Chapter 10
A Complete Resource Book in Mathematics for JEE Main ยท 120 exercises
Problem 62
If \(a_{1}, a_{2}, a_{3}, a_{4}\) are in H.P., then \(\frac{1}{a_{1} a_{4}} \sum_{r=1}^{3} a_{r} a_{r+1}\) is a root of (A) \(x^{2}+2 x+15=0\) (B) \(x^{2}+2 x-15=0\) (C) \(x^{2}-6 x-8=0\) (D) \(x^{2}-9 x+20=0\)
6 step solution
Problem 63
The sum to \(n\) terms of the series \(\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots\) is (A) \(n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}\) (B) \(n-\frac{2\left(3^{n}-2^{n}\right)}{3^{n}}\) (C) \(2^{n}-1\) (D) \(3^{n}-1\)
7 step solution
Problem 64
If \(a+b+c=3\) and \(a>0, b>0, c>0\), then the greatest value of \(a^{2} b^{3} c^{2}\) is (A) \(\frac{3^{10} \cdot 2^{4}}{7^{7}}\) (B) \(\frac{3^{9} \cdot 2^{4}}{7^{7}}\) (C) \(\frac{3^{8} \cdot 2^{4}}{7^{7}}\) (D) None of these
6 step solution
Problem 65
Let the harmonic mean and the geometric mean of two positive numbers be in the ratio \(4: 5\). The two numbers are in the ratio (A) \(1: 1\) (B) \(2: 1\) (C) \(3: 1\) (D) \(4: 1\)
8 step solution
Problem 66
The first and last term of an A.P. are \(a\) and \(l\), respectively. If \(S\) is the sum of all the terms of the A.P. and the common difference is \(\frac{l^{2}-a^{2}}{k-(l+a)}\), then \(k\) is equal to (A) \(S\) (B) \(2 S\) (C) \(3 S\) (D) None of these
7 step solution
Problem 67
If \(a_{1}, a_{2}, \ldots, a_{n}\) are in A.P. with common difference \(d \neq 0\), then sum of the series \(\sin d\left[\sec a_{1} \sec a_{2}+\sec a_{2}\right.\) \(\left.\sec a_{3}+\ldots+\sec a_{n-1} \sec a_{n}\right]\) is (A) \(\tan a_{n}-\tan a_{1}\) (B) \(\cot a_{n}-\cot a_{1}\) (C) \(\sec a_{n}-\sec a_{1}\) (D) \(\operatorname{cosec} a_{n}-\operatorname{cosec} a_{1}\)
6 step solution
Problem 68
Sum to \(n\) terms of the series \(\frac{1}{5 !}+\frac{1 !}{6 !}+\frac{2 !}{7 !}+\frac{3 !}{8 !}+\ldots\) is (A) \(\frac{2}{5 !}-\frac{1}{(n+1) !}\) (B) \(\frac{1}{4}\left(\frac{1}{4 !}-\frac{n !}{(n+4) !}\right)\) (C) \(\frac{1}{4}\left(\frac{1}{3 !}-\frac{3 !}{(n+2) !}\right)\) (D) None of these
6 step solution
Problem 70
For any odd integer \(n \geq 1\), \(n^{3}-(n-1)^{3}+\ldots+(-1)^{n-1} 1^{3}=\) (A) \(\frac{1}{2}(n-1)^{2}(2 n-1)\) (B) \(\frac{1}{4}(n-1)^{2}(2 n-1)\) (C) \(\frac{1}{2}(n+1)^{2}(2 n-1)\) (D) \(\frac{1}{4}(n+1)^{2}(2 n-1)\)
6 step solution
Problem 71
For a positive integer \(n\), let \(a(n)=\) \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\ldots+\frac{1}{\left(2^{n}\right)-1}\), Then (A) \(a(100) \leq 100\) (B) \(a(100)>100\) (C) \(a(200) \leq 100\) (D) \(a(200)>100\)
4 step solution
Problem 72
Let \(\alpha, \beta, \gamma\) be the roots of the equation \(3 x^{3}-x^{2}-3 x+1=0 .\) If \(\alpha, \beta, \gamma\) are in H.P. then \(|\alpha-\gamma|=\) (A) \(\frac{1}{3}\) (B) \(\frac{2}{3}\) (C) \(\frac{4}{3}\) (D) None of these
