Chapter 9
Mathematics for IIT JEE Main and Advanced Differential Calculus Algebra Trigonometry · 307 exercises
Problem 211
If \(a, b, c\) are in A.P., prove that \(\frac{b c}{c a+a b}, \frac{c a}{b c+a b}, \frac{a b}{b c+c a}\) are in H.P.
5 step solution
Problem 212
First three of the four numbers are in A.P. \& the last three in H.P. Prove that the four numbers are proportional.
6 step solution
Problem 213
If \(a, b, c\) be in A.P. \(b, c, a\) be in H.P. then prove that \(c, a, b\) are in G.P.
3 step solution
Problem 214
If \(x, y, z\) are in A.P., \(a x, b y, c z\) in G.P. and \(a, b, c\) in H.P. prove that \(\frac{x}{z}+\frac{z}{x}=\frac{a}{c}+\frac{c}{a}\).
4 step solution
Problem 215
If \(a^{x}=b^{y}=c^{z}\) and \(a, b, c\) be in G.P. then prove that \(x, y, z\) are in H.P.
8 step solution
Problem 216
If \(a, b, c\) be in G.P. then prove that \(\log _{a} n, \log _{b} n, \log _{c} n\) are in H.P.
3 step solution
Problem 217
Given \(a^{x}=b^{y}=c^{z}=d^{u}\) and \(a, b, c, d\) are in G.P., show that \(x, y, z, u\) are in H.P.
3 step solution
Problem 218
If \(a, b, c, d, e\) be five numbers such that \(a, b, c\) are in A.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in H.P., prove that \(a, c, e\) are in G.P. and \(e=\frac{(2 b-a)^{2}}{a}\). If \(a=2\) and \(e=18\), find all possible values of \(b, c\) and \(d\).
4 step solution
Problem 219
\(a, b, c\) are in H.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in A.P. show that \(e=\frac{a b^{2}}{(2 a-b)^{2}}\).
5 step solution
Problem 220
If \(\frac{a-x}{p x}=\frac{a-y}{q y}=\frac{a-z}{r z}\) and \(p, q, r\) be in A.P. then prove that \(x, y, z\) are in H.P.
4 step solution
Problem 221
If \(a, b, c\) are all positive and in H.P., then show that the roots of \(a x^{2}+2 b x+3 c\) are imaginary.
4 step solution
Problem 222
If \(a, b, c\) be in A.P. and \(a^{2}, b^{2}, c^{2}\) in H.P. then prove that either \(-\frac{a}{2}, b, c\) are in G.P. or \(a=b=c\).
9 step solution
Problem 223
\(p, q, r\) are three numbers in G.P. Prove that the first term of an A.P., whose \(p\) th, \(q\) th and \(r\) th terms are in H.P., is to the common difference as \((q+1): 1\).
2 step solution
Problem 224
A G.P. and a H.P. have the same \(p\) th, \(q\) th and \(r\) th terms as \(a, b, c\) respectively. Show that \(a(b-c) \log a+b(c-a) \log b+c(a-b) \log c=0 .\)
3 step solution
Problem 225
An A.P., a G.P and a H.P. have \(a\) and \(b\) for their first two terms. Show that their \((n+2)\) th terms will be in G.P. if \(\frac{b^{2 n+2}-a^{2 n+2}}{a b\left(b^{2 n}-a^{2 n}\right)}=\frac{n+1}{n}\).
4 step solution
Problem 226
An A.P. and a H.P., have the same first term, the same last term, and the same number of terms; prove that the product of the \(r\) th term from the beginning in one series and the \(r\) th term from the end in the other is independent of \(r\).
5 step solution
Problem 227
\(\alpha, \beta, \gamma\) are the geometric means between \(c a, a b ; a b, b c ; b c, c a\) respectively. Prove that if \(a, b, c\) are in A.P., then \(\alpha^{2}, \beta^{2}, \gamma^{2}\) are also in A.P., and \(\beta+\gamma, \gamma+\alpha, \alpha+\beta\) are in H.P.
3 step solution
Problem 228
If the \((m+1)^{\text {th }},(n+1)^{\text {sh }}\) and \((r+1)^{t h}\) terms of an A.P. are in G.P., \(m, n, r\) are in H.P. show that the ratio of the common difference to the first term in the A.P. is \(-\frac{2}{n}\).
10 step solution
Problem 229
If \(S_{1}, S_{2}, S_{3}\) denote the sums of \(n\) terms of three A.P.'s whose first terms are unity and common differences in H.P., prove that \(n=\frac{2 S_{3} S_{1}-S_{1} S_{2}-S_{2} S_{3}}{S_{1}-2 S_{2}+S_{3}}\).
5 step solution
Problem 230
If \(a, b, c\) are in A.P., \(\alpha, \beta, \gamma\) in H.P., \(a \alpha, b \beta, c \gamma\) in G.P., (with common ratio not equal to \(1 .)\), then prove that \(a: b: c=\frac{1}{\gamma}: \frac{1}{\beta}: \frac{1}{\alpha}\).
4 step solution
Problem 231
Insert six harmonic means between 3 and \(\frac{6}{23}\).
4 step solution
Problem 233
Let the harmonic mean and geometric mean of two positive numbers be in the ratio \(4: 5\), then find the ratio of the two numbers.
5 step solution
Problem 234
If A.M between two numbers is 5 and their GM is 4, then find their HM.
8 step solution
Problem 235
A.M and H.M. between two quantities are 27 and 12 respectively, find their G.M.
