Q38.

Question

Find the vertex, the equation of the axis of symmetry, and the y-intercept of the given equation.

y=5x2+20x+10

Step-by-Step Solution

Verified
Answer

The vertex is 2,10, the equation of the axis of symmetry is x=2 and the y-intercept is 10.

1Step 1. Define the standard form of the quadratic function.

A quadratic function, which is written in the form, y=ax2+bx+c, where a0, is called the standard form of the quadratic function.

2Step 2. Define the vertex of the function y = a x 2 + b x + c .

For the function y=ax2+bx+c,

(1) If a>0, then the function has the minimum value at x=b2a and the vertex is located at the minimum point.

(2) If a<0, then the function has the maximum value at x=b2a and the vertex is located at the maximum point.

3Step 3. Write the axis of symmetry for the function y = a x 2 + b x + c .

The axis of symmetry for the function y=ax2+bx+c is

x=b2a

4Step 4. Define y -intercept of the function y = a x 2 + b x + c .

The y-intercept of the function y=ax2+bx+c is always at c.

5Step 5. Calculate the vertex, the equation of the axis of symmetry, and the y -intercept of the function y = 5 x 2 + 20 x + 10 .

Compare the quadratic function y=5x2+20x+10 with the standard quadratic function y=ax2+bx+c.

a=5,b=20,c=10

Substitute a=5 and b=20 in x=b2a.

x=2025x=2010x=2x=2

So, the axis of symmetry is given by 

x=2

Since, a>0.

So, the function has a minimum value at x=2.

Substitute x=2 in y=5x2+20x+10.

y=522+202+10y=5440+10y=2040+10y=3040y=10

So, the vertex point is located at the point 2,10.

Since, the y-intercept is given by c.

So, the y-intercept is 10. 

 

Therefore the vertex is 2,10, the equation of the axis of symmetry is x=2 and the y-intercept is 10.