Benzene and Aromaticity

Organic Chemistry (Mcmurry) ยท 66 exercises

Q 15-15-18 E-e


Give IUPAC names for the following compounds

e) 



3 step solution

Q15-1P


Tell whether the following compounds are ortho-, meta-, or para-disubstituted:



4 step solution

Q15-2P


Give IUPAC names for the following compounds:



7 step solution

Q15-3P

Draw structures corresponding to the following IUPAC names: 

(a) p-Bromochlorobenzene 

(b) p-Bromotoluene 

(c) m-Chloroaniline 

(d) 1-Chloro-3,5-dimethylbenzene

6 step solution

Q15-4P


Pyridine is a flat, hexagonal molecule with bond angles of 120°. It undergoes substitution rather than addition and generally behaves like benzene. Draw a picture of the orbitals of pyridine to explain its properties. Check your answer by looking ahead to Sections 15-5.


3 step solution

Q15-5P


To be aromatic, a molecule must have 4n+2 p electrons and must have a planar, monocyclic system of conjugation. Cyclodecapentaene fulfills one of these criteria but not the other and has resisted all attempts at synthesis. Explain.


2 step solution

Q6P

Draw the five resonance structures of the cyclopentadienyl anion. are all carbon-carbon bonds equivalent? How many absorption lines would you expect to see in the 1HNMR and 13CNMR spectra of the anion?


4 step solution

Q15-7P


 Cyclooctatetraene readily reacts with potassium metal to form the stable cyclooctatetraene dianion, C8H82-. Why do you suppose this reaction occurs so easily? What geometry do you expect for the cyclooctatetraene dianion?


3 step solution

Q15-8P

The relative energy levels of the five molecular orbitals of the cyclopentadienyl system are similar to those in benzene. That is, there is a single lowest energy MO, above which the orbitals come in degenerate pairs. Draw a diagram like that in Figure 15-5, and tell which of the five orbitals are occupied in the cation, radical, and anion.


4 step solution

Q9P


Draw an orbital picture of furan to show how the molecule is aromatic.




3 step solution

Q15-10P


Thiamin, or vitamin B1, contains a positively charged five-membered nitrogen–sulfur heterocycle called a thiazolium ring. Explain why the thiazolium ring is aromatic.



3 step solution

Q15-11P


Azulene, a beautiful blue hydrocarbon, is an isomer of naphthalene. Is azulene aromatic? Draw a second resonance form of azulene in addition to that shown.


4 step solution

Q15-12P

How many electrons does each of the four nitrogen atoms in purine contribute to the aromatic system?


3 step solution

Q15-15-33E

Which would you expect to be most stable, Cyclononatetraenyl radical, cation, or anion?

2 step solution

Q15-15-32E


Cycloheptatrienone is stable, but cyclopentadienone is so reactive that it can’t be isolated. Explain, taking the polarity of the carbonyl group into account.



Cycloheptatrienone                                                Cyclopentadienone

2 step solution

Q15-15-31E


Cyclopropane is highly reactive because of its large amount of angle strain. Methylcyclopropenone, although even more strained than cyclopropanone, is nevertheless quite stable and can even be distilled. Explain, taking the polarity of the carbonyl group into account.



Cyclopropanone                                           Methylcyclopropenone

2 step solution

Q15-15-30E

Draw an energy diagram for the three molecular orbitals of the cyclopropenyl system  (C3H3). How are these three molecular orbitals occupied in the cyclopropenyl anion, cation, and radical? Which of the three substances is aromatic according to Hückel’s rule?

2 step solution

Q15EP

Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine

(b) 1,3,5-Benzenetriol  

(c) 3-Methyl-2-phenylhexane 

(d) o-Aminobenzoic acid  

(e) m-Bromophenol  

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

Q15FP

Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine 

(b) 1,3,5-Benzenetriol 

(c) 3-Methyl-2-phenylhexane  

(d) o-Aminobenzoic acid 

(e) m-Bromophenol 

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

Q15-15-29E


3-Chlorocyclopropene, on treatment with AgBF4, gives a precipitate of AgCl and a stable solution of a product that shows a single  1HNMR absorption at 11.04 d. What is a likely structure for the product, and what is its relation to Hückel’s rule?



       3-Chlorocyclopropene


2 step solution

Q15-15-28


In 1932, A. A. Levine and A. G. Cole studied the ozonolysis of o-xylene and isolated three products: glyoxal, 2,3-butanedione, and pyruvaldehyde:



In what ratio would you expect the three products to be formed if o-xylene is a resonance hybrid of two structures? The actual ratio found was 3 parts glyoxal, 1 part 2,3-butanedione, and 2 parts pyruvaldehyde. What conclusions can you draw about the structure of o-xylene?

2 step solution

Q15-15-27

Look at the five resonance structures for phenanthrene (Problem 15-26), and predict which of its carbon-carbon bonds is the shortest.

2 step solution

Q15-15-26E

Phenanthrene has five resonance structures, one of which is shown. Draw the other four.

