Q. 9

Question

In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak} and {bk} such that the sequence {akbk} diverges.

Step-by-Step Solution

Verified
Answer

The example of the sequence is {ak}={k2} and {bk}=k.

1Step 1. Given Information.

Two divergent sequence {ak} and {bk}.

2Step 2. Consider the divergent sequence.

Consider the sequence {ak}={k2} which is strictly increasing and not bounded above.

So it is divergent sequence.

Consider the sequence {bk}={k} which is strictly increasing and not bounded above.

So it is divergent sequence.

3Step 3. Division of the sequence.

The sequence {akbk}={k} which is a decreasing sequence and not bounded above.

And the sequence does not converge to zero.

So the division of two divergent sequence can be divergent.