Q. 8

Question

In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak} and {bk} such that the sequence {akbk} converges.

Step-by-Step Solution

Verified
Answer

The example of the sequence is {ak}={k} and {bk}={k2}.

1Step 1. Given Information.

Two divergent sequence {ak} and {bk}.

2Step 2. Consider the divergent sequence.

Consider the sequence {ak}={k} which is strictly increasing an not bounded above.

So it is divergent sequence.

Consider the sequence {bk}={k2} which is strictly increasing an not bounded above.

So it is divergent sequence.

3Step 3. Division of the sequence.

The sequence {akbk}={1k} which is a decreasing sequence and bounded below.

And the sequence converges to zero.

So the division of two divergent sequence can be convergent.