Problem 61
Question
\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\).
Then,
(A) \(x<-1\) or \(x>3\)
(B) \(-1
Step-by-Step Solution
Verified Answer
(A) \(x<-1\) or \(x>3\).
1Step 1: Understanding G.P.
Since \(a, b, c\) are in a geometric progression (G.P.), we can express them as \(a = ar^0 = a\), \(b = ar^1 = ar\), and \(c = ar^2\), where \(r\) is the common ratio. Given they are distinct, \(r eq 1\) and \(a eq 0\).
2Step 2: Set Up the Sum Equation
According to the problem, \(a + b + c = x b\). Substituting the G.P. terms, we have \(a + ar + ar^2 = x (ar)\). Simplifying, we obtain \(a(1 + r + r^2) = arx\).
3Step 3: Simplifying the Equation
Cancel out the \(a\) from both sides (assuming \(a eq 0\)), we get \(1 + r + r^2 = rx\). This results in the quadratic equation \(r^2 + r(1-x) + 1 = 0\).
4Step 4: Calculate the Discriminant
For the quadratic \(r^2 + (1-x)r + 1 = 0\) to have real roots, its discriminant must be non-negative. The discriminant is \((1-x)^2 - 4 \cdot 1 \cdot 1 = (1-x)^2 - 4\).
5Step 5: Solve the Discriminant Inequality
Set the discriminant \((1-x)^2 - 4 \geq 0\). Solving \((1-x)^2 \geq 4\) gives two cases: \(1-x \geq 2\) or \(1-x \leq -2\). This results in \(x \leq -1\) or \(x \geq 3\).
6Step 6: Final Inequality Condition
The inequality \(x \leq -1\) or \(x \geq 3\) implies that the permissible values of \(x\) satisfy either being less than or equal to -1 or greater than or equal to 3.
Key Concepts
Quadratic EquationDiscriminantReal Roots
Quadratic Equation
A quadratic equation is a type of polynomial equation of degree two. It is commonly written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are coefficients, and \(x\) represents the unknown variable.
The reason such equations are called "quadratic" is because "quad" represents "square", stemming from the squared term \(x^2\). Quadratic equations are used in various mathematical problems and applications, including physics and engineering, whenever the relationship between two variables is parabolic.
To solve a quadratic equation, one can use several methods:
The reason such equations are called "quadratic" is because "quad" represents "square", stemming from the squared term \(x^2\). Quadratic equations are used in various mathematical problems and applications, including physics and engineering, whenever the relationship between two variables is parabolic.
To solve a quadratic equation, one can use several methods:
- Factoring: Breaking down the quadratic into a product of two linear expressions, if possible.
- Using the Quadratic Formula: Utilizing the famous formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\), which provides solutions for any quadratic equation.
- Completing the Square: Rewriting the equation in a form that allows you to solve for \(x\) by taking the square root of both sides.
Discriminant
The discriminant is a critical component of a quadratic equation, represented by the expression \(b^2 - 4ac\). It is part of the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\), located under the square root.
The discriminant determines the nature and number of the roots of the quadratic equation:
The discriminant determines the nature and number of the roots of the quadratic equation:
- If the discriminant is positive, the quadratic equation has two distinct real roots.
- If the discriminant is zero, the equation has exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, no real roots exist; instead, there are two complex conjugate roots.
Real Roots
Real roots refer to the solutions of an equation that lie within the set of real numbers. For quadratic equations, the concept of real roots is intertwined with the discriminant.
As previously discussed, a quadratic equation can have two, one, or no real roots, depending on the value of its discriminant:
As previously discussed, a quadratic equation can have two, one, or no real roots, depending on the value of its discriminant:
- Two distinct real roots when \(b^2 - 4ac > 0\).
- A single real root when \(b^2 - 4ac = 0\).
- No real roots when \(b^2 - 4ac < 0\), as the solutions involve imaginary numbers.
Other exercises in this chapter
Problem 59
If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\Delta A B C\) and \([r]\) denotes greatest integer function, then \([r]+
View solution Problem 60
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View solution Problem 62
If \(a_{1}, a_{2}, a_{3}, a_{4}\) are in H.P., then \(\frac{1}{a_{1} a_{4}} \sum_{r=1}^{3} a_{r} a_{r+1}\) is a root of (A) \(x^{2}+2 x+15=0\) (B) \(x^{2}+2 x-1
View solution Problem 63
The sum to \(n\) terms of the series \(\frac{1}{3}+\frac{5}{9}+\frac{19}{27}+\frac{65}{81}+\ldots\) is (A) \(n-\frac{\left(3^{n}-2^{n}\right)}{2^{n}}\) (B) \(n-
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