Chapter 9

Algebra A Combined Function · 175 exercises

Problem 15

Solve each system. $$ \left\\{\begin{array}{r} x+y+z=8 \\ 2 x-y-z=10 \\ x-2 y-3 z=22 \end{array}\right. $$

7 step solution

Problem 15

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{array}{r} y+2 x \geq 0 \\ 5 x-3 y \leq 12 \\ y \leq 2 \end{array}\right. $$

6 step solution

Problem 15

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} x+y+z=2 \\ 2 x-z=5 \\ 3 y+z=2 \end{array}\right. $$

6 step solution

Problem 15

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=100\) when \(x=7\)

4 step solution

Problem 16

Solve each system. $$ \left\\{\begin{aligned} 5 x+y+3 z &=1 \\ x-y+3 z &=-7 \\ -x+y &=1 \end{aligned}\right. $$

9 step solution

Problem 16

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{array}{rr} y+2 x \leq & 0 \\ 5 x+3 y \geq & -2 \\ y \leq & 4 \end{array}\right. $$

4 step solution

Problem 16

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} x+2 y+z=5 \\ x-y-z=3 \\ y+z=2 \end{array}\right. $$

6 step solution

Problem 16

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=63\) when \(x=3\)

4 step solution

Problem 17

Solve each system. $$ \left\\{\begin{array}{r} x+2 y-z=5 \\ 6 x+y+z=7 \\ 2 x+4 y-2 z=5 \end{array}\right. $$

7 step solution

Problem 17

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{aligned} 3 x-4 y & \geq-6 \\ 2 x+y \leq & 7 \\ y \geq &-3 \end{aligned}\right. $$

4 step solution

Problem 17

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} 5 x-2 y=27 \\ -3 x+5 y=18 \end{array}\right. $$

4 step solution

Problem 17

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=\frac{1}{8}\) when \(x=16\)

3 step solution

Problem 18

Solve each system. $$ \left\\{\begin{array}{r} 4 x-y+3 z=10 \\ x+y-z=5 \\ 8 x-2 y+6 z=10 \end{array}\right. $$

5 step solution

Problem 18

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{aligned} 4 x-y & \geq-2 \\ 2 x+3 y & \leq-8 \\ y & \geq-5 \end{aligned}\right. $$

5 step solution

Problem 18

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=\frac{1}{10}\) when \(x=40\)

5 step solution

Problem 19

Solve each system. $$ \left\\{\begin{array}{r} 2 x-3 y+z=2 \\ x-5 y+5 z=3 \\ 3 x+y-3 z=5 \end{array}\right. $$

7 step solution

Problem 19

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{aligned} 2 x+y & \leq 5 \\ x & \leq 3 \\ x & \geq 0 \\ y & \geq 0 \end{aligned}\right. $$

5 step solution

Problem 19

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{aligned} 4 x-7 y &=7 \\ 12 x-21 y &=24 \end{aligned}\right. $$

3 step solution

Problem 19

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=0.2\) when \(x=0.7\)

5 step solution

Problem 20

Solve each system. $$ \left\\{\begin{array}{r} 4 x+y-z=8 \\ x-y+2 z=3 \\ 3 x-y+z=6 \end{array}\right. $$

8 step solution

Problem 20

Graph the solutions of each system of linear inequalities $$ \left\\{\begin{aligned} 3 x+y &=4 \\ x & \leq 4 \\ x & \geq 0 \\ y & \geq 0 \end{aligned}\right. $$

6 step solution

Problem 20

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} 2 x-5 y=12 \\ -4 x+10 y=20 \end{array}\right. $$

3 step solution

Problem 20

If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=0.6\) when \(x=0.3\)

4 step solution

Problem 21

Solve each system. $$ \left\\{\begin{array}{rr} -2 x-4 y+6 z= & -8 \\ x+2 y-3 z= & 4 \\ 4 x+8 y-12 z= & 16 \end{array}\right. $$

5 step solution

Problem 21

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{rr} 4 x-y+2 z= & 5 \\ 2 y+z= & 4 \\ 4 x+y+3 z= & 10 \end{array}\right. $$

3 step solution

Problem 21

Pairs of markings a set distance apart are made on highways so that police can detect drivers exceeding the speed limit. Over a fixed distance, the speed \(R\) varies inversely with the time \(T\). In one particular pair of markings, \(R\) is 45 mph when \(T\) is 6 seconds. Find the speed of a car that travels the given distance in 5 seconds.

4 step solution

Problem 22

Solve each system. $$ \left\\{\begin{aligned} -6 x+12 y+3 z &=-6 \\ 2 x-4 y-z &=2 \\ -x+2 y+\frac{z}{2} &=-1 \end{aligned}\right. $$

9 step solution

Problem 22

The weight of an object on or above the surface of Earth varies inversely as the square of the distance between the object and Earth's center. If a person weighs 160 pounds on Earth's surface, find the individual's weight if he moves 200 miles above Earth. Round to the nearest whole pound. (Assume that Earth's radius is 4000 miles.)

