Chapter 10
A Complete Resource Book in Mathematics for JEE Main · 120 exercises
Problem 1
If \(a, b, c\) are positive numbers in A.P. such that their product is 64 , then the minimum value of \(b\) \((\mathrm{A})=2\) (B) \(=4\) \((\mathrm{C})=1\) (D) Does not exist
4 step solution
Problem 2
If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\triangle A B C\) and \([r]\) denotes greatest integer function, then \([r]+[-r]=\) (A) 0 (B) 1 (C) \(-1\) (D) None of these
6 step solution
Problem 4
Number of increasing geometrical progression(s) with first term unity, such that any three consecutive terms, on doubling the middle become an A.P, is (A) 0 (B) (C) 2 (D) infinity
7 step solution
Problem 6
Let \(S_{n}(1 \leq n \leq 9)\) denotes the sum of \(n\) terms of series \(1+22+333+\ldots+999999999\), then for \(2 \leq n \leq 9\) (A) \(S_{n}-S_{n-1}=\frac{1}{9}\left(10^{n}-n^{2}+n\right)\) (B) \(S_{n}=\frac{1}{9}\left(10^{n}-n^{2}+2 n-2\right)\) (C) \(9\left(S_{n}-S_{n-1}\right)=n\left(10^{n}-1\right)\) (D) None of these
5 step solution
Problem 7
If \(\log _{\sqrt{5}} x+\log _{5^{n}} x+\log _{5^{4}} x+\ldots\) upto 7 terms \(=35\), then \(x\) is equal to (A) 5 (B) 25 (C) 125 (D) None of these
7 step solution
Problem 8
If \(\sum_{n=1}^{\infty} x^{n-1}=a\) and \(\sum_{n=1}^{\infty} y^{n-1}=b\) where \(|x|,|y|<1\), then \(\sum_{n=1}^{\infty}(x y)^{n-1}=\) (A) \(a b\) (B) \(\frac{a+b-1}{a b}\) (C) \(\frac{1}{1-a b}\) (D) \(\frac{a b}{a+b-1}\)
2 step solution
Problem 9
Let \(p, q, r \in R^{+}\)and \(27 p q r \geq(p+q+r)^{3}\) and \(3 p+4 q\) \(+5 r=12\) then \(p^{3}+q^{4}+r^{5}\) is equal to (A) 3 (B) 6 (C) 2 (D) None of these
7 step solution
Problem 10
The sum of the series \(\frac{1}{1+1^{2}+1^{4}}+\frac{2}{1+2^{2}+2^{4}}+\frac{3}{1+3^{2}+3^{4}}+\ldots\) to \(n\) terms is (A) \(\frac{n\left(n^{2}+1\right)}{n^{2}+n+1}\) (B) \(\frac{n(n+1)}{2\left(n^{2}+n+1\right)}\) (C) \(\frac{n\left(n^{2}-1\right)}{2\left(n^{2}+n+1\right)}\) (D) None of these
5 step solution
Problem 11
\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\).
Then
(A) \(x<-1\) or \(x>3\)
(B) \(-1
6 step solution
Problem 12
The sum of the first hundred terms of an A.P. is \(x\) and the sum of the hundred terms starting from the third term is \(y\). Then the common difference is (A) \(\frac{y-x}{2}\) (B) \(\frac{y-x}{50}\) (C) \(\frac{y-x}{100}\) (D) \(\frac{y-x}{200}\)
6 step solution
Problem 13
If \(\lambda=\sum_{i=1}^{\infty} \frac{1}{i^{4}}\), then \(\sum_{i=1}^{\infty} \frac{1}{(2 i-1)^{4}}\) is (A) \(\frac{14}{15} \lambda\) (B) \(\frac{\lambda}{2}\) (C) \(\frac{16}{15} \lambda\) (D) \(\frac{15}{16} \lambda\)
6 step solution
Problem 14
The sum of all possible products of the first \(n\) natural numbers taken two at a time is (A) \(\frac{1}{2}\left[\Sigma n^{2}-\Sigma n\right]\) (B) \(\frac{1}{2}\left[(\Sigma n)^{2}-\Sigma n\right]\) (C) \(\frac{1}{2}\left[\Sigma n^{2}-\Sigma(n+1)\right]\) (D) \(\frac{1}{2}\left[(\Sigma n)^{2}-\Sigma n^{2}\right]\)
