Benzene and Aromaticity

Organic Chemistry (Mcmurry) ยท 66 exercises

Q.19 E-b

Draw structures corresponding to the following names:

(a) 3-Methyl-1,2-benzenediamine 

(b) 1,3,5-Benzenetriol 

(c) 3-Methyl-2-phenylhexane 

(d) o-Aminobenzoic acid

(e) m-Bromophenol 

(f) 2,4,6-Trinitrophenol (picric acid)

2 step solution

Q20AP

Draw and name all possible isomers of the following: 

  1. Dinitrobenzene
  2. Bromo dimethyl benzene 
  3. Trinitrophenol

6 step solution

Q21P

Draw and name all possible aromatic compounds with the formula C7H7Cl.

2 step solution

Q22P

Draw and name all possible aromatic compounds with the formula C8H9Br.

2 step solution

Q41E

Propose structures for compounds that fit the following descriptions:

 (a) C10H14  1HNMR: 7.18δ (4 H, broad singlet); 2.70δ(4 H, quartet, J = 7 Hz);  1.20δ(6 H, triplet, J =7 Hz) IR:745cm-1 .


(b)C10H14 1HNMR:  7.0δ (4 H, broad singlet); 2.85  δ (1 H, septet, J = 8 Hz); 2.28  δ(3 H, singlet);  1.20  δ(6 H, doublet, J = 8 Hz) IR:825cm-1 .


3 step solution

Q42E


On reaction with acid, 4-pyrone is protonated on the carbonyl-group oxygen to give a stable cationic product. Using resonance structures and the Hückel’s 4n+2 rule, explain why the protonated product is so stable.



4-Pyrone

2 step solution

Q43E


Bextra, a COX-2 inhibitor once used in the treatment of arthritis, contains an isoxazole ring. Why is the ring aromatic?




Bextra

2 step solution

Q44E


N-Phenylsydnone, so-named because it was first studied at the University of Sydney, Australia, behaves like a typical aromatic molecule. Explain, using the Hückel’s 4n+2  rule .



N-phenylsydnone

2 step solution

Q45E


Show the relative energy levels of the seven p molecular orbitals of the cycloheptatrienyl system. Tell which of the seven orbitals are filled in the cation, radical, and anion, and account for the aromaticity of the cycloheptatrienyl cation.


2 step solution

Q46E

1-Phenyl-2-butene has an ultraviolet absorption λmax=208nm  ( ε=8000). On treatment with a small amount of strong acid, isomerization occurs and a new substance with λmax=250nm (ε=15,8000) is formed. Propose a structure for this isomer, and suggest a mechanism for its formation.

2 step solution

Q47E




    7 Propose structures for aromatic compounds that have the following 1HNMR spectra:

 (a)  C8H9Br IR=820cm-1




b) C9H12  IR:750cm-1


 



c)  C11H16  IR:820cm-1




4 step solution

Q48E


Propose a structure for a molecule C14H12 that has the following 1H NMR spectrum and has IR absorptions at 700, 740, and 890cm-1 :




2 step solution

Q49E



The proton NMR spectrum for a compound with formula C10H12O2  is shown below. The infrared spectrum has a strong band at 1711cm-1 . The normal carbon-13 NMR spectral results are tabulated along with the DEPT-135 and DEPT-90 information. Draw the structure of this compound. 






2 step solution

Q50E



The proton NMR spectrum of a compound with formula C6H5NCl2  is shown. The normal carbon-13 and DEPT experimental results are tabulated. The infrared spectrum shows peaks at 3432 and 3313cm-1 and a series of medium-sized peaks between 1618 and 1466cm-1 . Draw the structure of this compound.







2 step solution

Q51E

Aromatic substitution reactions occur by the addition of an electrophile such as Br+  to an aromatic ring to yield an allylic carbocation intermediate, followed by loss of H+. Show the structure of the intermediate formed by the reaction of benzene with Br+ .

2 step solution

Q 56E

Azo dyes are the major source of artificial color in textiles and food. Part of the reason for their intense coloring is the conjugation from an electron-donating group through the diazo bridge (-N=N-) to an electron-withdrawing group on the other side. For the azo dyes below, draw a resonance form that shows how the electron-donating group is related to the electron-withdrawing group on the other side of the diazo bridge. Used curved arrows to show how the electrons are reorganized.


a.

Methyl orange



b.

C.I. Acid Red 74


2 step solution

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