5 step solution
Problem 74
The coefficient of \(x^{n}\) in the product \((1-x)(1-2 x)\left(1-2^{2} \cdot x\right)\left(1-2^{3} \cdot x\right) \ldots\left(1-2^{n}+x\right)\) is equal to \((\) A \()\left(1-2^{n+1}\right) 2^{\frac{n(n-1)}{2}}\). (B) \(\left(2^{n+1}-1\right) \cdot 2^{\frac{n(n-1)}{2}}\) (C) \(\left(1-2^{n}\right) 2^{\frac{n(n-1)}{2}}\). (D) None of these
6 step solution
Problem 75
If \(0.272727 \ldots, x\) and \(0.727272 \ldots\) are in H.P., then \(x\) must be (A) rational (B) integer (C) irrational (D) None of these
6 step solution
Problem 76
If \(a_{1}=0\) and \(a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) are real numbers such that \(\left|a_{i}\right|=\left|a_{i-1}+1\right|\) for all \(i\) then the A.M. of the numbers \(a_{1}, a_{2}, \ldots, a_{n}\) has value \(x\) where (A) \(x \leq-\frac{1}{2}\) (B) \(x \geq-\frac{1}{2}\) (C) \(x<-\frac{1}{2}\) (D) None of these
5 step solution
Problem 77
If \(a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) are in H.P, then \(\frac{a_{1}}{a_{2}+a_{3}+\ldots+a_{n}}, \frac{a_{2}}{a_{1}+a_{3}+\ldots+a_{n}} \cdots\) \(\frac{a_{n}}{a_{1}+a_{2}+\ldots+a_{n-1}}\) are in (A) A.P. (B) G.P. (C) H.P. (D) None of these
6 step solution
Problem 78
The consecutive numbers of a three digit number form a G.P. If we subtract 792 from this number, we get a number consisting of the same digits written in the reverse order and if we increase the second digit of the required number by 2, the resulting number forms an A.P. The number is (A) 139 (B) 193 (C) 931 (D) None of these
7 step solution
Problem 79
The largest term of the sequence \(\frac{1}{503}, \frac{4}{524}, \frac{9}{581}, \frac{16}{692}, \ldots\) is (A) \(\frac{16}{692}\) (B) \(\frac{4}{524}\) (C) \(\frac{49}{1520}\) (D) None of these
5 step solution
Problem 80
The coefficient of \(x^{99}\) and \(x^{98}\) in the polynomial \((x-1)(x-2)(x-3) \ldots(x-100)\) are (A) \(-5050\) and 12482075 (B) \(-4050\) and 12582075 (C) \(-5050\) and 12582075 (D) None of these
4 step solution
Problem 81
The three successive terms of a G.P. will form the sides of a triangle if the
common ratio \(r\) satisfies the inequality
(A) \(\frac{\sqrt{3}-1}{2}
8 step solution
Problem 82
If the sides of a right angled triangle are in G.P., then the cosine of the greater acute angle is (A) \(\frac{1}{1+\sqrt{5}}\) (B) \(\frac{1}{1-\sqrt{5}}\) (C) \(\frac{1+\sqrt{5}}{2}\) (D) None of these
4 step solution
Problem 85
If, in a G.P. of \(3 n\) terms, \(S_{1}\) denotes the sum of the first \(n\) terms, \(S_{2}\) the sum of the second block of \(n\) terms and \(S_{3}\) the sum of the last \(n\) terms, then \(S_{1}, S_{2}, S_{3}\) are in (A) A.P. (B) G.P. (C) H.P. (D) None of these
6 step solution
Problem 86
