Q. 8
Question
In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences and such that the sequence converges.
Step-by-Step Solution
Verified Answer
The example of the sequence is and .
1Step 1. Given Information.
Two divergent sequence .
2Step 2. Consider the divergent sequence.
Consider the sequence which is strictly increasing an not bounded above.
So it is divergent sequence.
Consider the sequence which is strictly increasing an not bounded above.
So it is divergent sequence.
3Step 3. Division of the sequence.
The sequence which is a decreasing sequence and bounded below.
And the sequence converges to zero.
So the division of two divergent sequence can be convergent.
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