Problem 49
Question
Convert the given equation to rectangular cocrdinates. $$ r=5 \sec \theta $$
Step-by-Step Solution
Verified Answer
The rectangular coordinate equation is \( x = 5 \).
1Step 1: Understand Polar Coordinates Terminology
The equation is in polar coordinates, which typically involve the variables \( r \) and \( \theta \). Here, \( r \) is the distance from the origin and \( \theta \) is the angle from the positive x-axis. The given equation is \( r = 5 \sec \theta \).
2Step 2: Express \( \sec \theta \) in terms of Trigonometric Identity
Recall that \( \sec \theta = \frac{1}{\cos \theta} \). Substituting this in the equation gives us \( r = \frac{5}{\cos \theta} \).
3Step 3: Rewrite \( r \) in Terms of \( x \, \text{and} \, y \)
In polar to rectangular conversion, \( x = r \cos \theta \) and \( y = r \sin \theta \). Since \( \cos \theta = \frac{x}{r} \), we substitute it in our equation: \( r = \frac{5}{\frac{x}{r}} = \frac{5r}{x} \).
4Step 4: Solve for \( x \) in Terms of \( r \)
After simplifying \( r = \frac{5r}{x} \), we can multiply both sides by \( x \) to get \( x = 5 \).
5Step 5: Conversion Verification
Check if \( x = 5 \) is consistent with the polar form by substituting into the equations \( x = r \cos \theta \): \( 5 = r \cos \theta \). Given \( r = 5 \sec \theta \) implies \( r \cos \theta = 5 \), confirms that \( x = 5 \) is correct.
Key Concepts
Polar CoordinatesRectangular CoordinatesTrigonometric Identities
Polar Coordinates
Polar coordinates provide a unique system for locating points on a plane using the radius and angle. This system is particularly useful when dealing with circular or rotational systems.
In polar coordinates:
In polar coordinates:
- \( r \) represents the radial distance from the origin (or the center of the circle).
- \( \theta \) (theta) is the angle made with the positive x-axis.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, represent points on a plane using two perpendicular axes—horizontal (x-axis) and vertical (y-axis).
In rectangular coordinates:
This exercise emphasizes the simplicity of such conversions once you know \( r \) and \( \theta \) and need an equivalent \( x, y \) description. The polar equation \( r = 5 \sec \theta \) converts neatly to \( x = 5 \), a line parallel to the y-axis.
In rectangular coordinates:
- \( x \) describes the horizontal distance from the origin.
- \( y \) describes the vertical distance from the origin.
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
This exercise emphasizes the simplicity of such conversions once you know \( r \) and \( \theta \) and need an equivalent \( x, y \) description. The polar equation \( r = 5 \sec \theta \) converts neatly to \( x = 5 \), a line parallel to the y-axis.
Trigonometric Identities
Trigonometric identities are mathematical relationships expressing the connections between various trigonometric functions like sine, cosine, and tangent and their reciprocals—cosecant, secant, and cotangent.
A key identity in this exercise is the secant function:
Understanding these connections allows us to replace \( \sec \theta \) with expressions involving \( \cos \theta \), facilitating the shift from polar to rectangular equations. The expression \( r = \frac{5}{\cos \theta} \) aids in determining the rectangular coordinate by letting \( x = 5 \), as shown by solving \( r \cos \theta = 5 \).
Trigonometric identities not only support conversions but also streamline solving problems across different coordinate systems, making them indispensable tools in mathematics.
A key identity in this exercise is the secant function:
- \( \sec \theta = \frac{1}{\cos \theta} \)
Understanding these connections allows us to replace \( \sec \theta \) with expressions involving \( \cos \theta \), facilitating the shift from polar to rectangular equations. The expression \( r = \frac{5}{\cos \theta} \) aids in determining the rectangular coordinate by letting \( x = 5 \), as shown by solving \( r \cos \theta = 5 \).
Trigonometric identities not only support conversions but also streamline solving problems across different coordinate systems, making them indispensable tools in mathematics.
Other exercises in this chapter
Problem 49
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