In a geometric series, the first term is \(a\) and common ratio is \(r\). If \(\mathrm{S}_{n}\) denotes the sum of \(n\) terms and \(U_{n}\) \(=\sum_{n=1}^{n} \mathrm{~S}_{n}\), then \(r S_{n}+(1-r) u_{n}=\) (A) \(n a\) (B) \((n-1) a\) (C) \((n+1) a\) (D) None of these
5 step solution
Problem 88
If \(\frac{1}{1^{4}}+\frac{1}{2^{4}}+\frac{1}{3^{4}}+\ldots .\) up to \(\infty=\frac{\pi^{4}}{90}\), then the value of \(\frac{1}{1^{4}}+\frac{1}{3^{4}}+\frac{1}{5^{4}}+\ldots .\) up to \(\infty\) is (A) \(\frac{\pi^{4}}{45}\) (B) \(\frac{\pi^{4}}{96}\) (C) \(\frac{\pi^{4}}{124}\) (D) None of these
6 step solution
Problem 89
If the \((m+1)\) th, \((n+1)\) th and \((r+1)\) th terms of an A.P. are in G.P. and \(m, n, r\) are in H.P., then the ratio of the first term of the A.P. to its common difference is (A) \(\frac{n}{3}\) (B) \(-\frac{n}{3}\) (C) \(\frac{n}{2}\) (D) \(-\frac{n}{2}\)
6 step solution
Problem 90
Let there be \(n\) numbers in G.P. whose common ratio is \(r\) and \(S_{m}\) denotes the sum of their first \(m\) terms. The sum of their products taken two at a time is \(k S_{n} S_{n-1}\) where \(k=\) (A) \(\frac{r-1}{r}\) (B) \(\frac{r-1}{r+1}\) (C) \(\frac{r}{r+1}\) (D) None of these
7 step solution
Problem 92
If \(H_{n}=1+\frac{1}{2}+\frac{1}{3}+\ldots .+\frac{1}{n}\), then the value of \(1+\frac{3}{2}+\frac{5}{3}+\ldots+\frac{2 n-1}{n}\) is (A) \(n-H_{n}\) (B) \(2 n-H_{n}\) (C) \((n-1)-H_{n}\) (D) \(n-2 H_{n}\)
5 step solution
Problem 93
If \(a_{m}\) be the \(m\) th term of an A.P., then \(a_{1}^{2}-a_{2}^{2}+a_{3}^{2}-a_{4}^{2}+\ldots .+a_{2 n-1}^{2}-a_{2 n}^{2}=\) (A) \(\frac{n-1}{2 n-1}\left(a_{1}^{2}-a_{2 n}^{2}\right)\) (B) \(\frac{n}{2 n-1}\left(a_{2 n}^{2}-a_{1}^{2}\right)\) (C) \(\frac{n}{2 n-1}\left(a_{1}^{2}-a_{2 n}^{2}\right)\) (D) None of these
7 step solution
Problem 94
If \(a_{n+1}=\frac{1}{1-a_{n}}\) for \(n \geq 1\) and \(a_{3}=a_{1}\), then \(\left(a_{2001}\right)^{2001}=\) (A) 1 (B) \(-1\) (C) 0 (D) None of these
6 step solution
Problem 95
If \(a, b, c\) are positive numbers in G.P. and log \(\left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)\) and \(\log \left(\frac{a}{3 b}\right)\) are in A.P. then \(a, b, c\) (A) form the sides of an equilateral triangle (B) form the sides of an isosceles triangle (C) form the sides of a right angled triangle (D) can not form the sides of a triangle
5 step solution
Problem 96
If \(a, b, c\) are in G.P. and \(\log a-\log 2 b, \log 2 b-\log 3 c\) and \(\log 3 c-\log a\) are in A.P., then \(a, b, c\) are the sides of a triangle which is (A) right angled (B) acute angled (C) obtuse angled (D) None of these
7 step solution
Problem 97
In a sequence of \(4 n+1\) terms, the first \(2 n+1\) terms are in A.P. having common difference 2 and the last \(2 n+1\) terms are in G.P. having common ratio \(\frac{1}{2}\), If the middle term of the A.P. is equal to the middle term of the G.P. then the middle term of the sequence is (A) \(\frac{n \cdot 2^{n+1}}{2^{n}+1}\) (B) \(\frac{n \cdot 2^{n+1}}{2^{n}-1}\) (C) \(\frac{n \cdot 2^{n}}{2^{n}-1}\) (D) None of these
