Chapter 13

Algebra and Trigonometry · 330 exercises

Problem 29

\(25-32\) . Find the \(n\) th term of a sequence whose first several terms are given. $$ 1, \frac{3}{4}, \frac{5}{9}, \frac{7}{16}, \frac{9}{25}, \dots $$

4 step solution

Problem 29

Find the first three terms in the expansion of \((x+2 y)^{20}\)

5 step solution

Problem 29

\(F_{n}\) denotes \(n t h\) term of the Fibonacci sequence discussed in Section \(13.1 .\) Use mathematical induction to prove the statement. \(F_{3 n}\) is even for all natural numbers \(n\)

5 step solution

Problem 30

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ 11,8,5,2, \dots $$

4 step solution

Problem 30

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 1, \sqrt{2}, 2,2 \sqrt{2}, \ldots $$

3 step solution

Problem 30

\(25-32\) . Find the \(n\) th term of a sequence whose first several terms are given. $$ \frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}, \dots $$

4 step solution

Problem 30

Find the first four terms in the expansion of \(\left(x^{1 / 2}+1\right)^{30}\)

7 step solution

Problem 30

An Annuity That Lasts Forever An annuity in perpetuity is one that continues forever. Such annuities are useful in setting up scholarship funds to ensure that the award continues. (a) Draw a time line (as in Example 1\()\) to show that to set up an annuity in perpetuity of amount \(R\) per time period, the amount that must be invested now is \(A_{p}=\frac{R}{1+i}+\frac{R}{(1+i)^{2}}+\frac{R}{(1+i)^{3}}+\cdots+\frac{R}{(1+i)^{n}}+\cdots\) where \(j\) is the interest rate per time period. (b) Find the sum of the infinite series in part (a) to show that $$ A_{p}=\frac{R}{i} $$ (c) How much money must be invested now at 10\(\%\) per year, compounded annually, to provide an annuity in perpetuity of \(\$ 5000\) per year? The first payment is due in one year. (d) How much money must be invested now at 8\(\%\) per year, compounded quarterly, to provide an annuity in perpetuity of \(\$ 3000\) per year? The first payment is due in one year.

5 step solution

Problem 31

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ -12,-8,-4,0, \dots $$

4 step solution

Problem 31

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 144,-12,1,-\frac{1}{12}, \dots $$

3 step solution

Problem 31

\(25-32\) . Find the \(n\) th term of a sequence whose first several terms are given. $$ 0,2,0,2,0,2, \dots $$

4 step solution

Problem 31

Find the last two terms in the expansion of \(\left(a^{2 / 3}+a^{1 / 3}\right)^{25}\)

6 step solution

Problem 31

\(F_{n}\) denotes \(n t h\) term of the Fibonacci sequence discussed in Section \(13.1 .\) Use mathematical induction to prove the statement. $$ F_{1}^{2}+F_{2}^{2}+F_{3}^{2}+\cdots+F_{n}^{2}=F_{n} F_{n+1} $$

5 step solution

Problem 31

Amortizing a Mortgage When they bought their house, John and Mary took out a \(\$ 90,000\) mortgage at 9\(\%\) interest, repayable monthly over 30 years. Their payment is \(\$ 724.17\) per month (check this, using the formula in the text). The bank gave them an amortization schedule, which is a table showing how much of each payment is interest, how much goes toward the principal, and the remaining principal after each payment. The table below shows the first few entries in the amortization schedule. After 10 years they have made 120 payments and are wondering how much they still owe, but they have lost the amortization schedule. (a) How much do John and Mary still owe on their mortgage? [Hint: The remaining balance is the present value of the 240 remaining payments. (b) How much of their next payment is interest, and how much goes toward the principal? IHint: Since \(9 \% \div 12=0.75 \%\) , they must pay 0.75\(\%\) of the remaining principal in interest each month.

5 step solution

Problem 32

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ \frac{7}{6}, \frac{5}{3}, \frac{13}{6}, \frac{8}{3}, \dots $$

5 step solution

Problem 32

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ -8,-2,-\frac{1}{2},-\frac{1}{8}, \ldots $$

3 step solution

Problem 32

\(25-32\) . Find the \(n\) th term of a sequence whose first several terms are given. $$ 1, \frac{1}{2}, 3, \frac{1}{4}, 5, \frac{1}{6}, \dots $$

4 step solution

Problem 32

Find the first three terms in the expansion of $$ \left(x+\frac{1}{x}\right)^{40} $$

6 step solution

Problem 32

\(F_{n}\) denotes \(n t h\) term of the Fibonacci sequence discussed in Section \(13.1 .\) Use mathematical induction to prove the statement. $$ F_{1}+F_{3}+\cdots+F_{2 n-1}=F_{2 n} $$

6 step solution

Problem 33

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ 25,26.5,28,29.5, \dots $$

5 step solution

Problem 33

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 3,3^{5 / 3}, 3^{7 / 3}, 27, \dots $$

4 step solution

Problem 33

\(33-36\) . Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$ 1,3,5,7, \ldots $$

8 step solution

Problem 33

Find the middle term in the expansion of \(\left(x^{2}+1\right)^{18}\)

