Problem 30
Question
Find the first four terms in the expansion of \(\left(x^{1 / 2}+1\right)^{30}\)
Step-by-Step Solution
Verified Answer
The first four terms are: \(x^{15} + 30x^{14.5} + 435x^{14} + 4060x^{13.5}\).
1Step 1: Understand the Binomial Theorem
The binomial theorem allows us to expand expressions of the form \((a+b)^n\). It states that the expansion of \((a+b)^n\) is given by the sum: \(\sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). Here, \(\binom{n}{k}\) represents the binomial coefficient, which can be calculated as \(\binom{n}{k} = \frac{n!}{k! (n-k)!}\).
2Step 2: Identify Variables in the Expression
For the expression \((x^{1/2}+1)^{30}\), we have the variables:- \(a = x^{1/2}\)- \(b = 1\)- \(n = 30\)
3Step 3: Calculate the First Term
Using the binomial theorem formula, the first term is obtained with \(k=0\):\[ T_0 = \binom{30}{0} (x^{1/2})^{30-0} 1^0 = 1 \times x^{15} = x^{15} \]
4Step 4: Calculate the Second Term
For the second term, we use \(k=1\):\[ T_1 = \binom{30}{1} (x^{1/2})^{30-1} 1^1 = 30 \times x^{14.5} = 30 x^{14.5} \]
5Step 5: Calculate the Third Term
For the third term, use \(k=2\):\[ T_2 = \binom{30}{2} (x^{1/2})^{30-2} 1^2 = \frac{30 \times 29}{2} \times x^{14} = 435 x^{14} \]
6Step 6: Calculate the Fourth Term
For the fourth term, use \(k=3\):\[ T_3 = \binom{30}{3} (x^{1/2})^{30-3} 1^3 = \frac{30 \times 29 \times 28}{6} \times x^{13.5} = 4060 x^{13.5} \]
7Step 7: Combine the First Four Terms
Combine all terms calculated: \(T_0 + T_1 + T_2 + T_3 = x^{15} + 30 x^{14.5} + 435 x^{14} + 4060 x^{13.5}\).
Key Concepts
Binomial ExpansionBinomial CoefficientPolynomial Expressions
Binomial Expansion
The binomial expansion is a powerful technique used in algebra to expand expressions of the form \((a+b)^n\). This method allows us to express a power of a binomial as a sum of terms involving binomial coefficients and the variables raised to varying powers. For example, in the expression \((x^{1/2} + 1)^{30}\), the binomial expansion enables us to systematically determine each term in the expansion according to the formula defined by the binomial theorem. In general, the expansion takes the shape of:
- \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\)
- Where \(\binom{n}{k}\) is the binomial coefficient, calculated as \(\frac{n!}{k! (n-k)!}\)
Binomial Coefficient
A binomial coefficient is a crucial component of binomial expansion, representing the number of ways to choose \(k\) elements from a set of \(n\) elements without regard to the order of selection. The notation \(\binom{n}{k}\) indicates a binomial coefficient, which can be computed using the formula:
- \(\binom{n}{k} = \frac{n!}{k! (n-k)!}\)
Polynomial Expressions
A polynomial expression is an algebraic expression consisting of variables and coefficients, involving only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. In the context of the binomial theorem, polynomial expressions emerge when expanding binomials. The resulting terms follow a structured pattern:
- Variable components have gradually decreasing powers for one variable and increasing powers for the other.
- The coefficients come from binomial coefficients, indicating each term's weight or significance.
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