\) is given by \(b = a \cdot r\), and \(c = b \cdot r = a \cdot r^2\).
- The common ratio \(r\) is crucial to express terms related to each other, allowing us to replace variables in the equations or set equal the exponents.
Other exercises in this chapter
Problem 123
Find all the numbers \(x\) and \(y\) and such that \(x, x+2 y, 2 x+y\) from an A.P. while the numbers \((y+1)^{2}\), \(x y+5,(x+1)^{2}\) form a G.P. Write down
View solution Problem 124
If \(a, b, c, x\) are all real numbers, and \(\left(a^{2}+b^{2}\right) x^{2}-2 b(a+c) x+\left(b^{2}+c^{2}\right)=0\) then show that \(a, b, c\) are in G.P., and
View solution Problem 126
If \(a, b, c\) be in G.P. then prove that \(\log a^{n}, \log b^{n}, \log c^{n}\) are in A.P.
View solution Problem 127
If the \(m\) th, \(n\) th, and \(p\) th terms of an A.P. and G.P. be equal and be respectively \(x, y\) and \(z\), then prove that \(x^{y-z} \cdot y^{z-x} \cdot
View solution