Chapter 10

A Complete Resource Book in Mathematics for JEE Main · 120 exercises

Problem 1

If \(a, b, c\) are positive numbers in A.P. such that their product is 64 , then the minimum value of \(b\) \((\mathrm{A})=2\) (B) \(=4\) \((\mathrm{C})=1\) (D) Does not exist

4 step solution

Problem 2

If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\triangle A B C\) and \([r]\) denotes greatest integer function, then \([r]+[-r]=\) (A) 0 (B) 1 (C) \(-1\) (D) None of these

6 step solution

Problem 4

Number of increasing geometrical progression(s) with first term unity, such that any three consecutive terms, on doubling the middle become an A.P, is (A) 0 (B) (C) 2 (D) infinity

7 step solution

Problem 6

Let \(S_{n}(1 \leq n \leq 9)\) denotes the sum of \(n\) terms of series \(1+22+333+\ldots+999999999\), then for \(2 \leq n \leq 9\) (A) \(S_{n}-S_{n-1}=\frac{1}{9}\left(10^{n}-n^{2}+n\right)\) (B) \(S_{n}=\frac{1}{9}\left(10^{n}-n^{2}+2 n-2\right)\) (C) \(9\left(S_{n}-S_{n-1}\right)=n\left(10^{n}-1\right)\) (D) None of these

5 step solution

Problem 7

If \(\log _{\sqrt{5}} x+\log _{5^{n}} x+\log _{5^{4}} x+\ldots\) upto 7 terms \(=35\), then \(x\) is equal to (A) 5 (B) 25 (C) 125 (D) None of these

7 step solution

Problem 8

If \(\sum_{n=1}^{\infty} x^{n-1}=a\) and \(\sum_{n=1}^{\infty} y^{n-1}=b\) where \(|x|,|y|<1\), then \(\sum_{n=1}^{\infty}(x y)^{n-1}=\) (A) \(a b\) (B) \(\frac{a+b-1}{a b}\) (C) \(\frac{1}{1-a b}\) (D) \(\frac{a b}{a+b-1}\)

2 step solution

Problem 9

Let \(p, q, r \in R^{+}\)and \(27 p q r \geq(p+q+r)^{3}\) and \(3 p+4 q\) \(+5 r=12\) then \(p^{3}+q^{4}+r^{5}\) is equal to (A) 3 (B) 6 (C) 2 (D) None of these

7 step solution

Problem 10

The sum of the series \(\frac{1}{1+1^{2}+1^{4}}+\frac{2}{1+2^{2}+2^{4}}+\frac{3}{1+3^{2}+3^{4}}+\ldots\) to \(n\) terms is (A) \(\frac{n\left(n^{2}+1\right)}{n^{2}+n+1}\) (B) \(\frac{n(n+1)}{2\left(n^{2}+n+1\right)}\) (C) \(\frac{n\left(n^{2}-1\right)}{2\left(n^{2}+n+1\right)}\) (D) None of these

5 step solution

Problem 11

\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\). Then (A) \(x<-1\) or \(x>3\) (B) \(-1

6 step solution

Problem 12

The sum of the first hundred terms of an A.P. is \(x\) and the sum of the hundred terms starting from the third term is \(y\). Then the common difference is (A) \(\frac{y-x}{2}\) (B) \(\frac{y-x}{50}\) (C) \(\frac{y-x}{100}\) (D) \(\frac{y-x}{200}\)

6 step solution

Problem 13

If \(\lambda=\sum_{i=1}^{\infty} \frac{1}{i^{4}}\), then \(\sum_{i=1}^{\infty} \frac{1}{(2 i-1)^{4}}\) is (A) \(\frac{14}{15} \lambda\) (B) \(\frac{\lambda}{2}\) (C) \(\frac{16}{15} \lambda\) (D) \(\frac{15}{16} \lambda\)

6 step solution

Problem 14

The sum of all possible products of the first \(n\) natural numbers taken two at a time is (A) \(\frac{1}{2}\left[\Sigma n^{2}-\Sigma n\right]\) (B) \(\frac{1}{2}\left[(\Sigma n)^{2}-\Sigma n\right]\) (C) \(\frac{1}{2}\left[\Sigma n^{2}-\Sigma(n+1)\right]\) (D) \(\frac{1}{2}\left[(\Sigma n)^{2}-\Sigma n^{2}\right]\)

6 step solution

Problem 15

The minimum value of \(8^{\sin x^{\prime} 8}+8^{\cos x^{\prime} 8}\) is (A) \(2^{\frac{1}{3-\sqrt{2} / \sqrt{2}}}\) (B) \(2^{\frac{3+\sqrt{2}}{\sqrt{2}}}\) (C) \(2^{\frac{1}{3+\sqrt{2} / \sqrt{2}}}\) (D) \(2^{\frac{3-\sqrt{2}}{\sqrt{2}}}\)

