Chapter 9

Advanced Engineering Mathematics · 776 exercises

Problem 41

The temperature at a point \((x, y)\) on a rectangular metal plate is given by \(T(x, y)=100-2 x^{2}-y^{2}\). Find the path a heatseeking particle will take, starting at \((3,4)\), as it moves in the direction in which the temperature increases most rapidly.

6 step solution

Problem 41

Convert the point given in rectangular cocrdinates to cylindrical coondinates. $$ (-\sqrt{2}, \sqrt{6}, 2) $$

5 step solution

Problem 41

Assume that \(f\) and \(g\) have continuous second partial derivatives. Show that the given vector field is solenoidal. $$ \mathbf{F}=\nabla f \times \nabla g $$

4 step solution

Problem 41

Find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=a \cos t \mathbf{i}+a \sin t \mathbf{j}+c t \mathbf{k} ; 0 \leq t \leq 2 \pi $$

5 step solution

Problem 42

In Problems \(39-42\), convert the point given in rectangular coardinates to cylindrical coordinates. $$ (1,2,7) $$

4 step solution

Problem 42

Find the center of mass of the lamina that has the given shape and density. $$ x=0, y=0,2 x+y=4 ; \rho(x, y)=x^{2} $$

7 step solution

Problem 42

In Problems, find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=t \mathbf{i}+t \cos t \mathbf{j}+t \sin t \mathbf{k} ; 0 \leq t \leq \pi $$

6 step solution

Problem 42

Use the Chain Rule to find the indicated partial derivatives. $$ z=\frac{x-y}{x+y} ; x=\frac{u}{v}, y=\frac{v^{2}}{u} ; \frac{\partial z}{\partial u}, \frac{\partial z}{\partial v} $$

7 step solution

Problem 42

The temperature \(T\) at a point \((x, y, z)\) in space is inversely proportional to the square of the distance from \((x, y, z)\) to the origin. It is known that \(T(0,0,1)=500\). Find the rate of change of \(T\) at \((2,3,3)\) in the direction of \((3,1,1)\). In which direction from \((2,3,3)\) does the temperature \(T\) increase most rapidly? At \((2,3,3)\) what is the maximum rate of change of \(T ?\)

7 step solution

Problem 42

Convert the point given in rectangular cocrdinates to cylindrical coondinates. $$ (1,2,7) $$

5 step solution

Problem 42

Assume that \(f\) and \(g\) have continuous second partial derivatives. Show that the given vector field is solenoidal. $$ \mathbf{F}=\nabla f \times(f \nabla g) $$

6 step solution

Problem 42

Find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=t \mathbf{i}+t \cos t \mathbf{j}+t \sin t \mathbf{k} ; 0 \leq t \leq \pi $$

6 step solution

Problem 43

In Problems \(43-46\), convert the given equation to cylindrical coardinates. $$ x^{2}+y^{2}+z^{2}=25 $$

4 step solution

Problem 43

Find the center of mass of the lamina that has the given shape and density. $$ y=x, x+y=6, y=0 ; \rho(x, y)=2 y $$

9 step solution

Problem 43

In Problems, find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=e^{t} \cos 2 t \mathbf{i}+e^{t} \sin 2 t \mathbf{j}+e^{t} \mathbf{k} ; 0 \leq t \leq 3 \pi $$

6 step solution

Problem 43

Use the Chain Rule to find the indicated partial derivatives. $$ w=\left(u^{2}+v^{2}\right)^{3 / 2} ; u=e^{-t} \sin \theta, v=e^{-t} \cos \theta ; \frac{\partial w}{\partial t}, \frac{\partial w}{\partial \theta} $$

5 step solution

Problem 43

Find a function \(f\) such that $$ \nabla f=\left(3 x^{2}+y^{3}+y e^{x}\right) \mathbf{i}+\left(-2 y^{2}+3 x y^{2}+x e^{x}\right) \mathbf{j} $$

