Problem 35
Question
Determine the common ratio, the fifth term, and the nth term of the geometric sequence. $$ 1, s^{2 / 7}, s^{4 / 7}, s^{6 / 7}, \dots $$
Step-by-Step Solution
Verified Answer
Common ratio: \(s^{2/7}\), Fifth term: \(s^{8/7}\), nth term: \(s^{2(n-1)/7}\).
1Step 1: Identify the Geometric Sequence Elements
The given sequence is \(1, s^{2/7}, s^{4/7}, s^{6/7}, \ldots\). We are to determine the common ratio, the fifth term, and the general nth term of the sequence.
2Step 2: Calculate the Common Ratio
A geometric sequence has the form \(a, ar, ar^2, ar^3, \ldots\), where \(a\) is the first term and \(r\) is the common ratio. Here, the first term \(a = 1\). The second term is \(s^{2/7}\). The common ratio \(r\) can be found using the formula: \[ r = \frac{s^{2/7}}{1} = s^{2/7} \]. Hence, the common ratio \(r = s^{2/7}\).
3Step 3: Find the Fifth Term using the Common Ratio
To find the fifth term, we use the formula for the nth term of a geometric sequence: \[ a_n = ar^{n-1} \]. For the fifth term \(a_5\), it is \(a \times r^4\). So: \[ a_5 = 1 \times (s^{2/7})^4 = s^{8/7} \]. Therefore, the fifth term is \(s^{8/7}\).
4Step 4: Determine the General nth Term
The general formula for the nth term of a geometric sequence is \(a_n = ar^{n-1}\). Here, \(a = 1\) and \(r = s^{2/7}\). Substituting these in gives: \[ a_n = 1 \times (s^{2/7})^{n-1} = s^{2(n-1)/7} \]. This is the formula for the nth term of the sequence.
Key Concepts
Common Rationth Term FormulaSequences and Series
Common Ratio
In a geometric sequence, the common ratio is a key feature that determines the pattern of the sequence. It is the factor by which each term in the sequence is multiplied to get the next term. Identifying the common ratio allows you to predict future terms and analyze the sequence's behavior.
The formula to find the common ratio \( r \) in a geometric sequence is:
Thus, the common ratio \( r \) is:
The formula to find the common ratio \( r \) in a geometric sequence is:
- \( r = \frac{a_{n}}{a_{n-1}} \) where \( a_{n} \) is the current term and \( a_{n-1} \) is the previous term in the sequence.
Thus, the common ratio \( r \) is:
- \( r = \frac{s^{2/7}}{1} = s^{2/7} \)
nth Term Formula
To find any term in a geometric sequence, it's essential to understand the nth term formula. This formula provides a shortcut to calculate any term directly without having to determine each preceding term.
The general form of the nth term \( a_n \) in a geometric sequence is given by:
The general form of the nth term \( a_n \) in a geometric sequence is given by:
- \( a_n = ar^{n-1} \)
- \( a \) is the first term.
- \( r \) is the common ratio.
- \( n \) is the term number.
- \( a_n = 1 \times (s^{2/7})^{n-1} = s^{2(n-1)/7} \)
Sequences and Series
Sequences and series form the foundation of understanding patterns in mathematics. A sequence is a set of numbers arranged in a specific order following a specific rule. In contrast, a series is the sum of the terms of a sequence.
There are various types of sequences, with geometric sequences being one of them. In a geometric sequence, each term is derived by multiplying the previous term by a constant value known as the common ratio.
To summarize the essential points:
There are various types of sequences, with geometric sequences being one of them. In a geometric sequence, each term is derived by multiplying the previous term by a constant value known as the common ratio.
To summarize the essential points:
- A sequence is an ordered list of numbers.
- In a geometric sequence, the ratio between consecutive terms remains constant.
- While sequences deal with the arrangement of terms, series involve their summation.
- Understanding these concepts is crucial for solving complex mathematical problems and recognizing patterns in data.
Other exercises in this chapter
Problem 34
Find the fifth term in the expansion of \((a b-1)^{20}\)
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\(33-36\) . Find the first six partial sums \(S_{1}, S_{2}, S_{3}, S_{4}, S_{5}, S_{6}\) of the sequence. $$ \frac{1}{3}, \frac{1}{3^{2}}, \frac{1}{3^{3}}, \fra
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