Q41.

Question

Find the vertex, the equation of the axis of symmetry, and the y-intercept of the given equation.


y=3x2+6x18

Step-by-Step Solution

Verified
Answer

The vertex is 1,15, the equation of the axis of symmetry is x=1 and the y-intercept is 18.

1Step 1. Define the standard form of the quadratic function.

A quadratic function, which is written in the form, y=ax2+bx+c, where, a0 is called the standard form of the quadratic function.

2Step 2. Define the vertex of the function y = a x 2 + b x + c .

For the function y=ax2+bx+c

(1) If a>0, then the function has the minimum value at x=b2a and the vertex is located at the minimum point.

(2) If a<0, then the function has the maximum value at x=b2a and the vertex is located at the maximum point.

3Step 3. Write the axis of symmetry for the function y = a x 2 + b x + c .

The axis of symmetry for the function y=ax2+bx+c is

x=b2a

4Step 4. Define y -intercept of the function y = a x 2 + b x + c .

The y-intercept of the function y=ax2+bx+c is always at c.

5Step 5. Calculate the vertex, the equation of the axis of symmetry, and the y -intercept of the function y = &#8722; 3 x 2 + 6 x &#8722; 18 .

Compare the quadratic function y=3x2+6x18 with the standard quadratic function y=ax2+bx+c.

a=3,b=6,c=18

Substitute a=3 and b=6 in x=b2a.

x=623x=66x=1x=1

So, the axis of symmetry is given by 

x=1

Since, a>0.

So, the function has a minimum value at x=1.

Substitute x=1 in y=3x2+6x18.

y=312+6118y=31+618y=3+618y=21+6y=15

So, the vertex point is located at the point 1,15.

Since, the y-intercept is given by c.

So, the y-intercept is 18.

 

Therefore the vertex is 1,15, the equation of the axis of symmetry is x=1 and the y-intercept is 18.