Chapter 7

A Graphical Approach to Precalculus with Limits · 546 exercises

Problem 9

For each element in the second row of the given matrix, find its cofactor (See Example 3 .) $$\left[\begin{array}{rrr}-2 & 0 & 1 \\\1 & 2 & 0 \\\4 & 2 & 1\end{array}\right]$$

4 step solution

Problem 9

Find the partial fraction decomposition for each rational expression. $$\frac{4 x+2}{(x+2)(2 x-1)}$$

7 step solution

Problem 9

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{ll} 3 & 7 \\ 2 & 5 \end{array}\right]$$

4 step solution

Problem 9

Write the augmented matrix for each system. Do not solve the system. $$\begin{array}{r} x+5 y=6 \\ x=3 \end{array}$$

4 step solution

Problem 9

Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ll}w & x \\ y & z\end{array}\right]=\left[\begin{array}{rr}3 & 2 \\ -1 & 4\end{array}\right]$$

3 step solution

Problem 9

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} &x+2 y+z=4\\\ &x+y=0\\\ &x-y=-2 \end{aligned}$$

7 step solution

Problem 9

Solve each system by substitution. $$\begin{aligned}&y=2 x+3\\\&3 x+4 y=78\end{aligned}$$

6 step solution

Problem 10

Graph each inequality. $$2 x-y>-1$$

3 step solution

Problem 10

For each element in the second row of the given matrix, find its cofactor (See Example 3 .) $$\left[\begin{array}{rrr}1 & -1 & 2 \\\1 & 0 & 2 \\\0 & -3 & 1\end{array}\right]$$

4 step solution

Problem 10

Find the partial fraction decomposition for each rational expression. $$\frac{x+2}{(x+1)(x-1)}$$

7 step solution

Problem 10

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{ll} -5 & 3 \\ -8 & 5 \end{array}\right]$$

4 step solution

Problem 10

Write the augmented matrix for each system. Do not solve the system. $$\begin{aligned} 2 x+7 y &=1 \\ 5 x &=-15 \end{aligned}$$

3 step solution

Problem 10

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} x-y-z &=6 \\ x+2 y &=1 \\ 2 x-y &=12 \end{aligned}$$

7 step solution

Problem 10

Solve each system by substitution. $$\begin{aligned}&y=4 x-6\\\&2 x+5 y=-8\end{aligned}$$

5 step solution

Problem 11

Graph each inequality. $$x+2 y \leq 6$$

5 step solution

Problem 11

For each element in the second row of the given matrix, find its cofactor (See Example 3 .) $$\left[\begin{array}{rrr}1 & 2 & -1 \\\2 & 3 & -2 \\\\-1 & 4 & 1\end{array}\right]$$

5 step solution

Problem 11

Find the partial fraction decomposition for each rational expression. $$\frac{x}{x^{2}+4 x-5}$$

7 step solution

Problem 11

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{rr} -1 & -2 \\ 3 & 4 \end{array}\right]$$

4 step solution

Problem 11

Write the augmented matrix for each system. Do not solve the system. $$\begin{aligned} 2 x+y+z &=3 \\ 3 x-4 y+2 z &=-7 \\ x+y+z &=2 \end{aligned}$$

3 step solution

Problem 11

Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ccc}0 & 5 & x \\ -1 & 3 & y+2 \\ 4 & 1 & z\end{array}\right]=\left[\begin{array}{rrr}0 & w+3 & 6 \\ -1 & 3 & 0 \\ 4 & 1 & 8\end{array}\right]$$

3 step solution

Problem 11

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} x-y+z &=1 \\ -x+y-z &=0 \\ -x-y+z &=-2 \end{aligned}$$

5 step solution

Problem 11

Solve each system by substitution. $$\begin{aligned}&3 x-2 y=12\\\&5 x=4-2 y\end{aligned}$$

6 step solution

Problem 12

Graph each inequality. $$x-y \geq 2$$

5 step solution

Problem 12

For each element in the second row of the given matrix, find its cofactor (See Example 3 .) $$\left[\begin{array}{rrr}2 & -1 & 4 \\\3 & 0 & 1 \\\\-2 & 1 & 4\end{array}\right]$$

7 step solution

Problem 12

Find the partial fraction decomposition for each rational expression. $$\frac{5 x-3}{(x+1)(x-3)}$$

7 step solution

Problem 12

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{rr} -1 & 2 \\ -2 & -1 \end{array}\right]$$

