Problem 16
Question
Factor by grouping. $$x^{3}-x^{2}-5 x+5$$
Step-by-Step Solution
Verified Answer
The factored form by grouping of the polynomial \( x^{3}-x^{2}-5 x+5 \) is \( (x^{2}-5)(x-1) \)
1Step 1: Group the terms
Group the terms in the expression into two pairs. We get: \( (x^{3}-x^{2}) + (-5x+5) \) .
2Step 2: Factor out the common terms
Factor out a common variable or number from each group. From the first group we can factor out \( x^{2} \). In the second group we can factor out \( -5\). This gives us: \( x^{2}(x-1) -5(x-1) \).
3Step 3: Factor by grouping
Now, notice that the two chunks in our expression, \( x^{2} \) and \( -5 \), are both being multiplied by \( (x-1) \). Factor out \( (x-1) \) to get: \( (x^{2}-5)(x-1) \).
Other exercises in this chapter
Problem 15
Evaluate each algebraic expression for the given value or values of the variable(s). $$\frac{2 x+3 y}{x+1}, \text { for } x=-2 \text { and } y=4$$
View solution Problem 16
multiply or divide as indicated. $$ \frac{6 x+9}{3 x-15} \cdot \frac{x-5}{4 x+6} $$
View solution Problem 16
In Exercises 15–58, find each product. $$ (x+5)\left(x^{2}-5 x+25\right) $$
View solution Problem 16
Use the product rule to simplify the expressions in Exercises \(13-22 .\) In Exercises \(17-22,\) assume that variables represent nonnegative real numbers. $$ \
View solution