4 step solution

Problem 34

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ 15,12.3,9.6,6.9, \ldots $$

4 step solution

Problem 34

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ t, \frac{t^{2}}{2}, \frac{t^{3}}{4}, \frac{t^{4}}{8}, \dots $$

4 step solution

Problem 34

\(33-36\) . Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$ 1^{2}, 2^{2}, 3^{2}, 4^{2}, \ldots $$

8 step solution

Problem 34

Find the fifth term in the expansion of \((a b-1)^{20}\)

6 step solution

Problem 35

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ 2,2+s, 2+2 s, 2+3 s, \dots $$

5 step solution

Problem 35

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 1, s^{2 / 7}, s^{4 / 7}, s^{6 / 7}, \dots $$

4 step solution

Problem 35

\(33-36\) . Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$ \frac{1}{3}, \frac{1}{3^{2}}, \frac{1}{3^{3}}, \frac{1}{3^{4}}, \dots $$

8 step solution

Problem 35

Find the 24 th term in the expansion of \((a+b)^{25}\)

5 step solution

Problem 36

\(27-36\) . Determine the common difference, the fifth term, the nth term, and the 100 th term of the arithmetic sequence. $$ -t,-t+3,-t+6,-t+9, \ldots $$

4 step solution

Problem 36

Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 5,5^{c+1}, 5^{2 c+1}, 5^{3 c+1}, \ldots $$

4 step solution

Problem 36

\(33-36\) . Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$ -1,1,-1,1, \dots $$

8 step solution

Problem 36

Find the 28 th term in the expansion of \((A-B)^{30}\)

6 step solution

Problem 36

Find and prove an inequality relating 100\(n\) and \(n^{3}\) .

7 step solution

Problem 37

The tenth term of an arithmetic sequence is \(\frac{55}{2},\) and the second term is \(\frac{7}{2}\). Find the first term.

5 step solution

Problem 37

The first term of a geometric sequence is \(8,\) and the second term is 4. Find the fifth term.

5 step solution

Problem 37

\(37-40\) . Find the first four partial sums and the nth partial sum of the sequence \(a_{m}\) $$ a_{n}=\frac{2}{3^{n}} $$

6 step solution

Problem 37

Find the 100 th term in the expansion of \((1+y)^{100}\)

5 step solution

Problem 37

True or False? Determine whether each statement is true or false. If you think the statement is true, prove it. If you think it is false, give an example in which it fails. (a) \(p(n)=n^{2}-n+11\) is prime for all \(n .\) (b) \(n^{2}>n\) for all \(n \geq 2\) . (c) \(n^{2 n+1}+1\) is divisible by 3 for all \(n \geq 1\) (d) \(n^{3} \geq(n+1)^{2}\) for all \(n \geq 2\) . (e) \(n^{3}-n\) is divisible by 3 for all \(n \geq 2\) (f) \(n^{3}-6 n^{2}+11 n\) is divisible by 6 for all \(n \geq 1\)

6 step solution

Problem 38

The 12 th term of an arithmetic sequence is \(32,\) and the fifh term is 18 . Find the 20 \(\mathrm{th}\) term.

5 step solution

Problem 38

The first term of a geometric sequence is \(3,\) and the third term is \(\frac{4}{3} .\) Find the fifth term.

5 step solution

Problem 38

\(37-40\) . Find the first four partial sums and the nth partial sum of the sequence \(a_{m}\) $$ a_{n}=\frac{1}{n+1}-\frac{1}{n+2} $$

6 step solution

Problem 38

All Cats Are Black? What is wrong with the following "proof" by mathematical induction that all cats are black? Let \(P(n)\) denote the statement "In any group of \(n\) cats, if one cat is black, then they are all black." Step 1 The statement is clearly true for \(n=1\) Step 2 Suppose that \(P(k)\) is true. We show that \(P(k+1)\) is true. Suppose we have a group of \(k+1\) cats, one of whom is black; call this cat "Tadpole." Remove some other cat (call it "Sparky") from the group. We are left with \(k\) call it Sparky" (Tadpole) is black, so by the induction hypothesis, all \(k\) of these are black. Now put Sparky back in the group and take out Tadpole. We again have a group of \(k\) cats, all of whom-except possibly Sparky - are black. Then by the induction hypothesis, Sparky must be black too. So all \(k+1\) cats in the original group are black. Thus by induction \(P(n)\) is true for all \(n .\) since everyone has seen at least one black cat, it follows that all cats are black.

4 step solution

Problem 38

Find the second term in the expansion of $$ \left(x^{2}-\frac{1}{x}\right)^{25} $$

5 step solution

Problem 39

The 100 th term of an arithmetic sequence is \(98,\) and the comon difference is \(2 .\) Find the first three terms.

5 step solution

Problem 39

The common ratio in a geometric sequence is \(\frac{2}{5},\) and the fourth term is \(\frac{5}{2} .\) Find the third term.

6 step solution

Problem 39

\(37-40\) . Find the first four partial sums and the nth partial sum of the sequence \(a_{m}\) $$ a_{n}=\sqrt{n}-\sqrt{n+1} $$

5 step solution

Problem 39

Find the term containing \(x^{4}\) in the expansion of \((x+2 y)^{10}\)

7 step solution

Show/ page