6 step solution

Problem 16

If \(\log _{2^{12}} a+\log _{2^{n}} a+\log _{2^{n}} a+\log _{2^{n}} a+\ldots\) upto 20 terms is 840 , then \(a\) is equal to(A) 2 (B) 1 (C) 4 (D) \(\sqrt{2}\)

7 step solution

Problem 18

If \(a, b, c\) are distinct positive real numbers and \(a^{2}+b^{2}\) \(+c^{2}=1\), then \(a b+b c+c a\) is (A) less than 1 (B) equal to 1 (C) greater than 1 (D) any real number

3 step solution

Problem 19

The value of \((n-2)^{2}+(n-4)^{2}+(n-6)^{2}+\ldots\) to \(n\) terms is (A) \(\frac{n}{3}\left(n^{2}+2\right)\) (B) \(\frac{n}{2}\left(n^{2}+3\right)\) (C) \(\frac{n}{3}\left(n^{2}-2\right)\) (D) \(\frac{n}{2}\left(n^{2}-3\right)\)

6 step solution

Problem 21

\(a_{1}, a_{2}, a_{3}, \ldots\) are in A.P. with common difference not a multiple of 3 . Then, maximum number of consecutive terms so that all the terms are prime numbers is (A) 2 (B) 3 (C) 5 (D) infinite

4 step solution

Problem 22

The coefficient of \(x^{49}\) in the product \((x-1)(x-3) \ldots\) \((x-99)\) is (A) \(-99^{2}\) (B) 1 (C) \(-2500\) (D) None of these

5 step solution

Problem 23

If \(x, y, z\) are three real numbers of the same sign then the value of \(\frac{x}{y}+\frac{y}{z}+\frac{z}{x}\) lies in the interval (A) \([2, \infty)\) (B) \([3, \infty)\) (C) \((3, \infty)\) (D) \((-\infty, 3)\)

4 step solution

Problem 24

In a G.P. of alternating positive and negative terms, any term is the A.M. of the next two terms. Then the common ratio is (A) \(-1\) (B) \(-3\) (C) \(-2\) (D) \(\frac{-1}{2}\)

5 step solution

Problem 26

If the sum of \(n\) terms of an A.P. is cn \((n-1)\), where \(c \neq 0\), then sum of the squares of these terms is (A) \(c^{2} n^{2}(n+1)^{2}\) (B) \(\frac{2}{3} c^{2} n(n-1)(2 n-1)\) (C) \(\frac{2 c^{2}}{3} n(n+1)(2 n+1)\) (D) None of these

7 step solution

Problem 28

If \(b_{1}, b_{2}\) and \(b_{3}\left(b_{1}>0\right)\) are three successive terms of a G.P. with common ratio \(r\), the value of \(r\) for which the inequality \(b_{3}>4 b_{2}-3 b_{1}\) holds, is given by (A) \(r>3\) (B) \(r<1\) (C) \(r=2.5\) (D) \(r=1.7\)

6 step solution

Problem 29

If \(p, q, r\) are positive and are in A.P., the roots of quadratic equation \(p x^{2}+q x+r=0\) are all real for (A) \(\left|\frac{r}{p}-7\right| \geq 4 \sqrt{3}\) (B) \(\left|\frac{p}{r}-7\right| \geq 4 \sqrt{3}\) (C) all \(p\) and \(r\) (D) no \(p\) and \(r\)

6 step solution

Problem 30

The sum to \(n\) terms of the series \(\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots\) is (A) \(n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}\) (B) \(n-\frac{2\left(3^{n}-2^{n}\right)}{3^{n}}\) (C) \(2^{n}-1\) (D) \(3^{n}-1\)

6 step solution

Problem 31

Sum to \(n\) terms of the series \(\frac{1}{5 !}+\frac{1 !}{6 !}+\frac{2 !}{7 !}+\frac{3 !}{8 !}+\ldots\) is (A) \(\frac{2}{5 !}-\frac{1}{(n+1) !}\) (B) \(\frac{1}{4}\left(\frac{1}{4 !}-\frac{n !}{(n+4) !}\right)\) (C) \(\frac{1}{4}\left(\frac{1}{3 !}-\frac{3 !}{(n+2) !}\right)\) (D) None of these

5 step solution

Problem 32

If \(a, b, c, d\) and \(p\) are distinct real numbers such that \(\left(a^{2}+b^{2}+c^{2}\right) p^{2}-2 p(a b+b c+c d)+\left(b^{2}+c^{2}+d^{2}\right)\) \(\leq 0\) then \(a, b, c, d\) are in (A) A.P. (B) G.P. (C) H.P. (D) \(a b=c d\)