5 step solution

Problem 23

Solve each system. $$ \left\\{\begin{aligned} 2 x+2 y-3 z &=1 \\ y+2 z &=-14 \\ 3 x-2 y &=-1 \end{aligned}\right. $$

8 step solution

Problem 23

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{aligned} 4 x+y+z &=3 \\ -x+y-2 z &=-11 \\ x+2 y+2 z &=-1 \end{aligned}\right. $$

4 step solution

Problem 23

If the voltage \(V\) in an electric circuit is held constant, the current \(I\) is inversely proportional to the resistance \(R\). If the current is 40 amperes when the resistance is 270 ohms, find the current when the resistance is 150 ohms.

4 step solution

Problem 24

Solve each system. $$ \left\\{\begin{array}{rr} 7 x+4 y & =10 \\ x-4 y+2 z & =6 \\ y-2 z & =-1 \end{array}\right. $$

8 step solution

Problem 24

Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} x+y+z=9 \\ 3 x-y+z=-1 \\ -2 x+2 y-3 z=-2 \end{array}\right. $$

5 step solution

Problem 24

Because it is more efficient to produce larger numbers of items, the cost of producing a certain computer DVD is inversely proportional to the number produced. If 4000 can be produced at a cost of \(\$ 1.20\) each, find the cost per DVD when 6000 are produced.

5 step solution

Problem 25

Solve each system. $$ \left\\{\begin{array}{rr} x+2 y-z= & 5 \\ -3 x-2 y-3 z= & 11 \\ 4 x+4 y+5 z= & -18 \end{array}\right. $$

8 step solution

Problem 25

Evaluate each expression. $$ (-3)^{2} $$

3 step solution

Problem 25

The intensity \(I\) of light varies inversely as the square of the distance \(d\) from the light source. If the distance from the light source is doubled (see the figure), determine what happens to the intensity of light at the new location.

5 step solution

Problem 26

Evaluate each expression. $$ (-5)^{3} $$

3 step solution

Problem 26

Solve each system. $$ \left\\{\begin{aligned} 3 x-3 y+z &=-1 \\ 3 x-y-z &=3 \\ -6 x+4 y+3 z &=-8 \end{aligned}\right. $$

7 step solution

Problem 26

The maximum weight that a circular column can hold is inversely proportional to the square of its height. If an 8 -foot column can hold 2 tons, find how much weight a 10 -foot column can hold.

3 step solution

Problem 27

Evaluate each expression. $$ \left(\frac{2}{3}\right)^{2} $$

4 step solution

Problem 27

Solve each system. $$ \left\\{\begin{array}{l} \frac{3}{4} x-\frac{1}{3} y+\frac{1}{2} z=9 \\ \frac{1}{6} x+\frac{1}{3} y-\frac{1}{2} z=2 \\ \frac{1}{2} x-y+\frac{1}{2} z=2 \end{array}\right. $$

6 step solution

Problem 27

Write each statement as an equation. Use \(k\) as the constant of variation. \(x\) varies jointly as \(y\) and \(z\).

3 step solution

Problem 28

Evaluate each expression. $$ \left(\frac{3}{4}\right)^{3} $$

5 step solution

Problem 28

Solve each system. $$ \left\\{\begin{aligned} \frac{1}{3} x-\frac{1}{4} y+z &=-9 \\ \frac{1}{2} x-\frac{1}{3} y-\frac{1}{4} z &=-6 \\ x-\frac{1}{2} y-z &=-8 \end{aligned}\right. $$

5 step solution

Problem 28

Write each statement as an equation. Use \(k\) as the constant of variation. \(P\) varies jointly as \(R\) and the square of \(S\).

3 step solution

Problem 29

For Exercises 29 and 30 , the solutions have been started for you. The first few exercises are each modeled by a system of two linear equations in two variables. One number is two more than a second number. Twice the first is 4 less than 3 times the second. Find the numbers. 1\. UNDERSTAND the problem. Since we are looking for two numbers, let \(x=\) one number \(y=\) second number 2\. TRANSLATE. Since we have assigned two variables, we will translate the facts into two equations. (Fill in the blanks.) 3\. SOLVE the system and 4\. INTERPRET the results.

4 step solution

Problem 29

Perform each indicated operation. $$ \begin{aligned} &(-2)^{2}-(-3)+2(-1)\\\ &\text { 30. } 5^{2}-11+3(-5) \end{aligned} $$

4 step solution

Problem 29

Solve. See the Concept Check in this section. For the system \(\left\\{\begin{aligned} x \quad+z &=7 \\ y+2 z &=-6, \text { which is the correct corresponding matrix? } \\ 3 x-y \quad &=0 \end{aligned}\right.\) a. \(\left[\begin{array}{rrr}1 & 1 & 7 \\ 1 & 2 & -6 \\ 3 & -1 & 0\end{array}\right]\) b. \(\left[\begin{array}{rrrr}1 & 0 & 1 & 7 \\ 1 & 2 & 0 & -6 \\ 3 & -1 & 0 & 0\end{array}\right]\) C. \(\left[\begin{array}{rrrr}1 & 0 & 1 & 7 \\ 0 & 1 & 2 & -6 \\ 3 & -1 & 0 & 0\end{array}\right]\)

5 step solution

Problem 29

Write each statement as an equation. Use \(k\) as the constant of variation. \(r\) varies jointly as \(s\) and the cube of \(t\).

3 step solution

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