Q. 7

Question

In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak} and {bk} such that the sequence {ak.bk} diverges.

Step-by-Step Solution

Verified
Answer

The examples of such divergent sequence is {ak}={k} and {bk}={k}.

1Step 1. Given Information.

Two divergent sequences {ak} and {bk} such that the sequence {ak.bk} is divergent.

2Step 2. Consider the sequence.

Consider the sequence,

{ak}={k}{bk}={k}

Both are monotonically increasing function and are not bounded above.

So the sequences are divergent.

3Step 3. Explanation of the statement.

The product of the sequence {ak.bk}={k2} is again a strictly increasing sequence and not bounded above.

So the resultant sequence is also divergent.