Problem 47
Question
In Problems, assume that \(f\) and \(g\) are differentiable functions of two variables. Prove the given identity. $$ \nabla(f g)=f \nabla g+g \nabla f $$
Step-by-Step Solution
Verified Answer
The given identity is proven by applying the product rule for derivatives to the gradient of the product \(f g\).
1Step 1: Understand the Given Expression
The expression \( abla (f g) \) represents the gradient of the product of two functions \( f \) and \( g \). Our goal is to show that this gradient equals \( f abla g + g abla f \). The gradient, \( abla \), is a vector of partial derivatives.
2Step 2: Recall the Gradient Formula
The gradient of a function \( h \) of two variables \( x \) and \( y \) is given by \( abla h = \left( \frac{\partial h}{\partial x}, \frac{\partial h}{\partial y} \right) \). We will apply this to the product \( f g \).
3Step 3: Apply the Product Rule for Partial Derivatives
The derivative for products of functions follows the product rule. So, for \( \frac{\partial}{\partial x}(f g) \) we have:\[ \frac{\partial}{\partial x}(fg) = f \frac{\partial g}{\partial x} + g \frac{\partial f}{\partial x} \]This is because we applied the product rule individually to each partial derivative.
4Step 4: Determine the Full Gradient
Similarly, applying the product rule to \( \frac{\partial}{\partial y}(f g) \) gives:\[ \frac{\partial}{\partial y}(fg) = f \frac{\partial g}{\partial y} + g \frac{\partial f}{\partial y} \]So the gradient is:\[ abla(fg) = \left( f \frac{\partial g}{\partial x} + g \frac{\partial f}{\partial x}, f \frac{\partial g}{\partial y} + g \frac{\partial f}{\partial y} \right) \]
5Step 5: Connect to the Right-Hand Side of the Identity
The gradient \( abla g \) is \( \left( \frac{\partial g}{\partial x}, \frac{\partial g}{\partial y} \right) \) and the gradient \( abla f \) is \( \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \). Then:\[ f abla g = \left( f \frac{\partial g}{\partial x}, f \frac{\partial g}{\partial y} \right) \]\[ g abla f = \left( g \frac{\partial f}{\partial x}, g \frac{\partial f}{\partial y} \right) \]Adding these vectors gives us:\[ f abla g + g abla f = \left( f \frac{\partial g}{\partial x} + g \frac{\partial f}{\partial x}, f \frac{\partial g}{\partial y} + g \frac{\partial f}{\partial y} \right) \]
6Step 6: Conclude the Proof
Since both sides of the identity \( abla(fg) = f abla g + g abla f \) result in the same vector, the proof is complete. This demonstrates that the gradient of a product of functions can be expressed as a sum of gradients, each scaled by the other function.
Key Concepts
GradientProduct RulePartial Derivatives
Gradient
In vector calculus, the gradient is an essential concept that helps us understand how multi-variable functions change in space. The gradient of a function, denoted as \( abla \), provides a vector field containing the partial derivatives of the function with respect to its variables. This vector points in the direction of the greatest rate of increase of the function and its magnitude is the rate of increase in that direction.
For example, given a function \( f(x, y) \), its gradient is expressed as:
For example, given a function \( f(x, y) \), its gradient is expressed as:
- \( abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \)
Product Rule
The product rule is a cornerstone of calculus that comes into play when differentiating products of two functions. When it comes to partial derivatives with multiple variables, this rule is very handy and often essential.
Let's say we want to differentiate the product of two functions, \( u(x, y) \) and \( v(x, y) \), with respect to \( x \). The product rule states:
In the context of gradients, the product rule similarly extends to both variables when calculating both \( \partial / \partial x \) and \( \partial / \partial y \). This is why the formula for the gradient of a product \( abla(fg) = f abla g + g abla f \) holds true.
Let's say we want to differentiate the product of two functions, \( u(x, y) \) and \( v(x, y) \), with respect to \( x \). The product rule states:
- \( \frac{\partial}{\partial x}(uv) = u \frac{\partial v}{\partial x} + v \frac{\partial u}{\partial x} \)
In the context of gradients, the product rule similarly extends to both variables when calculating both \( \partial / \partial x \) and \( \partial / \partial y \). This is why the formula for the gradient of a product \( abla(fg) = f abla g + g abla f \) holds true.
Partial Derivatives
A partial derivative is a derivative where we keep all but one of the variables constant. It captures the rate of change of a multi-variable function with respect to one variable, while maintaining the others as constants. This is a critical aspect of vector calculus, as most functions in this realm depend on multiple variables.
Here's an example for function \( f(x, y) \):
Working with partial derivatives is crucial when proving identities or theorems in vector calculus, as they form the backbone of every derivative operation when multiple variables are involved.
Here's an example for function \( f(x, y) \):
- \( \frac{\partial f}{\partial x} \) means we differentiate \( f \) considering \( x \) as a variable and \( y \) as a constant.
- \( \frac{\partial f}{\partial y} \) reverses the role, keeping \( x \) constant.
Working with partial derivatives is crucial when proving identities or theorems in vector calculus, as they form the backbone of every derivative operation when multiple variables are involved.
Other exercises in this chapter
Problem 47
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