Problem 16
Question
In Exercises 15–58, find each product. $$ (x+5)\left(x^{2}-5 x+25\right) $$
Step-by-Step Solution
Verified Answer
The product of the given binomial and trinomial is \(x^3 + 125\).
1Step 1: Distribute the Binomial into the Trinomial
Start by distributing \(x+5\) into all the terms of the trinomial \(x^2 - 5x + 25\). So, the equation will be \(x*(x^2) - x*(5x) + x*25 + 5*(x^2) - 5*5x + 5*25\).
2Step 2: Simplify
Now, we simplify the equation to obtain \(x^3 - 5x^2 + 25x + 5x^2 - 25x + 125\). As we see in this equation, the \(25x\) and the \(-25x\) will cancel each other out.
3Step 3: Combine like terms
Next, combine like terms together. So \(x^3 - 5x^2 + 5x^2 = x^3\). Hence, the equation simplifies to \(x^3 + 125\).
Key Concepts
Binomial ExpansionDistributive PropertyCombine Like Terms
Binomial Expansion
Binomial expansion involves expanding a polynomial expression that includes two terms. In simple terms, a binomial is like an expression consisting of two terms, for example, \((x + 5)\). When we talk about expanding a binomial, especially in cases where it's multiplied by a trinomial like in the given exercise, the goal is to distribute each term from the binomial across every term in the other polynomial.
- The binomial here is \(x + 5\).
- The trinomial is \(x^2 - 5x + 25\).
Distributive Property
The distributive property is a fundamental arithmetic idea used to multiply a single term with terms inside parentheses. In this exercise, it allows us to break down the multiplication of a binomial by a trinomial into simple products that are easy to handle. Here's a closer look at how it works:
- The distributive property states that \(a(b + c) = ab + ac\).
- In our exercise, we use this idea twice: once for \(x\) and once for \(5\) from the binomial \((x + 5)\).
Combine Like Terms
Once the multiplication using the distributive property is complete, we end up with several terms. The next important step is to combine like terms to simplify our expression down into its simplest form. Like terms in algebra are terms that have the same variables raised to the same power. For example, \(-5x^2\) and \(5x^2\) can be combined because they are like terms.
By combining the like terms, the equation from our original distribution results in:
By combining the like terms, the equation from our original distribution results in:
- We have \(x^3\)
- Observe that \(-5x^2 + 5x^2 = 0\): These terms cancel each other
- Similarly, \(25x - 25x = 0\): Again, these terms cancel each other out
Other exercises in this chapter
Problem 16
multiply or divide as indicated. $$ \frac{6 x+9}{3 x-15} \cdot \frac{x-5}{4 x+6} $$
View solution Problem 16
Factor by grouping. $$x^{3}-x^{2}-5 x+5$$
View solution Problem 16
Use the product rule to simplify the expressions in Exercises \(13-22 .\) In Exercises \(17-22,\) assume that variables represent nonnegative real numbers. $$ \
View solution Problem 16
Evaluate each exponential expression. $$ \left(3^{3}\right)^{2} $$
View solution