7 step solution

Problem 43

Conven the given equation to cylindrical codrdinates. $$ x^{2}+y^{2}+z^{2}=25 $$

3 step solution

Problem 43

Find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=e^{t} \cos 2 t \mathbf{i}+e^{t} \sin 2 t \mathbf{j}+e^{t} \mathbf{k} ; 0 \leq t \leq 3 \pi $$

5 step solution

Problem 44

In Problems, find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=3 t \mathbf{i}+\sqrt{3} t^{2} \mathbf{j}+\frac{2}{3} t^{3} \mathbf{k} ; 0 \leq t \leq 1 $$

5 step solution

Problem 44

Use the Chain Rule to find the indicated partial derivatives. $$ w=\tan ^{-1} \sqrt{u v} ; u=r^{2}-s^{2}, v=r^{2} s^{2} ; \frac{\partial w}{\partial r}, \frac{\partial w}{\partial s} $$

6 step solution

Problem 44

Let \(f_{x}, f_{y}, f_{x y}, f_{y x}\) be continuous and \(\mathbf{u}\) and \(\mathbf{v}\) be unit vectors. Show that \(D_{\mathrm{u}} D_{\mathrm{v}} f=D_{\mathrm{v}} D_{\mathrm{u}} f\)

6 step solution

Problem 44

Find the length of the curve traced by the given vector function on the indicated interval. $$ \mathbf{r}(t)=3 t \mathbf{i}+\sqrt{3} t^{2} \mathbf{j}+\frac{2}{3} t^{3} \mathbf{k} ; 0 \leq t \leq 1 $$

3 step solution

Problem 45

In Problems \(43-46\), convert the given equation to cylindrical coardinates. $$ x^{2}+y^{2}-z^{2}=1 $$

4 step solution

Problem 45

Find the center of mass of the lamina that has the given shape and density. $$ y=x^{2}, x=1, y=0 ; \rho(x, y)=x+y $$

8 step solution

Problem 45

Consider the vector field \(\mathbf{F}=x^{2} y z \mathbf{i}-x y^{2} z \mathbf{j}+(z+5 x) \mathbf{k}\) Explain why \(\mathbf{F}\) is not the curl of another vector field \(\mathbf{G}\).

7 step solution

Problem 45

Use the Chain Rule to find the indicated partial derivatives. $$ R=r s^{2} t^{4} ; r=u e^{v^{2}}, s=v e^{-u^{2}}, t=e^{u^{2} v^{2}} ; \frac{\partial R}{\partial u}, \frac{\partial R}{\partial v} $$

6 step solution

Problem 45

Conven the given equation to cylindrical codrdinates. $$ x^{2}+y^{2}-z^{2}=1 $$

3 step solution

Problem 45

Express the vector equation of a circle \(\mathbf{r}(t)=a \cos t \mathbf{i}+\) \(a \sin t \mathbf{j}\) as a function of arc length \(s\). Verify that \(\mathbf{r}^{\prime}(s)\) is a unit vector.

6 step solution

Problem 46

In Problems \(43-46\), convert the given equation to cylindrical coardinates. $$ x^{2}+z^{2}=16 $$

4 step solution

Problem 46

Find the center of mass of the lamina that has the given shape and density. $$ x=y^{2}, x=4 ; \rho(x, y)=y+5 $$

9 step solution

Problem 46

Use the Chain Rule to find the indicated partial derivatives. $$ Q=\ln (p q r) ; p=t^{2} \sin ^{-1} x, q=\frac{x}{t^{2}}, r=\tan ^{-1} \frac{x}{t} ; \frac{\partial Q}{\partial x}, \frac{\partial Q}{\partial t} $$

3 step solution

Problem 46

In Problems, assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla(f+g)=\nabla f+\nabla g $$

6 step solution

Problem 46

Conven the given equation to cylindrical codrdinates. $$ x^{2}+z^{2}=16 $$

5 step solution

Problem 46

Assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla(f+g)=\nabla f+\nabla g $$

