Q40.

Question

Question: Find the vertex, the equation of the axis of symmetry, and the y-intercept of the given equation.


y=2x212x+6

Step-by-Step Solution

Verified
Answer

The vertex is 3,33, the equation of the axis of symmetry is x=3 and the y-intercept is 6.

1Step 1. Define the standard form of the quadratic function.

A quadratic function, which is written in the form, y=ax2+bx+c, where, a0 is called the standard form of the quadratic function.

2Step 2. Define the vertex of the function y = a x 2 + b x + c .

For the function y=ax2+bx+c

(1) If a>0, then the function has the minimum value at x=b2a and the vertex is located at the minimum point.

(2) If a<0, then the function has the maximum value at x=b2a and the vertex is located at the maximum point.

3Step 3. Write the axis of symmetry for the function y = a x 2 + b x + c .

The axis of symmetry for the function y=ax2+bx+c is

x=b2a

4Step 4. Define y -intercept of the function y = a x 2 + b x + c .

The y-intercept of the function y=ax2+bx+c is always at c.

5Step 5. Calculate the vertex, the equation of the axis of symmetry, and the y -intercept of the function y = 2 x 2 &#8722; 12 x + 6 .

Compare the quadratic function y=2x212x+6 with the standard quadratic function y=ax2+bx+c.

a=2,b=12,c=6

Substitute a=2 and b=12 in x=b2a.

x=1222x=124x=3x=3

So, the axis of symmetry is given by

x=3

Since, a>0.

So, the function has a minimum value at x=3.

Substitute x=3 in y=2x212x+6.

y=732123+6y=7936+6y=6336+6y=6936y=33

So, the vertex point is located at the point 3,33.

Since, the y-intercept is given by c.

So, the y-intercept is 6. 

 

Therefore the vertex is 3,33, the equation of the axis of symmetry is x=3 and the y-intercept is 6.