2 step solution

Q15-15-25E


Anthracene has four resonance structures, one of which is shown. Draw the other three



                                               Anthracene

2 step solution

Q15-15-24

Look at the three resonance structures of naphthalene shown in Section 15-6, and account for the fact that not all carbon-carbon bonds have the same length. The C1–C2 bond is 136 pm long, whereas the C2–C3 bond is 139 pm long

2 step solution

Q15-15-23E

Propose structures for aromatic hydrocarbons that meet the following descriptions:

 (a) C9H12; gives only one C9H11Br product on substitution of hydrogen on the aromatic ring with bromine 

(b)C10 H14 ; gives only one C10H13Cl product on substitution of hydrogen on the aromatic ring with chlorine 

(c) C8H10; gives three C8H9Br  products on substitution of hydrogen on the aromatic ring with bromine 

(d)C10 H14  ; gives two C10H13Cl products on substitution of hydrogen on the aromatic ring with chlorine

8 step solution

Q15-34E

How might you convert 1, 3, 5, 7-cyclononatetraene to an aromatic substance?


2 step solution

Q15-35E


Calicene, like azulene (Problem 15-17), has an unusually large dipole moment for a hydrocarbon. Explain, using resonance structures.




Calicene

3 step solution

Q15-36E



Pentalene is a most elusive molecule that has been isolated only at liquid-nitrogen temperature. The pentalene dianion, however, is well known and quite stable. Explain.




Pentalene




Pentalene dianion

2 step solution

Q15-37E


Indole is an aromatic heterocycle that has a benzene ring fused to a pyrrole ring. Draw an orbital picture of indole.

 (a) How many p electrons does indole have?

 (b) What is the electronic relationship of indole to naphthalene?




Indole

5 step solution

Q15-38E


Ribavirin, an antiviral agent used against hepatitis C and viral pneumonia, contains a 1,2,4-triazole ring. Why is the ring aromatic?



Ribavirin

2 step solution

Q15-39E

Compound A, C8H10 , yields three substitution products, C8H9Br, on reaction with Br2. Propose two possible structures for A. The 1HNMR spectrum of A shows a complex four-proton multiplet at 7.0 d and a six-proton singlet at 2.30 d. What is the structure of A?

2 step solution

Q15-40E

What is the structure of a hydrocarbon that has M+=120 in its mass spectrum and has the following 1HNMR spectrum? 7.25 d (5 H, broad singlet); 2.90 d (1 H, septet, J 5 7 Hz); 1.22 d (6 H, doublet, J 5 7 Hz).

2 step solution

Q15-13E


Give IUPAC names for the following substances (red 5 O, blue 5 N):



4 step solution

Q15-14E


All-cis cyclodecapentaene is a stable molecule that shows a single absorption in its NMR spectrum at 5.67δ. Tell whether it is aromatic, and explain its NMR spectrum.


3 step solution

Q15-15E


1,6-Methanonaphthalene has an interesting 1H NMR spectrum in which the eight hydrogens around the perimeter absorb at 6.9 to 7.3 d, while the two protons absorb at 20.5δ. Tell whether it is aromatic, and explain its NMR spectrum.


4 step solution

Q15-52E

The substitution reaction of toluene with Br2 can, in principle, lead to the formation of three isomeric Bromo toluene products. In practice, however, only o- and p-Bromo toluene are formed in substantial amounts. The meta isomer is not formed. Draw the structures of the three possible carbocation intermediates (Problem 15-51), and explain why ortho and para products predominate over meta products.

3 step solution

Q15-53E


Draw all of the resonance forms for each. What patterns emerge?



3 step solution

Q15-54E


After the reaction below, the chemical shift ofHamoves downfield from 6.98 ppm to 7.30 ppm. Explain.



2 step solution

Q15-55E


The compound below is the product initially formed in a Claisen rearrangement (Section 18-4). This product is not isolated but tautomerizes to its enol form. Give the structure of the enol and provide an explanation as to why the enol tautomer is favored.


2 step solution

Q 15-15-18 E-a


Give IUPAC names for the following compounds

a) 


3 step solution

Q 15-15-18 E-b


Give IUPAC names for the following compounds

b)



3 step solution

Q 15-15-18 E-c


Give IUPAC names for the following compounds

c) 


3 step solution

Q 15-15-18 E-d


Give IUPAC names for the following compounds

d) 


3 step solution

Q 15-15-18 E-f


Give IUPAC names for the following compounds

f) 


3 step solution

Q.15CP

Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine 

(b) 1,3,5-Benzenetriol 

(c) 3-Methyl-2-phenylhexane 

(d) o-Aminobenzoic acid 

(e) m-Bromophenol 

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

Q.15DP

Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine 

(b) 1,3,5-Benzenetriol

(c) 3-Methyl-2-phenylhexane 

(d) o-Aminobenzoic acid 

(e) m-Bromophenol  

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

Q16E


The following molecular model is that of a carbocation. Draw two resonance structures for the carbocation, indicating the positions of the double bonds.




2 step solution

Q17E


Azulene, an isomer of naphthalene, has a remarkably large dipole moment for a hydrocarbon (μ=5 1.0 D). Explain, using resonance structures.



2 step solution

Q.19 E-a

Draw structures corresponding to the following names:

 (a) 3-Methyl-1,2-benzenediamine 

(b) 1,3,5-Benzenetriol 

(c) 3-Methyl-2-phenylhexane 

(d) o-Aminobenzoic acid 

(e) m-Bromophenol 

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

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