Q. 6

Question

In Exercises 4–11, give examples of sequences satisfying the given conditions or explain why such an example cannot exist.
Two divergent sequences {ak} and {bk} such that the sequence {ak.bk} converges.

Step-by-Step Solution

Verified
Answer

There is no such divergent sequence {ak} and {bk} whose product {ak.bk} is a convergent sequence.

1Step 1. Given Information.

Two divergent sequences {ak} and {bk} such that the sequence {ak.bk} converges.

2Step 2. Explanation.

the product of any two divergent sequence is again a divergent sequence.

So there is no such divergent sequences {ak},{bk} such that their product {ak.bk} is a convergent sequence.