Problem 13
Question
For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{ll} -6 & 4 \\ -3 & 2 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
The matrix \(A\) is not invertible because its determinant is zero.
1Step 1: Determine if the Matrix is Invertible
To find the inverse of the matrix \(A\), we first need to check if it is invertible. A matrix is invertible if its determinant is non-zero. Compute the determinant of \(A\) using the formula: \[ \text{det}(A) = ad - bc \]for a 2x2 matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\). In our case, \(a = -6\), \(b = 4\), \(c = -3\), and \(d = 2\). Thus,\[ \text{det}(A) = (-6)(2) - (4)(-3) = -12 + 12 = 0 \].
2Step 2: Conclude about Invertibility
Since the determinant of matrix \(A\) is 0, \(A\) is not invertible. A matrix with a determinant of zero does not have an inverse.
Key Concepts
Determinant2x2 MatrixInvertibility
Determinant
When you're dealing with matrices, one important concept to grasp is the determinant. Especially in the context of finding the inverse of a matrix. The determinant is a special number calculated from the elements of a square matrix. In the case of a 2x2 matrix, it provides vital information about the matrix's properties. Given a matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant is found using the formula:
- \( \text{det}(A) = ad - bc \)
2x2 Matrix
The 2x2 matrix is a fundamental building block in linear algebra and appears frequently in various mathematical contexts. A 2x2 matrix has two rows and two columns, which makes it the simplest non-trivial example of a square matrix. For any given entries \( a, b, c, \) and \( d \), you can express a 2x2 matrix as:
- \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \)
Invertibility
Invertibility is a core concept in linear algebra, referring to a matrix's ability to have an inverse. Not all matrices can be inverted—that is, some don't possess an inverse at all. A matrix has an inverse if and only if its determinant is non-zero. This is especially simple to see in a 2x2 matrix scenario. For a given matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), if \( ad - bc e 0 \), the matrix is invertible.
- The inverse of the matrix \( A \), represented as \( A^{-1} \), can theoretically be calculated if it is invertible.
- If the determinant is zero, the matrix is not invertible, and no such inverse \( A^{-1} \) exists.
Other exercises in this chapter
Problem 13
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