Chapter 9

Mathematics for IIT JEE Main and Advanced Differential Calculus Algebra Trigonometry · 307 exercises

Problem 211

If \(a, b, c\) are in A.P., prove that \(\frac{b c}{c a+a b}, \frac{c a}{b c+a b}, \frac{a b}{b c+c a}\) are in H.P.

5 step solution

Problem 212

First three of the four numbers are in A.P. \& the last three in H.P. Prove that the four numbers are proportional.

6 step solution

Problem 213

If \(a, b, c\) be in A.P. \(b, c, a\) be in H.P. then prove that \(c, a, b\) are in G.P.

3 step solution

Problem 214

If \(x, y, z\) are in A.P., \(a x, b y, c z\) in G.P. and \(a, b, c\) in H.P. prove that \(\frac{x}{z}+\frac{z}{x}=\frac{a}{c}+\frac{c}{a}\).

4 step solution

Problem 215

If \(a^{x}=b^{y}=c^{z}\) and \(a, b, c\) be in G.P. then prove that \(x, y, z\) are in H.P.

8 step solution

Problem 216

If \(a, b, c\) be in G.P. then prove that \(\log _{a} n, \log _{b} n, \log _{c} n\) are in H.P.

3 step solution

Problem 217

Given \(a^{x}=b^{y}=c^{z}=d^{u}\) and \(a, b, c, d\) are in G.P., show that \(x, y, z, u\) are in H.P.

3 step solution

Problem 218

If \(a, b, c, d, e\) be five numbers such that \(a, b, c\) are in A.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in H.P., prove that \(a, c, e\) are in G.P. and \(e=\frac{(2 b-a)^{2}}{a}\). If \(a=2\) and \(e=18\), find all possible values of \(b, c\) and \(d\).

4 step solution

Problem 219

\(a, b, c\) are in H.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in A.P. show that \(e=\frac{a b^{2}}{(2 a-b)^{2}}\).

5 step solution

Problem 220

If \(\frac{a-x}{p x}=\frac{a-y}{q y}=\frac{a-z}{r z}\) and \(p, q, r\) be in A.P. then prove that \(x, y, z\) are in H.P.

4 step solution

Problem 221

If \(a, b, c\) are all positive and in H.P., then show that the roots of \(a x^{2}+2 b x+3 c\) are imaginary.

4 step solution

Problem 222

If \(a, b, c\) be in A.P. and \(a^{2}, b^{2}, c^{2}\) in H.P. then prove that either \(-\frac{a}{2}, b, c\) are in G.P. or \(a=b=c\).

9 step solution

Problem 223

\(p, q, r\) are three numbers in G.P. Prove that the first term of an A.P., whose \(p\) th, \(q\) th and \(r\) th terms are in H.P., is to the common difference as \((q+1): 1\).

2 step solution

Problem 224

A G.P. and a H.P. have the same \(p\) th, \(q\) th and \(r\) th terms as \(a, b, c\) respectively. Show that \(a(b-c) \log a+b(c-a) \log b+c(a-b) \log c=0 .\)

3 step solution

Problem 225

An A.P., a G.P and a H.P. have \(a\) and \(b\) for their first two terms. Show that their \((n+2)\) th terms will be in G.P. if \(\frac{b^{2 n+2}-a^{2 n+2}}{a b\left(b^{2 n}-a^{2 n}\right)}=\frac{n+1}{n}\).

4 step solution

Problem 226

An A.P. and a H.P., have the same first term, the same last term, and the same number of terms; prove that the product of the \(r\) th term from the beginning in one series and the \(r\) th term from the end in the other is independent of \(r\).

5 step solution

Problem 227

\(\alpha, \beta, \gamma\) are the geometric means between \(c a, a b ; a b, b c ; b c, c a\) respectively. Prove that if \(a, b, c\) are in A.P., then \(\alpha^{2}, \beta^{2}, \gamma^{2}\) are also in A.P., and \(\beta+\gamma, \gamma+\alpha, \alpha+\beta\) are in H.P.

3 step solution

Problem 228

If the \((m+1)^{\text {th }},(n+1)^{\text {sh }}\) and \((r+1)^{t h}\) terms of an A.P. are in G.P., \(m, n, r\) are in H.P. show that the ratio of the common difference to the first term in the A.P. is \(-\frac{2}{n}\).

10 step solution

Problem 229

If \(S_{1}, S_{2}, S_{3}\) denote the sums of \(n\) terms of three A.P.'s whose first terms are unity and common differences in H.P., prove that \(n=\frac{2 S_{3} S_{1}-S_{1} S_{2}-S_{2} S_{3}}{S_{1}-2 S_{2}+S_{3}}\).

5 step solution

Problem 230

If \(a, b, c\) are in A.P., \(\alpha, \beta, \gamma\) in H.P., \(a \alpha, b \beta, c \gamma\) in G.P., (with common ratio not equal to \(1 .)\), then prove that \(a: b: c=\frac{1}{\gamma}: \frac{1}{\beta}: \frac{1}{\alpha}\).

4 step solution

Problem 231

Insert six harmonic means between 3 and \(\frac{6}{23}\).

4 step solution

Problem 233

Let the harmonic mean and geometric mean of two positive numbers be in the ratio \(4: 5\), then find the ratio of the two numbers.

5 step solution

Problem 234

If A.M between two numbers is 5 and their GM is 4, then find their HM.

8 step solution

Problem 235

A.M and H.M. between two quantities are 27 and 12 respectively, find their G.M.

