Problem 15
Question
Evaluate each algebraic expression for the given value or values of the variable(s). $$\frac{2 x+3 y}{x+1}, \text { for } x=-2 \text { and } y=4$$
Step-by-Step Solution
Verified Answer
-8
1Step 1: Substitute Given Values
To start, replace \(x\) with \(-2\) and \(y\) with \(4\) in the given expression. You will have \(\frac{2(-2)+3(4)}{-2+1}\).
2Step 2: Perform Arithmetic Operations in the Numerator
Next, perform multiplication and addition in the numerator: \(2(-2) + 3(4)\) gives \(-4 + 12\), which is \(8\). Therefore, the revised expression becomes \(\frac{8}{-2+1}\).
3Step 3: Perform Arithmetic Operations in the Denominator
Perform addition in the denominator: \(-2+1\) gives \(-1\). The revised expression now becomes \(\frac{8}{-1}\).
4Step 4: Final Calculation
Finally, we perform the division, giving us a final result of \(-8\).
Other exercises in this chapter
Problem 15
Use the product rule to simplify the expressions in Exercises \(13-22 .\) In Exercises \(17-22,\) assume that variables represent nonnegative real numbers. $$ \
View solution Problem 15
Evaluate each exponential expression. $$ \left(2^{2}\right)^{3} $$
View solution Problem 16
multiply or divide as indicated. $$ \frac{6 x+9}{3 x-15} \cdot \frac{x-5}{4 x+6} $$
View solution Problem 16
Factor by grouping. $$x^{3}-x^{2}-5 x+5$$
View solution