6 step solution
Problem 15
The minimum value of \(8^{\sin x^{\prime} 8}+8^{\cos x^{\prime} 8}\) is (A) \(2^{\frac{1}{3-\sqrt{2} / \sqrt{2}}}\) (B) \(2^{\frac{3+\sqrt{2}}{\sqrt{2}}}\) (C) \(2^{\frac{1}{3+\sqrt{2} / \sqrt{2}}}\) (D) \(2^{\frac{3-\sqrt{2}}{\sqrt{2}}}\)
6 step solution
Problem 16
If \(\log _{2^{12}} a+\log _{2^{n}} a+\log _{2^{n}} a+\log _{2^{n}} a+\ldots\) upto 20 terms is 840 , then \(a\) is equal to(A) 2 (B) 1 (C) 4 (D) \(\sqrt{2}\)
7 step solution
Problem 18
If \(a, b, c\) are distinct positive real numbers and \(a^{2}+b^{2}\) \(+c^{2}=1\), then \(a b+b c+c a\) is (A) less than 1 (B) equal to 1 (C) greater than 1 (D) any real number
3 step solution
Problem 19
The value of \((n-2)^{2}+(n-4)^{2}+(n-6)^{2}+\ldots\) to \(n\) terms is (A) \(\frac{n}{3}\left(n^{2}+2\right)\) (B) \(\frac{n}{2}\left(n^{2}+3\right)\) (C) \(\frac{n}{3}\left(n^{2}-2\right)\) (D) \(\frac{n}{2}\left(n^{2}-3\right)\)
6 step solution
Problem 21
\(a_{1}, a_{2}, a_{3}, \ldots\) are in A.P. with common difference not a multiple of 3 . Then, maximum number of consecutive terms so that all the terms are prime numbers is (A) 2 (B) 3 (C) 5 (D) infinite
4 step solution
Problem 22
The coefficient of \(x^{49}\) in the product \((x-1)(x-3) \ldots\) \((x-99)\) is (A) \(-99^{2}\) (B) 1 (C) \(-2500\) (D) None of these
5 step solution
Problem 23
If \(x, y, z\) are three real numbers of the same sign then the value of \(\frac{x}{y}+\frac{y}{z}+\frac{z}{x}\) lies in the interval (A) \([2, \infty)\) (B) \([3, \infty)\) (C) \((3, \infty)\) (D) \((-\infty, 3)\)
4 step solution
Problem 24
In a G.P. of alternating positive and negative terms, any term is the A.M. of the next two terms. Then the common ratio is (A) \(-1\) (B) \(-3\) (C) \(-2\) (D) \(\frac{-1}{2}\)
5 step solution
Problem 26
If the sum of \(n\) terms of an A.P. is cn \((n-1)\), where \(c \neq 0\), then sum of the squares of these terms is (A) \(c^{2} n^{2}(n+1)^{2}\) (B) \(\frac{2}{3} c^{2} n(n-1)(2 n-1)\) (C) \(\frac{2 c^{2}}{3} n(n+1)(2 n+1)\) (D) None of these
7 step solution
Problem 28
If \(b_{1}, b_{2}\) and \(b_{3}\left(b_{1}>0\right)\) are three successive terms of a G.P. with common ratio \(r\), the value of \(r\) for which the inequality \(b_{3}>4 b_{2}-3 b_{1}\) holds, is given by (A) \(r>3\) (B) \(r<1\) (C) \(r=2.5\) (D) \(r=1.7\)
6 step solution
Problem 29
If \(p, q, r\) are positive and are in A.P., the roots of quadratic equation \(p x^{2}+q x+r=0\) are all real for (A) \(\left|\frac{r}{p}-7\right| \geq 4 \sqrt{3}\) (B) \(\left|\frac{p}{r}-7\right| \geq 4 \sqrt{3}\) (C) all \(p\) and \(r\) (D) no \(p\) and \(r\)
6 step solution
Problem 30
The sum to \(n\) terms of the series \(\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots\) is (A) \(n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}\) (B) \(n-\frac{2\left(3^{n}-2^{n}\right)}{3^{n}}\) (C) \(2^{n}-1\) (D) \(3^{n}-1\)
6 step solution
Problem 31
