Q42.

Question

Find the vertex, the equation of the axis of symmetry, and the y-intercept of the given equation.


y=x2+10x13

Step-by-Step Solution

Verified
Answer

The vertex is 5,12, the equation of the axis of symmetry is x=5 and the y-intercept is 13.

1Step 1. Define the standard form of the quadratic function.

A quadratic function, which is written in the form, y=ax2+bx+c, where, a0 is called the standard form of the quadratic function.

2Step 2. Define the vertex of the function y = a x 2 + b x + c .

For the function y=ax2+bx+c,

(1) If a>0, then the function has the minimum value at x=b2a and the vertex is located at the minimum point.

(2) If a<0, then the function has the maximum value at x=b2a and the vertex is located at the maximum point.

3Step 3. Write the axis of symmetry for the function y = a x 2 + b x + c .

The axis of symmetry for the function y=ax2+bx+c is

x=b2a

4Step 4. Define y -intercept of the function y = a x 2 + b x + c .

The y-intercept of the function y=ax2+bx+c is always at c.

5Step 5. Calculate the vertex, the equation of the axis of symmetry, and the y -intercept of the function y = &#8722; x 2 + 10 x &#8722; 13 .

Compare the quadratic function y=x2+10x13 with the standard quadratic function y=ax2+bx+c.

a=1,b=10,c=13

Substitute a=1 and b=10 in x=b2a.

x=1021x=102x=5x=5

So, the axis of symmetry is given by

x=5

Since, a>0.

So, the function has a minimum value at x=5.

Substitute x=5 in y=x2+10x13.

y=52+10513y=25+5013y=5038y=12

So, the vertex point is located at the point 5,12.

Since, the y-intercept is given by c.

So, the y-intercept is -13.

 

Therefore the vertex is 5,12, the equation of the axis of symmetry is x=5 and the y-intercept is 13.