5 step solution
Problem 98
If \(S_{1}, S_{2}\) and \(S_{3}\) denote the sums up to \(n>1\) terms of three sequences in A.P. whose first terms are unity and common differences are in H.P. then \(n=\) (A) \(\frac{2 S_{3} S_{1}+S_{1} S_{2}+S_{2} S_{3}}{S_{1}-2 S_{2}+S_{3}}\) (B) \(\frac{2 S_{3} S_{1}-S_{1} S_{2}-S_{2} S_{3}}{S_{1}+2 S_{2}+S_{3}}\) (C) \(\frac{2 S_{3} S_{1}-S_{1} S_{2}-S_{2} S_{3}}{S_{1}-2 S_{2}+S_{3}}\) (D) None of these
6 step solution
Problem 100
Let \(a\) be a fixed real number such that \(\frac{a-x}{p x}=\frac{a-y}{q y}=\frac{a-z}{r z}\)If \(p, q, \mathrm{r}\) are in A.P. then \(x, y, z\) are in (A) A.P. (B) G.P. (C) H. P (D) None of these
5 step solution
Problem 101
If \(|a|<1\) and \(|b|<1\), then the sum of the series \(1+(1+a) b+\left(1+a+a^{2}\right) b^{2}+\left(1+a+a^{2}+a^{3}\right) b^{3}+\) \(\ldots \infty\) is equal to (A) \(\frac{1}{(1-b)(1-a b)}\) (B) \(\frac{1}{(1-a)(1-a b)}\) (C) \(\frac{1}{(1-a)(1-b)}\) (D) None of these
6 step solution
Problem 103
The sixth term of an A.P. is equal to 2 . The value of the common difference of the A.P. which makes the product \(a_{1} a_{4} a_{5}\) greatest, is (A) \(\frac{8}{5}\) (B) \(\frac{2}{3}\) (C) \(\frac{3}{5}\) (D) \(\frac{3}{4}\)
6 step solution
Problem 106
If the first and the \((2 n-1)\) th terms of an A.P., G.P. and H.P. are equal and their \(n\)th terms are \(a, b, c\) respectively, then (A) \(a=b=c\) (B) \(a \geq b \geq c\) (C) \(a+c=b\) (D) \(a c-b^{2}=0\)
4 step solution
Problem 108
If \(a, b, c\) are in A.P. and \(a^{2}, b^{2}, c^{2}\) arc in H.P. then (A) \(a=b=c\) (B) \(-\frac{a}{2}, b, c\) are in G.P. (C) \(-\frac{c}{2}, b, a\) are in G.P. (D) \(-\frac{a}{2}, b, c\) are in H.P.
5 step solution
Problem 109
If the G.M. between \(a\) and \(b\) be twice the H.M., then \(\frac{a}{b}\) is equal to (A) \(\frac{2+\sqrt{3}}{2-\sqrt{3}}\) (B) \(\frac{2-\sqrt{3}}{2+\sqrt{3}}\) (C) \(\frac{4+\sqrt{3}}{4-\sqrt{3}}\) (D) \(\frac{4-\sqrt{3}}{4+\sqrt{3}}\)
11 step solution
Problem 110
If \(a, b, c\) are in G.P. and \(x\) is the A.M. between \(a\) and \(b, y\) the A.M. between \(b\) and \(c\), then (A) \(\frac{a}{x}+\frac{c}{y}=1\) (B) \(\frac{a}{x}+\frac{c}{y}=2\) (C) \(\frac{1}{x}+\frac{1}{y}=\frac{2}{b}\) (D) None of these
5 step solution
Problem 111
The solution of the equations \(\log x+\log x^{1 / 2}+\log x^{1 / 4}\) \(+\ldots=y\) and \(\frac{1+3+5+\ldots . .+(2 y-1)}{4+7+10+\ldots+(3 y+1)}\) \(=\frac{20}{7 \log x}\) is (A) \(x=10^{5}, 10^{-5 / 7}\) (B) \(y=10,-\frac{10}{7}\) (C) \(x=10,-\frac{10}{7}\) (D) \(y=10^{5}, 10^{-5 / 7}\)
7 step solution
Problem 112