Sum to \(n\) terms of the series \(\frac{1}{5 !}+\frac{1 !}{6 !}+\frac{2 !}{7 !}+\frac{3 !}{8 !}+\ldots\) is (A) \(\frac{2}{5 !}-\frac{1}{(n+1) !}\) (B) \(\frac{1}{4}\left(\frac{1}{4 !}-\frac{n !}{(n+4) !}\right)\) (C) \(\frac{1}{4}\left(\frac{1}{3 !}-\frac{3 !}{(n+2) !}\right)\) (D) None of these
5 step solution
Problem 32
If \(a, b, c, d\) and \(p\) are distinct real numbers such that \(\left(a^{2}+b^{2}+c^{2}\right) p^{2}-2 p(a b+b c+c d)+\left(b^{2}+c^{2}+d^{2}\right)\) \(\leq 0\) then \(a, b, c, d\) are in (A) A.P. (B) G.P. (C) H.P. (D) \(a b=c d\)
5 step solution
Problem 33
If \(a+b+c=3\) and \(a>0, b>0, c>0\), then the greatest value of \(a^{2} b^{3} c^{2}\) is (A) \(\frac{3^{10} \cdot 2^{4}}{7^{7}}\) (B) \(\frac{3^{9} \cdot 2^{4}}{7^{7}}\) (C) \(\frac{3^{8} \cdot 2^{4}}{7^{7}}\) (D) None of these
7 step solution
Problem 34
If \(\left|\begin{array}{ccc}a & b & a \alpha-b \\ b & c & b \alpha-c \\ 2 & 1 & 0\end{array}\right|=0\) and \(\alpha \neq \frac{1}{2}\), then (A) \(a, b, c\) are in A.P. (B) \(a, b, c\) are in G.P. (C) \(a, b, c\) are in H.P. (D) None of these
5 step solution
Problem 35
Suppose \(a, b, c\) are in A.P. and \(a^{2}, b^{2}, c^{2}\) are in G.P. If \(a
5 step solution
Problem 36
If \(a_{1}, a_{2}, \ldots, a_{n}\) are in A.P. with common difference \(d \neq 0\), then sum of the series \(\sin d\left[\sec a_{1} \sec a_{2}+\sec \right.\) \(\left.a_{2} \sec a_{3}+\ldots+\sec a_{n-1} \sec a_{n}\right]\) is (A) \(\tan a_{n}-\tan a_{1}\) (B) \(\cot a_{n}-\cot a_{1}\) (C) \(\sec a_{n}-\sec a_{1}\) (D) \(\operatorname{cosec} a_{n}-\operatorname{cosec} a_{1}\)
5 step solution
Problem 37
The first and last term of an A.P. are \(a\) and \(l\) respectively. If \(S\) is the sum of all the terms of the A.P. and the common difference is \(\frac{l^{2}-a^{2}}{k-(l+a)}\), then \(k\) is equal to (A) \(S\) (B) \(2 S\) (C) \(3 S\) (D) None of these
6 step solution
Problem 38
If \(a, b, c, d\) are in G.P., then \(\left(a^{2}+b^{2}+c^{2}\right)\left(b^{2}+c^{2}+d^{2}\right)=\) (A) \((a b+a c+b c)^{2}\) (B) \((a c+c d+a d)^{2}\) (C) \((a b+b c+c d)^{2}\) (D) None of these
3 step solution
Problem 41
A man saves ? 200 in each of the first three months of his service. In each of the subsequent months his saving increases by ? 40 more than the saving of immediately previous months. His total saving from the start of service will be ? 11040 after (A) 21 months (B) 18 months (C) 19 months (D) 20 months
6 step solution
Problem 42
Statement-1: The sum of the series \(1+(1+2+4)+\) \((4+6+9)+(9+12+16)+\ldots+(361+380+400)\) is \(8000 .\) \(\begin{array}{l}\text { Statement-2: } \\ \text { number } n .\end{array}_{k=1}^{n}\left(k^{3}-(k-1)^{3}\right)=n^{3}\), for any natural (A) Statement- 1 is false, Statement-2 is true. (B) Statement- 1 is true, statement- 2 is true; statement- 2 is a correct explanation for Statement- 1 (C) Statement- 1 is true, statement-2 is true; statement-2 is not a correct explanation for Statement-1. (D) Statement- 1 is true, statement- 2 is false.