4 step solution

Problem 236

If \(x, 1, z\) are in AP and \(x, 2, z\) are in GP, then find the harmonic mean of \(x\) and \(z\).

4 step solution

Problem 237

If \(H\) be the HM between \(a\) and \(b\), then show that \(\frac{H}{a}+\frac{H}{b}=2\).

10 step solution

Problem 238

The harmonic mean of two numbers is 4 . Their A.M., \(A\), and G.M., \(G\), satisfy the relation \(2 A+G^{2}=27\). Find the two numbers.

3 step solution

Problem 239

The A.M. of two numbers exceeds their G.M. by 15 and H.M. by 27 , find the numbers

5 step solution

Problem 240

If the A.M. between two numbers exceeds their G.M. by 2 and the G.M. exceeds their H.M. by \(\frac{8}{5}\); find the numbers.

5 step solution

Problem 241

If the A.M., the G.M and the H.M. of first and last terms of the sequence \(25,26,27, \ldots, N-1, N\) are the term of this sequence, find the value of \(N\).

4 step solution

Problem 242

If 9 arithmetic and harmonic means be inserted between 2 and 3, prove that \(A+\frac{6}{H}=5\) where \(A\) is any of the A.M.'s and \(H\) the corresponding H.M.

4 step solution

Problem 243

If \(H\) be the harmonic mean between \(a\) and \(b\) then prove that \(\frac{1}{H-a}+\frac{1}{H-b}=\frac{1}{a}+\frac{1}{b}\).

4 step solution

Problem 244

If \(A, G, H\) be respectively the A.M., G.M. and H.M. between two given quantities \(a\) and \(b\), then prove that \(A, G, H\) are in G.P.

2 step solution

Problem 245

If \(A\) be the A.M. and \(H\) the H.M. between two numbers \(a\) and \(b\) then \(\frac{a-A}{a-H} \times \frac{b-A}{b-H}=\frac{A}{H}\).

3 step solution

Problem 246

If \(A_{1}, A_{2} ; G_{1}, G_{2}\); and \(H_{1}, H_{2}\) be two A.M.'s and G.M.'s and H.M.'s between two quantities then prove that \(\frac{G_{1} G_{2}}{H_{1} H_{2}}=\frac{A_{1}+A_{2}}{H_{1}+H_{2}}\)

2 step solution

Problem 247

If \(n\) harmonic means are inserted between 1 and \(r\) then show that \(\frac{1 \text { st mean }}{n \text { th mean }}=\frac{n+r}{n r+1}\).

3 step solution

Problem 248

If \(H_{1}, H_{2}, \ldots H_{n}\) be \(n\) harmonic means between \(a\) and \(b\) show that \(\frac{H_{1}+a}{H_{1}-a}+\frac{H_{n}+b}{H_{n}-b}=2 n\). If \(n\) be a root of the equation \(x^{2}(1-a b)-x\left(a^{2}+b^{2}\right)-(1+a b)=0\), prove that \(H_{1}-H_{n}=a b(a-b)\).

9 step solution

Problem 249

For what value of \(n, \frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}}\) is the harmonic mean of \(a\) and \(b ?\)

5 step solution

Problem 250

If \(a\) be A.M. of \(b\) and \(c, b\) the G.M. of \(c\) and \(a\), then prove that \(c\) is the \(\mathrm{H} . \mathrm{M}\). of \(a\) and \(b\).

3 step solution

Problem 251

If \(2(y-a)\) is the H.M. between \(y-x\) and \(y-z\), then show that \(x-a, y-a, z-a\) are in G.P.

4 step solution

Problem 252

If \(p\) be the first of \(n\) arithmetic means between two numbers and \(q\) be the first of \(n\) harmonic means

3 step solution

Problem 253

Sum the series \(1 \cdot 2^{2}+2 \cdot 3^{2}+3 \cdot 4^{2}+\cdots \cdots\) to \(n\) terms.

5 step solution

Problem 254

Sum the series \(1 \cdot 3^{2}+2 \cdot 5^{2}+3 \cdot 7^{2}+\cdots \cdots \cdot\) to 20 terms.

3 step solution

Problem 255

Sum the series \(1 \cdot 2 \cdot 3+2 \cdot 3 \cdot 4+3 \cdot 4 \cdot 5+\cdots \cdots \cdot\) to \(n\) terms.

4 step solution

Problem 256

Sum the series \(1 \cdot 2 \cdot 5+2 \cdot 3 \cdot 6+3 \cdot 4 \cdot 7+\cdots \cdots \cdot\) to \(n\) terms.

3 step solution

Problem 257

Sum the series \(1+(1+2)+(1+2+3)+(1+2+3+4)+\cdots \cdots \cdot\) to \(n\) terms.

6 step solution

Problem 258

Sum the series \(1^{2}+\left(1^{2}+2^{2}\right)+\left(1^{2}+2^{2}+3^{2}\right)+\cdots \cdots \cdot\) to \(n\) terms.

4 step solution

Problem 259

Sum the series \(\frac{1^{3}}{1}+\frac{1^{3}+2^{3}}{1+3}+\frac{1^{3}+2^{3}+3^{3}}{1+3+5}+\cdots \cdot .\) to 16 terms .

5 step solution

Problem 260

Find the sum of the series \(31^{3}+32^{3}+\cdots \cdots+50^{3}\).

5 step solution

Problem 261

Sum to \(n\) terms the series \(1^{2}-2^{2}+3^{2}-4^{2}+5^{2}-6^{2}+\).

7 step solution

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