The sum of of first ten terms of an A.P. is equal to 155 and the sum of first two terms of a G.P. is 9 . If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to the common difference of the A.P, then (A) first term of the G.P. is \(\frac{2}{3}, 3\) (B) first term of the A.P. is \(\frac{2}{3}, 3\) (C) Common ratio of the G.P. is \(\frac{25}{2}, 2\) (D) Common difference of the A.P is \(\frac{2}{3}, 3\)
7 step solution
Problem 113
Let \(\left(1+x^{2}\right)^{2}(1+x)^{n}=\sum_{k=0}^{n+4} a_{k} x^{k}\). If \(a_{1}, a_{2}, a_{3}\), are in A.P., then \(n\) is equal to (A) 1 (B) 2 (C) 3 (D) 4
6 step solution
Problem 114
If \(a, b, c\) are non-zero real numbers such that 3 \(\left(a^{2}+b^{2}+c^{2}+1\right)=2(a+b+c+a b+b c+c a)\), then, \(a, b, c\) are in (A) A.P. (B) G. P. (C) H.P. (D) all equal
6 step solution
Problem 115
Let \(t_{n}=\underbrace{1.1 \ldots 1}_{n \text { times }}\), then (A) \(t_{912}\) is not prime (B) \(t_{951}\) is not prime (C) \(t_{480}\) is not prime (D) \(t_{91}\) is not prime
6 step solution
Problem 118
Sum to \(n\) terms of the series \(\frac{1}{1 \cdot 3}+\frac{1}{3 \cdot 5}+\frac{1}{5 \cdot 7}+\ldots .\) is (A) \(\frac{n}{2 n+1}\) (B) \(\frac{n}{2 n-1}\) (C) \(\frac{n-1}{2 n+1}\) (D) None of these
4 step solution
Problem 119
Sum to infinite terms of the series \(\frac{1}{1 \cdot 3}+\frac{1}{3 \cdot 5}+\frac{1}{5 \cdot 7}+\ldots .\) is (A) \(\frac{1}{4}\) (B) \(\frac{1}{3}\) (C) \(\frac{1}{2}\) (D) None of these
6 step solution
Problem 120
The sum to infinity of the series \(1+\frac{3}{2}+\frac{5}{2^{2}}+\frac{7}{2^{3}}+\ldots\) is (A) 4 (B) 6 (C) 8 (D) None of these
4 step solution
Problem 122
If the sum to infinity of the series \(3+(3+d) \frac{1}{4}+(3+2 d) \frac{1}{4^{2}}+\ldots\) is \(\frac{44}{9}\), then \(d=\) (A) 1 (B) 2 (C) 4 (D) None of these
6 step solution
Problem 123
\(3^{1 / 3} \cdot 9^{1 / 9} \cdot 27^{1 / 27} \cdot 81^{1 / 81} \ldots\) upto \(\infty=\) (A) \(\sqrt{27}\) (B) \(\sqrt[3]{27}\) (C) \(\sqrt[4]{27}\) (D) None of these
6 step solution
Problem 130
\begin{tabular}{l} Column-I & Column-II \\ \hline I. If \(a, b, c\) are in A.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in H.P., then (A) A.P. \\ \(\qquad a, c, e\) are in \\ II. If \(2(y-a)\) is the H.M. between \(y-x, y-z\) then \(x-a, y-a, z-a\) & (B) G.P. \\\ are in \\ III. If three numbers are in H.P., then the numbers obtained by subtract- (C) H.P. \\ ing half of the middle number from each of them are in \\ IV. If \(a, b, c\) are in G.P., then the equations \(a x^{2}+2 b x+c=0\) and \(d x^{2}+\) (D) A.G.P. \\ \(2 e x+f=0\) have a common root, if \(\frac{d}{a}, \frac{e}{b}\) and \(\frac{f}{c}\) are in \end{tabular}
4 step solution
Problem 132
Assertion: If \(a, b, c\) are distinct positive real numbers and \(a^{2}+b^{2}+c^{2}=1\), then \(a b+b c+c a\) is less than 1 . Reason: A.M. >G.M. for unequal numbers
7 step solution