Problem 21
Question
Solve each system. $$ \left\\{\begin{array}{rr} -2 x-4 y+6 z= & -8 \\ x+2 y-3 z= & 4 \\ 4 x+8 y-12 z= & 16 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The system has infinitely many solutions: \( (x, y, z) = (4 - 2t + 3s, t, s) \).
1Step 1: Identify Dependencies
Observe the given system of equations:\[ \begin{align*} \text{1.} & -2x - 4y + 6z = -8 \ \text{2.} & x + 2y - 3z = 4 \ \text{3.} & 4x + 8y - 12z = 16 \end{align*} \] Notice that Equation 3 is simply twice Equation 2, which means they are linearly dependent. This reduces our system to two independent equations.
2Step 2: Solve for One Variable
From Equation 2: \( x + 2y - 3z = 4 \), we can solve for \( x \):\[ x = 4 - 2y + 3z \] Substitute this expression for \( x \) into Equation 1.
3Step 3: Substitute and Simplify
Substitute \( x = 4 - 2y + 3z \) into Equation 1: \[ -2(4 - 2y + 3z) - 4y + 6z = -8 \] Simplify this equation: \[ -8 + 4y - 6z - 4y + 6z = -8 \] Notice the terms cancel each other out: \[ -8 = -8 \] This confirms the equations are consistent and represent the same line.
4Step 4: Interpret the Solution
The solution implies that the equations are dependent (describe the same plane), therefore they have infinitely many solutions based on free parameters for \( y \) and \( z \). Pick \( y = t \) and \( z = s \) to represent the free variables and express \( x \) in terms of \( t \) and \( s \): \[ x = 4 - 2t + 3s \]
5Step 5: Formulate the Parametric Solution
Write the general solution in parametric form as:\[ \left( x, y, z \right) = \left( 4 - 2t + 3s, t, s \right) \] where \( t \) and \( s \) are parameters representing any real numbers.
Key Concepts
Linear DependenceParametric SolutionInfinitely Many Solutions
Linear Dependence
In a system of linear equations, some equations might be multiples of others. This means they are linearly dependent. Linear dependence occurs when one equation can be derived from another by multiplying by a constant.
It can reduce the system's complexity, as it essentially provides the same information repeatedly. In the provided exercise, you can see linear dependence between Equation 3 and Equation 2, since Equation 3 is just twice Equation 2:
It can reduce the system's complexity, as it essentially provides the same information repeatedly. In the provided exercise, you can see linear dependence between Equation 3 and Equation 2, since Equation 3 is just twice Equation 2:
- Equation 2: \( x + 2y - 3z = 4 \)
- Equation 3: \( 4x + 8y - 12z = 16 \)
Parametric Solution
Once linear dependence reduces our system, we need to solve it. Often, systems with more variables than independent equations require a parametric solution. Parametric solutions express variables in terms of any arbitrary parameters.
In our exercise, with two equations and three variables \((x, y, z)\), we can represent two variables as parameters. By solving \(x + 2y - 3z = 4\) for \(x\), we get:
In our exercise, with two equations and three variables \((x, y, z)\), we can represent two variables as parameters. By solving \(x + 2y - 3z = 4\) for \(x\), we get:
- \(x = 4 - 2y + 3z\)
- \((x, y, z) = (4 - 2t + 3s, t, s)\)
Infinitely Many Solutions
When solving linear systems, you might encounter a consistent solution that isn't unique but rather infinite. This indicates that the system has designed constraints, setting a scenario where infinitely many solutions exist. This occurs when relationships among equations describe a common geometric feature, generally as lines or planes in space.
In the given problem, after identifying linear dependence and using parametric solutions, the system manifests as infinitely many solutions. By expressing \(y = t\) and \(z = s\), with arbitrary \(t\) and \(s\), the problem shows that for every \((t, s)\) pair, an \((x, y, z)\) solution satisfies the system:
In the given problem, after identifying linear dependence and using parametric solutions, the system manifests as infinitely many solutions. By expressing \(y = t\) and \(z = s\), with arbitrary \(t\) and \(s\), the problem shows that for every \((t, s)\) pair, an \((x, y, z)\) solution satisfies the system:
- \((x, y, z) = (4 - 2t + 3s, t, s)\)
Other exercises in this chapter
Problem 20
Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{r} 2 x-5 y=12 \\ -4 x+10 y=20 \end{array}\right. $$
View solution Problem 20
If \(y\) varies inversely as \(x\), find the constant of variation and the inverse variation equation for each situation. \(y=0.6\) when \(x=0.3\)
View solution Problem 21
Solve each system of linear equations using matrices. See Examples 1 through 3. $$ \left\\{\begin{array}{rr} 4 x-y+2 z= & 5 \\ 2 y+z= & 4 \\ 4 x+y+3 z= & 10 \en
View solution Problem 21
Pairs of markings a set distance apart are made on highways so that police can detect drivers exceeding the speed limit. Over a fixed distance, the speed \(R\)
View solution