Problem 16
Question
multiply or divide as indicated. $$ \frac{6 x+9}{3 x-15} \cdot \frac{x-5}{4 x+6} $$
Step-by-Step Solution
Verified Answer
The simplified form of the multiplication of the given algebraic fractions is \(\frac{1}{4}\).
1Step 1: Multiply the Fractions
Multiply the numerators together: \((6x + 9)(x - 5)\), and the denominators together: \((3x - 15)(4x + 6)\). The fraction now is \(\frac{(6x + 9)(x - 5)}{(3x - 15)(4x + 6)}\).
2Step 2: Factor the Terms
Factor each term in the fraction: The numerator \((6x + 9)(x - 5)\) becomes \(3(2x + 3)(x - 5)\), and the denominator \((3x - 15)(4x + 6)\) becomes \(3(x - 5)(4(2x + 3))\). The fraction now is \(\frac{3(2x + 3)(x - 5)}{3(x - 5)(4(2x + 3))}\)
3Step 3: Cancel out the Common Factors
Next, cancel out the common factors in the numerator and denominator. In this case, the common factors are \(3(2x + 3)(x - 5)\). After cancelling out, the fraction becomes \(\frac{1}{4}\)
Key Concepts
Factorization in AlgebraSimplifying Algebraic ExpressionsCommon Factors in Algebra
Factorization in Algebra
Factorization is a critical concept in algebra that involves breaking down an algebraic expression into a product of simpler factors. It can significantly simplify solving equations, as well as multiplying and dividing algebraic fractions.
For instance, when you encounter an algebraic expression like \(6x + 9\), you can factor it by finding the greatest common factor (GCF), which is 3 in this case, and writing it as \(3(2x + 3)\). This process is vital before you proceed with multiplication or division of fractions.
In our example, both the numerator and the denominator are factored to reveal common factors that can eventually be canceled out. By mastering factorization, you'll be able to reduce complex algebraic fractions to their simplest form with ease.
For instance, when you encounter an algebraic expression like \(6x + 9\), you can factor it by finding the greatest common factor (GCF), which is 3 in this case, and writing it as \(3(2x + 3)\). This process is vital before you proceed with multiplication or division of fractions.
In our example, both the numerator and the denominator are factored to reveal common factors that can eventually be canceled out. By mastering factorization, you'll be able to reduce complex algebraic fractions to their simplest form with ease.
Simplifying Algebraic Expressions
Simplifying algebraic expressions involves reducing them to a more basic or compact form without changing their value. This often includes combining like terms, factoring, and canceling out common factors. Simplification is useful not only for making an expression easier to understand but also for solving equations and working with algebraic fractions.
In the given exercise, after multiplying the fractions, we have \(\frac{(6x + 9)(x - 5)}{(3x - 15)(4x + 6)}\), which looks complex. By factoring out common terms, we reduce this to simplest terms. The simplified form, \(\frac{1}{4}\), is much easier to grasp and use in further calculations or applications. The ability to simplify algebraic expressions is an essential skill for students to master in algebra.
In the given exercise, after multiplying the fractions, we have \(\frac{(6x + 9)(x - 5)}{(3x - 15)(4x + 6)}\), which looks complex. By factoring out common terms, we reduce this to simplest terms. The simplified form, \(\frac{1}{4}\), is much easier to grasp and use in further calculations or applications. The ability to simplify algebraic expressions is an essential skill for students to master in algebra.
Common Factors in Algebra
Identifying common factors plays a pivotal role in working with algebraic expressions, especially when multiplying or dividing fractions. A common factor is a factor that is shared by two or more terms or numbers.
For example, in our original problem, the terms \(\frac{3(2x + 3)(x - 5)}{3(x - 5)(4(2x + 3))}\) share several common factors. Recognizing and canceling out these common factors, such as \(3\), \(2x + 3\), and \(x - 5\), simplifies the expression significantly. In algebra, reducing fractions by eliminating common factors helps in presenting the final answer in its most simplified form, which is a fundamental aspect of solving algebraic problems correctly.
For example, in our original problem, the terms \(\frac{3(2x + 3)(x - 5)}{3(x - 5)(4(2x + 3))}\) share several common factors. Recognizing and canceling out these common factors, such as \(3\), \(2x + 3\), and \(x - 5\), simplifies the expression significantly. In algebra, reducing fractions by eliminating common factors helps in presenting the final answer in its most simplified form, which is a fundamental aspect of solving algebraic problems correctly.
Other exercises in this chapter
Problem 15
Evaluate each exponential expression. $$ \left(2^{2}\right)^{3} $$
View solution Problem 15
Evaluate each algebraic expression for the given value or values of the variable(s). $$\frac{2 x+3 y}{x+1}, \text { for } x=-2 \text { and } y=4$$
View solution Problem 16
Factor by grouping. $$x^{3}-x^{2}-5 x+5$$
View solution Problem 16
In Exercises 15–58, find each product. $$ (x+5)\left(x^{2}-5 x+25\right) $$
View solution