5 step solution

Problem 33

If \(a+b+c=3\) and \(a>0, b>0, c>0\), then the greatest value of \(a^{2} b^{3} c^{2}\) is (A) \(\frac{3^{10} \cdot 2^{4}}{7^{7}}\) (B) \(\frac{3^{9} \cdot 2^{4}}{7^{7}}\) (C) \(\frac{3^{8} \cdot 2^{4}}{7^{7}}\) (D) None of these

7 step solution

Problem 34

If \(\left|\begin{array}{ccc}a & b & a \alpha-b \\ b & c & b \alpha-c \\ 2 & 1 & 0\end{array}\right|=0\) and \(\alpha \neq \frac{1}{2}\), then (A) \(a, b, c\) are in A.P. (B) \(a, b, c\) are in G.P. (C) \(a, b, c\) are in H.P. (D) None of these

5 step solution

Problem 35

Suppose \(a, b, c\) are in A.P. and \(a^{2}, b^{2}, c^{2}\) are in G.P. If \(a

5 step solution

Problem 36

If \(a_{1}, a_{2}, \ldots, a_{n}\) are in A.P. with common difference \(d \neq 0\), then sum of the series \(\sin d\left[\sec a_{1} \sec a_{2}+\sec \right.\) \(\left.a_{2} \sec a_{3}+\ldots+\sec a_{n-1} \sec a_{n}\right]\) is (A) \(\tan a_{n}-\tan a_{1}\) (B) \(\cot a_{n}-\cot a_{1}\) (C) \(\sec a_{n}-\sec a_{1}\) (D) \(\operatorname{cosec} a_{n}-\operatorname{cosec} a_{1}\)

5 step solution

Problem 37

The first and last term of an A.P. are \(a\) and \(l\) respectively. If \(S\) is the sum of all the terms of the A.P. and the common difference is \(\frac{l^{2}-a^{2}}{k-(l+a)}\), then \(k\) is equal to (A) \(S\) (B) \(2 S\) (C) \(3 S\) (D) None of these

6 step solution

Problem 38

If \(a, b, c, d\) are in G.P., then \(\left(a^{2}+b^{2}+c^{2}\right)\left(b^{2}+c^{2}+d^{2}\right)=\) (A) \((a b+a c+b c)^{2}\) (B) \((a c+c d+a d)^{2}\) (C) \((a b+b c+c d)^{2}\) (D) None of these

3 step solution

Problem 41

A man saves ? 200 in each of the first three months of his service. In each of the subsequent months his saving increases by ? 40 more than the saving of immediately previous months. His total saving from the start of service will be ? 11040 after (A) 21 months (B) 18 months (C) 19 months (D) 20 months

6 step solution

Problem 42

Statement-1: The sum of the series \(1+(1+2+4)+\) \((4+6+9)+(9+12+16)+\ldots+(361+380+400)\) is \(8000 .\) \(\begin{array}{l}\text { Statement-2: } \\ \text { number } n .\end{array}_{k=1}^{n}\left(k^{3}-(k-1)^{3}\right)=n^{3}\), for any natural (A) Statement- 1 is false, Statement-2 is true. (B) Statement- 1 is true, statement- 2 is true; statement- 2 is a correct explanation for Statement- 1 (C) Statement- 1 is true, statement-2 is true; statement-2 is not a correct explanation for Statement-1. (D) Statement- 1 is true, statement- 2 is false.

5 step solution

Problem 43

If 100 times the \(100^{\text {th }}\) term of an \(A P\) with non-zero common difference equals the 50 times its \(50^{\text {th }}\) term, then the \(150^{\text {th }}\) term of this \(A P\) is (A) \(-150\) (B) 150 times its \(50^{\text {th }}\) term (C) 150 (D) zero

7 step solution

Problem 44

If the sum of first \(n\) terms of two A.P's are in the ratio \(3 n+8: 7 n+15\), then the ratio of their 12 th terms is (A) \(8: 7\) (B) \(7: 16\) (C) \(74: 169\) (D) \(13: 47\)

6 step solution

Problem 46

The first two terms of a geometric progression add up to 12 . The sum of the third and the fourth terms is 48 . If the terms of the geometric progression are alternately positive and negative, then the first term is (A) \(-4\) (B) \(-12\) (C) 12 (D) 4

6 step solution

Problem 49

The sum of the products of the \(2 n\) numbers \(\pm 1, \pm 2, \pm 3\). \(\ldots . \pm n\) taking two at a time is (A) \(\frac{n(n+1)}{2}\) (B) \(-\frac{n(n+1)}{2}\) (C) \(\frac{n(n+1)(2 n+1)}{6}\) (D) \(-\frac{n(n+1)(2 n+1)}{6}\)