4 step solution
Problem 236
If \(x, 1, z\) are in AP and \(x, 2, z\) are in GP, then find the harmonic mean of \(x\) and \(z\).
4 step solution
Problem 237
If \(H\) be the HM between \(a\) and \(b\), then show that \(\frac{H}{a}+\frac{H}{b}=2\).
10 step solution
Problem 238
The harmonic mean of two numbers is 4 . Their A.M., \(A\), and G.M., \(G\), satisfy the relation \(2 A+G^{2}=27\). Find the two numbers.
3 step solution
Problem 239
The A.M. of two numbers exceeds their G.M. by 15 and H.M. by 27 , find the numbers
5 step solution
Problem 240
If the A.M. between two numbers exceeds their G.M. by 2 and the G.M. exceeds their H.M. by \(\frac{8}{5}\); find the numbers.
5 step solution
Problem 241
If the A.M., the G.M and the H.M. of first and last terms of the sequence \(25,26,27, \ldots, N-1, N\) are the term of this sequence, find the value of \(N\).
4 step solution
Problem 242
If 9 arithmetic and harmonic means be inserted between 2 and 3, prove that \(A+\frac{6}{H}=5\) where \(A\) is any of the A.M.'s and \(H\) the corresponding H.M.
4 step solution
Problem 243
If \(H\) be the harmonic mean between \(a\) and \(b\) then prove that \(\frac{1}{H-a}+\frac{1}{H-b}=\frac{1}{a}+\frac{1}{b}\).
4 step solution
Problem 244
If \(A, G, H\) be respectively the A.M., G.M. and H.M. between two given quantities \(a\) and \(b\), then prove that \(A, G, H\) are in G.P.
2 step solution
Problem 245
If \(A\) be the A.M. and \(H\) the H.M. between two numbers \(a\) and \(b\) then \(\frac{a-A}{a-H} \times \frac{b-A}{b-H}=\frac{A}{H}\).
3 step solution
Problem 246
If \(A_{1}, A_{2} ; G_{1}, G_{2}\); and \(H_{1}, H_{2}\) be two A.M.'s and G.M.'s and H.M.'s between two quantities then prove that \(\frac{G_{1} G_{2}}{H_{1} H_{2}}=\frac{A_{1}+A_{2}}{H_{1}+H_{2}}\)
2 step solution
Problem 247
If \(n\) harmonic means are inserted between 1 and \(r\) then show that \(\frac{1 \text { st mean }}{n \text { th mean }}=\frac{n+r}{n r+1}\).
3 step solution
Problem 248
If \(H_{1}, H_{2}, \ldots H_{n}\) be \(n\) harmonic means between \(a\) and \(b\) show that \(\frac{H_{1}+a}{H_{1}-a}+\frac{H_{n}+b}{H_{n}-b}=2 n\). If \(n\) be a root of the equation \(x^{2}(1-a b)-x\left(a^{2}+b^{2}\right)-(1+a b)=0\), prove that \(H_{1}-H_{n}=a b(a-b)\).
9 step solution
Problem 249
For what value of \(n, \frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}}\) is the harmonic mean of \(a\) and \(b ?\)
5 step solution
Problem 250
If \(a\) be A.M. of \(b\) and \(c, b\) the G.M. of \(c\) and \(a\), then prove that \(c\) is the \(\mathrm{H} . \mathrm{M}\). of \(a\) and \(b\).
3 step solution
Problem 251
If \(2(y-a)\) is the H.M. between \(y-x\) and \(y-z\), then show that \(x-a, y-a, z-a\) are in G.P.
4 step solution
Problem 252
If \(p\) be the first of \(n\) arithmetic means between two numbers and \(q\) be the first of \(n\) harmonic means
3 step solution
Problem 253
Sum the series \(1 \cdot 2^{2}+2 \cdot 3^{2}+3 \cdot 4^{2}+\cdots \cdots\) to \(n\) terms.
5 step solution
Problem 254
Sum the series \(1 \cdot 3^{2}+2 \cdot 5^{2}+3 \cdot 7^{2}+\cdots \cdots \cdot\) to 20 terms.
3 step solution
Problem 255
Sum the series \(1 \cdot 2 \cdot 3+2 \cdot 3 \cdot 4+3 \cdot 4 \cdot 5+\cdots \cdots \cdot\) to \(n\) terms.
4 step solution
Problem 256
Sum the series \(1 \cdot 2 \cdot 5+2 \cdot 3 \cdot 6+3 \cdot 4 \cdot 7+\cdots \cdots \cdot\) to \(n\) terms.
3 step solution
Problem 257
Sum the series \(1+(1+2)+(1+2+3)+(1+2+3+4)+\cdots \cdots \cdot\) to \(n\) terms.
6 step solution
Problem 258
Sum the series \(1^{2}+\left(1^{2}+2^{2}\right)+\left(1^{2}+2^{2}+3^{2}\right)+\cdots \cdots \cdot\) to \(n\) terms.
4 step solution
Problem 259
Sum the series \(\frac{1^{3}}{1}+\frac{1^{3}+2^{3}}{1+3}+\frac{1^{3}+2^{3}+3^{3}}{1+3+5}+\cdots \cdot .\) to 16 terms .
5 step solution
Problem 260
Find the sum of the series \(31^{3}+32^{3}+\cdots \cdots+50^{3}\).
5 step solution
Problem 261
Sum to \(n\) terms the series \(1^{2}-2^{2}+3^{2}-4^{2}+5^{2}-6^{2}+\).
7 step solution