4 step solution

Problem 12

Write the augmented matrix for each system. Do not solve the system. $$\begin{aligned} &4 x-2 y+3 z=4\\\ &3 x+5 y+z=7\\\ &5 x-y+4 z=7 \end{aligned}$$

4 step solution

Problem 12

Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ccc}3+x & 4 & t \\ 5 & 8-w & y+1 \\ -4 & 3 & 2 r\end{array}\right]=\left[\begin{array}{ccc}9 & 4 & 6 \\ z+3 & w & 9 \\ p & q & r\end{array}\right]$$

9 step solution

Problem 12

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{array}{c} x-y-z=6 \\ x+2 y+2 z=3 \\ 2 x+y+z=9 \end{array}$$

6 step solution

Problem 12

Solve each system by substitution. $$\begin{aligned}&8 x+3 y=2\\\&5 x=17+6 y\end{aligned}$$

6 step solution

Problem 13

Find each determinant. $$\operatorname{det}\left[\begin{array}{rrr}4 & -7 & 8 \\\2 & 1 & 3 \\\\-6 & 3 & 0\end{array}\right]$$

8 step solution

Problem 13

Graph each inequality. $$2 x+3 y \geq 4$$

4 step solution

Problem 13

Find the partial fraction decomposition for each rational expression. $$\frac{2 x}{(x+1)(x+2)^{2}}$$

8 step solution

Problem 13

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{ll} -6 & 4 \\ -3 & 2 \end{array}\right]$$

2 step solution

Problem 13

Write the augmented matrix for each system. Do not solve the system. $$\begin{aligned} x+y &=2 \\ 2 y+z &=-4 \\ z &=2 \end{aligned}$$

4 step solution

Problem 13

Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ccc}z & 4 r & 8 s \\ 6 p & 2 & 5\end{array}\right]+\left[\begin{array}{ccc}-9 & 8 r & 3 \\ 2 & 5 & 4\end{array}\right]=\left[\begin{array}{ccc}2 & 36 & 27 \\ 20 & 7 & 12 a\end{array}\right]$$

3 step solution

Problem 13

Solve each system by substitution. $$\begin{aligned}&4 x-5 y=-11\\\&2 x+y=5\end{aligned}$$

5 step solution

Problem 14

Find each determinant. $$\operatorname{det}\left[\begin{array}{rrr}8 & -2 & -4 \\\7 & 0 & 3 \\\5 & -1 & 2\end{array}\right]$$

6 step solution

Problem 14

Graph each inequality. $$4 y-3 x<5$$

5 step solution

Problem 14

Find the partial fraction decomposition for each rational expression. $$\frac{2}{x^{2}(x+3)}$$

7 step solution

Problem 14

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{rr} 5 & 10 \\ -3 & -6 \end{array}\right]$$

2 step solution

Problem 14

Write the augmented matrix for each system. Do not solve the system. $$\begin{aligned} x &=6 \\ y+2 z &=2 \\ x-3 z &=6 \end{aligned}$$

3 step solution

Problem 14

Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ccc}a+2 & 1 & 5 m \\ 8 k & 0 & 3\end{array}\right]+\left[\begin{array}{ccc}3 a & 2 z & 5 m \\ 2 k & 5 & 6\end{array}\right]=\left[\begin{array}{ccc}10 & -14 & 80 \\ 10 & 5 & 9\end{array}\right]$$

7 step solution

Problem 14

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{array}{l} 2 x+y+z=9 \\ -x-y+z=1 \\ 3 x-y+z=9 \end{array}$$

7 step solution

Problem 14

Solve each system by substitution. $$\begin{aligned}&7 x-y=-10\\\&3 y-x=10\end{aligned}$$

6 step solution

Problem 15

Find the partial fraction decomposition for each rational expression. $$\frac{4}{x(1-x)}$$

7 step solution

Problem 15

For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{ll} 0.6 & 0.2 \\ 0.5 & 0.1 \end{array}\right]$$

3 step solution

Problem 15

Write the system of equations associated with each augmented matrix. $$\left[\begin{array}{rr|r} 2 & 1 & 1 \\ 3 & -2 & -9 \end{array}\right]$$

4 step solution

Problem 15

Your friend missed the lecture on adding matrices. In your own words, explain to her how to add two matrices.

5 step solution

Problem 15

Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{array}{r} x+3 y+4 z=14 \\ 2 x-3 y+2 z=10 \\ 3 x-y+z=9 \end{array}$$

6 step solution

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