6 step solution

Problem 47

Find the center of mass of the lamina that has the given shape and density. \(y=1-x^{2}, y=0 ;\) density at a point \(P\) directly proportional to the distance from the \(x\) -axis

6 step solution

Problem 47

Suppose \(\mathbf{r}\) is a differentiable vector function for which \(\|\mathbf{r}(t)\|=c\) for all \(t\). Show that the tangent vector \(\mathbf{r}^{\prime}(t)\) is perpendicular to the position vector \(\mathbf{r}(t)\) for all \(t\).

5 step solution

Problem 47

Use the Chain Rule to find the indicated partial derivatives. $$ \begin{aligned} &w=\sqrt{x^{2}+y^{2}} ; x=\ln (r s+t u) \\ &y=\frac{t}{u} \cosh r s ; \frac{\partial w}{\partial t}, \frac{\partial w}{\partial r}, \frac{\partial w}{\partial u} \end{aligned} $$

6 step solution

Problem 47

In Problems, assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla(f g)=f \nabla g+g \nabla f $$

6 step solution

Problem 47

Assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla(f g)=f \nabla g+g \nabla f $$

7 step solution

Problem 48

In Problems \(47-50\), convert the given equation to rectangular coardinates. $$ z=2 r \sin \theta $$

4 step solution

Problem 48

Find the center of mass of the lamina that has the given shape and density. \(y=1-x^{2}, y=0 ;\) density at a point \(P\) directly proportional to the distance from the \(x\) -axis

8 step solution

Problem 48

Use the Chain Rule to find the indicated partial derivatives. $$ \begin{aligned} &s=p^{2}+q^{2}-r^{2}+4 t ; p=\phi e^{3 \theta}, q=\cos (\phi+\theta), r=\phi \theta^{2}, \\ &t=2 \phi+8 \theta ; \frac{\partial s}{\partial \phi^{\prime}}, \frac{\partial s}{\partial \theta} \end{aligned} $$

10 step solution

Problem 48

In Problems, assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla\left(\frac{f}{g}\right)=\frac{g \nabla f-f \nabla g}{g^{2}} $$

4 step solution

Problem 48

Assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla\left(\frac{f}{g}\right)=\frac{g \nabla f-f \nabla g}{g^{2}} $$

5 step solution

Problem 49

In Problems \(47-50\), convert the given equation to rectangular coardinates. $$ r=5 \sec \theta $$

7 step solution

Problem 49

Find the center of mass of the lamina that has the given shape and density. $$ y=e^{x}, x=0, x=1, y=0 ; \rho(x, y)=y^{3} $$

6 step solution

Problem 49

Use (8) to find the indicated derivative. $$ z=\ln \left(u^{2}+v^{2}\right) ; u=t^{2}, v=t^{-2} ; \frac{d z}{d t} $$

6 step solution

Problem 49

If \(\mathbf{F}(x, y, z)=f_{1}(x, y, z) \mathbf{i}+f_{2}(x, y, z) \mathbf{j}+f_{3}(x, y, z) \mathbf{k}\) and \(\nabla=\mathbf{i} \frac{\partial}{\partial x}+\mathbf{j} \frac{\partial}{\partial y}+\mathbf{k} \frac{\partial}{\partial z}\) show that \(\nabla \times \mathbf{F}=\left(\frac{\partial f_{3}}{\partial y}-\frac{\partial f_{2}}{\partial z}\right) \mathbf{i}+\left(\frac{\partial f_{1}}{\partial z}-\frac{\partial f_{3}}{\partial x}\right) \mathbf{j}+\left(\frac{\partial f_{2}}{\partial x}-\frac{\partial f_{1}}{\partial y}\right) \mathbf{k} .\)

5 step solution

Problem 49

Convert the given equation to rectangular cocrdinates. $$ r=5 \sec \theta $$

5 step solution

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