Problem 9
Question
Write the augmented matrix for each system. Do not solve the system. $$\begin{array}{r} x+5 y=6 \\ x=3 \end{array}$$
Step-by-Step Solution
Verified Answer
\(\begin{bmatrix} 1 & 5 & | & 6 \\ 1 & 0 & | & 3 \end{bmatrix}\)
1Step 1: Identify the System of Equations
The system of equations is given as: \[\begin{array}{r}x + 5y = 6 \x = 3 \\end{array}\] This involves two equations with two variables, \(x\) and \(y\).
2Step 2: Rewrite Each Equation in Standard Form
Ensure both equations are in standard form, \( Ax + By = C \). The equations already fit this form:1. \(x + 5y = 6\) 2. \(x + 0y = 3\) (Note: we explicitly express the absence of \(y\) in the second equation by writing it as \(0y\)).
3Step 3: Extract Coefficients for the Augmented Matrix
For the augmented matrix, extract the coefficients of \(x\) and \(y\) and the constants from both equations:1. From \(x + 5y = 6\), coefficients are \(1, 5\) and constant \(6\).2. From \(x + 0y = 3\), coefficients are \(1, 0\) and constant \(3\).
4Step 4: Write the Augmented Matrix
Form the augmented matrix using the coefficients and constants extracted:\[\begin{bmatrix}1 & 5 & | & 6 \1 & 0 & | & 3\end{bmatrix}\] This matrix represents the system of equations, where each row corresponds to an equation from the system.
Key Concepts
Systems of EquationsCoefficientsStandard FormLinear Equations
Systems of Equations
A system of equations is essentially a collection of two or more equations that work together with shared variables. In our everyday context, when two or more equations are considered at the same time, they form a system of equations. In the context of the given exercise, we are working with two equations:
- Equation 1: \( x + 5y = 6 \)
- Equation 2: \( x = 3 \)
Coefficients
Coefficients are the numerical values that are directly placed alongside the variables in an equation. They serve as multipliers of the variables and are crucial in forming the augmented matrix of a system. In our example, each equation has coefficients:
- For the equation \( x + 5y = 6 \), the coefficient of \(x\) is 1 and for \(y\) is 5.
- In the equation \( x = 3 \), the coefficient of \(x\) is 1, while \(y\) is not present, so we can consider its coefficient to be 0 (thus, it's \(x + 0y = 3\)).
Standard Form
The standard form of a linear equation is expressed as \( Ax + By = C \), where \( A \), \( B \), and \( C \) are constants, and \( x \) and \( y \) are variables. This conventional format makes it easier to organize and solve systems of equations because each equation conforms to the same structure.
In the provided exercise:
In the provided exercise:
- The first equation, \( x + 5y = 6 \), already fits nicely into this form where \( A = 1 \), \( B = 5 \), and \( C = 6 \).
- The second equation, \( x = 3 \), is also in standard form implied by \( x + 0y = 3 \), with \( A = 1 \), \( B = 0 \), and \( C = 3 \).
Linear Equations
Linear equations are equations of the first degree, meaning they only include variables raised to the power of one. They form straight lines when graphed on a coordinate plane, hence the name 'linear'. In any linear equation like \( Ax + By = C \), the solution represents all the points \( (x, y) \) that lie on the line defined by the equation.
In context of our exercise, both equations
In context of our exercise, both equations
- \( x + 5y = 6 \)
- \( x = 3 \)
Other exercises in this chapter
Problem 9
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Find the value of each variable. Do not use a calculator. $$\left[\begin{array}{ll}w & x \\ y & z\end{array}\right]=\left[\begin{array}{rr}3 & 2 \\ -1 & 4\end{a
View solution Problem 9
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} &x+2 y+z=4\\\ &x+y=0\\\
View solution