4 step solution

Problem 50

If \(a\) is the first term, \(d\) the common difference and \(S_{k}\) the sum to \(k\) terms of an A.P., then for \(\frac{S_{k x}}{S_{x}}\) to be inde- pendent of \(x\) (A) \(a=2 d\) (B) \(a=d\) (C) \(2 a=d\) (D) None of these

5 step solution

Problem 51

Given that \(\alpha, \gamma\) are roots of the equation \(A x^{2}-4 x+1=0\) and \(\beta, \delta\) are roots of the equation \(B x^{2}-6 x+1=0\). If \(\alpha, \beta, \gamma\) and \(\delta\) are in H.P., then (A) \(A=5\) (B) \(A=-3\) (C) \(B=8\) (D) \(B=-8\)

3 step solution

Problem 52

The sum of \(n\) terms of \(m\) A.P.s are \(S_{1}, S_{2}, S_{3}, \ldots, S_{m}\), If the first term and common difference are \(1,2,3, \ldots, m\) respectively, then \(S_{1}+S_{2}+S_{3}+\ldots+S_{m}=\) (A) \(\frac{1}{4} m n(m+1)(n+1)\) (B) \(\frac{1}{2} m n(m+1)(n+1)\) (C) \(m n(m+1)(n+1)\) (D) None of these

8 step solution

Problem 53

If three positive numbers \(a, b, c\) are in H.P., then \(a^{n}+c^{n}\) \((\mathrm{A})>2 b^{n}\) \((\mathrm{B})=2 b^{n}\) \((\mathrm{C})<2 b^{n}\) \((\mathrm{D})>b^{n}\)

5 step solution

Problem 54

The sum of first \(n\) terms of the series \(1 \cdot 1 !+2 \cdot 2 !+3 \cdot 3 !+4 \cdot 4 !+\ldots\) is (A) \((n+1) !-1\) (B) \(n !-1\) (C) \((n-1) !-1\) (D) None of these

5 step solution

Problem 55

If \(a, b, c\) are digits, then the rational number represented by \(0 \cdot c a b a b a b \ldots\) is (A) \(\frac{99 c+a b}{990}\) (B) \(\frac{99 c+10 a+b}{99}\) (C) \(\frac{99 c+10 a+b}{990}\) (D) None of these

5 step solution

Problem 56

The sum of first \(n\) terms of the series \(1^{2}+2.2^{2}+3^{2}+2.4^{2}+5^{2}+5.6^{2}+\ldots\) is \(\frac{n(n+1)^{2}}{2}\) when \(n\) is even. When \(n\) is odd, the sum is (A) \(\frac{n^{2}(n+1)}{2}\) (B) \(\frac{n(n+1)^{2}}{2}\) (C) \(\left[\frac{n(n+1)}{2}\right]^{2}\) (D) \(\frac{n(n+1)}{2}\)

6 step solution

Problem 57

The sum of the series \(1+2 \cdot 2+3 \cdot 2^{2}+4 \cdot 2^{3}+5 \cdot 2^{4}+\ldots+100 \cdot 2^{99}\) is (A) \(99 \cdot 2^{100}+1\) (B) \(100 \cdot 2^{100}\) (C) \(99 \cdot 2^{100}\) (D) \(99 \cdot 2^{100}+1\)

6 step solution

Problem 58

Four different integers form an increasing A.P. If one of these numbers is equal to the sum of the squares of the other three numbers, then the numbers are (A) \(-2,-1,0,1\) (B) \(0,1,2,3\) (C) \(-1,0,1,2\) (D) None of these

6 step solution

Problem 59

If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\Delta A B C\) and \([r]\) denotes greatest integer function, then \([r]+[-r]=\) (A) 0 (B) 1 (C) \(-1\) (D) None of these

5 step solution

Problem 60

Let \(S_{n}(1 \leq n \leq 9)\) denotes the sum of \(n\) terms of series \(1+22+333+\ldots+999999999\), then for \(2 \leq n \leq 9\) (A) \(S_{n}-S_{n-1}=\frac{1}{9}\left(10^{n}-n^{2}+n\right)\) (B) \(S_{n}=\frac{1}{9}\left(10^{n}-n^{2}+2 n-2\right)\) (C) \(9\left(S_{n}-S_{n-1}\right)=n\left(10^{n}-1\right)\) (D) None of these

4 step solution

Problem 61

\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\). Then, (A) \(x<-1\) or \(x>3\) (B) \(-1

6 step solution

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