5 step solution
Problem 43
If 100 times the \(100^{\text {th }}\) term of an \(A P\) with non-zero common difference equals the 50 times its \(50^{\text {th }}\) term, then the \(150^{\text {th }}\) term of this \(A P\) is (A) \(-150\) (B) 150 times its \(50^{\text {th }}\) term (C) 150 (D) zero
7 step solution
Problem 44
If the sum of first \(n\) terms of two A.P's are in the ratio \(3 n+8: 7 n+15\), then the ratio of their 12 th terms is (A) \(8: 7\) (B) \(7: 16\) (C) \(74: 169\) (D) \(13: 47\)
6 step solution
Problem 46
The first two terms of a geometric progression add up to 12 . The sum of the third and the fourth terms is 48 . If the terms of the geometric progression are alternately positive and negative, then the first term is (A) \(-4\) (B) \(-12\) (C) 12 (D) 4
6 step solution
Problem 49
The sum of the products of the \(2 n\) numbers \(\pm 1, \pm 2, \pm 3\). \(\ldots . \pm n\) taking two at a time is (A) \(\frac{n(n+1)}{2}\) (B) \(-\frac{n(n+1)}{2}\) (C) \(\frac{n(n+1)(2 n+1)}{6}\) (D) \(-\frac{n(n+1)(2 n+1)}{6}\)
4 step solution
Problem 50
If \(a\) is the first term, \(d\) the common difference and \(S_{k}\) the sum to \(k\) terms of an A.P., then for \(\frac{S_{k x}}{S_{x}}\) to be inde- pendent of \(x\) (A) \(a=2 d\) (B) \(a=d\) (C) \(2 a=d\) (D) None of these
5 step solution
Problem 51
Given that \(\alpha, \gamma\) are roots of the equation \(A x^{2}-4 x+1=0\) and \(\beta, \delta\) are roots of the equation \(B x^{2}-6 x+1=0\). If \(\alpha, \beta, \gamma\) and \(\delta\) are in H.P., then (A) \(A=5\) (B) \(A=-3\) (C) \(B=8\) (D) \(B=-8\)
3 step solution
Problem 52
The sum of \(n\) terms of \(m\) A.P.s are \(S_{1}, S_{2}, S_{3}, \ldots, S_{m}\), If the first term and common difference are \(1,2,3, \ldots, m\) respectively, then \(S_{1}+S_{2}+S_{3}+\ldots+S_{m}=\) (A) \(\frac{1}{4} m n(m+1)(n+1)\) (B) \(\frac{1}{2} m n(m+1)(n+1)\) (C) \(m n(m+1)(n+1)\) (D) None of these
8 step solution
Problem 53
If three positive numbers \(a, b, c\) are in H.P., then \(a^{n}+c^{n}\) \((\mathrm{A})>2 b^{n}\) \((\mathrm{B})=2 b^{n}\) \((\mathrm{C})<2 b^{n}\) \((\mathrm{D})>b^{n}\)
5 step solution
Problem 54
The sum of first \(n\) terms of the series \(1 \cdot 1 !+2 \cdot 2 !+3 \cdot 3 !+4 \cdot 4 !+\ldots\) is (A) \((n+1) !-1\) (B) \(n !-1\) (C) \((n-1) !-1\) (D) None of these
5 step solution
Problem 55
If \(a, b, c\) are digits, then the rational number represented by \(0 \cdot c a b a b a b \ldots\) is (A) \(\frac{99 c+a b}{990}\) (B) \(\frac{99 c+10 a+b}{99}\) (C) \(\frac{99 c+10 a+b}{990}\) (D) None of these
5 step solution
Problem 56
The sum of first \(n\) terms of the series \(1^{2}+2.2^{2}+3^{2}+2.4^{2}+5^{2}+5.6^{2}+\ldots\) is \(\frac{n(n+1)^{2}}{2}\) when \(n\) is even. When \(n\) is odd, the sum is (A) \(\frac{n^{2}(n+1)}{2}\) (B) \(\frac{n(n+1)^{2}}{2}\) (C) \(\left[\frac{n(n+1)}{2}\right]^{2}\) (D) \(\frac{n(n+1)}{2}\)
6 step solution
Problem 57
The sum of the series \(1+2 \cdot 2+3 \cdot 2^{2}+4 \cdot 2^{3}+5 \cdot 2^{4}+\ldots+100 \cdot 2^{99}\) is (A) \(99 \cdot 2^{100}+1\) (B) \(100 \cdot 2^{100}\) (C) \(99 \cdot 2^{100}\) (D) \(99 \cdot 2^{100}+1\)
6 step solution
Problem 58
Four different integers form an increasing A.P. If one of these numbers is equal to the sum of the squares of the other three numbers, then the numbers are (A) \(-2,-1,0,1\) (B) \(0,1,2,3\) (C) \(-1,0,1,2\) (D) None of these
6 step solution
Problem 59
If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\Delta A B C\) and \([r]\) denotes greatest integer function, then \([r]+[-r]=\) (A) 0 (B) 1 (C) \(-1\) (D) None of these
5 step solution
Problem 60
Let \(S_{n}(1 \leq n \leq 9)\) denotes the sum of \(n\) terms of series \(1+22+333+\ldots+999999999\), then for \(2 \leq n \leq 9\) (A) \(S_{n}-S_{n-1}=\frac{1}{9}\left(10^{n}-n^{2}+n\right)\) (B) \(S_{n}=\frac{1}{9}\left(10^{n}-n^{2}+2 n-2\right)\) (C) \(9\left(S_{n}-S_{n-1}\right)=n\left(10^{n}-1\right)\) (D) None of these
4 step solution
Problem 61
\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\).
Then,
(A) \(x<-1\) or \(x>3\)
(B) \(-1
6 step solution