Chapter 21
Master Resource Book in JEE Main Physics · 80 exercises
Problem 47
A uniformly wound solenoidal coil of self-inductance \(1.8 \times 10^{-4} \mathrm{H}\) and resistance \(6 \Omega\) is broken up into two identical coils. These identical coils are then connected in parallel across a \(12 \mathrm{~V}\) battery of negligible resistance. The time constant of the current in the circuit and the steady state current through battery is (a) \(3 \times 10^{-5} \mathrm{~s}, 8 \mathrm{~A}\) (b) \(1.5 \times 10^{-5}\) s, \(8 \mathrm{~A}\) (c) \(0.75 \times 10^{-4} s, 4 \mathrm{~A}\) (d) \(6 \times 10^{-5} \mathrm{~s}, 2 \mathrm{~A}\)
5 step solution
Problem 47
Match the following Column I to Column II. \begin{tabular}{c|l|c|l} \hline \multicolumn{2}{c|} { Column I } & \multicolumn{2}{c} { Column II } \\ \hline L. & Condenser & A. & increases AC \\ II. & Inductor & B. & reduces \(A C\) \\ III. & Energy dissipation is due to & C. & is conductor for DC \\ IV. & A transformer & D. & resistance only \\ \hline \end{tabular} (a) \(1-B, \|-B, C M I-D, I V-A, B\) (b) \(1-\mathrm{D}, \|-\mathrm{C}, \mathrm{D}, \mathrm{III}-\mathrm{B}, \mathrm{IV}-\mathrm{B}, \mathrm{C}\) (c) \(1-\mathrm{A}, \mathrm{II}-\mathrm{B}, \mathrm{C}, \mathrm{III}-\mathrm{D}, \mathrm{IV}-\mathrm{B}\) (d) \(1-\mathrm{C}, 11-\mathrm{B}, \mathrm{III}-\mathrm{D}, \mathrm{IV}-\mathrm{A}\)
5 step solution
Problem 48
When a voltage measuring device is connected to \(\mathrm{AC}\) mains, the meter
shows the steady input voltage of 220 V. This means [NCERT Exemplar]
(a) input voltage cannot be AC voltage, but a DC voltage.
(b) maximum input voltage is \(220 \mathrm{~V}\)
(c) the meter reads not \(v\) but \(
4 step solution
Problem 49
When a voltage measuring device is connected to \(\mathrm{AC}\) mains, the meter
shows the steady input voltage of 220 V. This means [NCERT Exemplar]
(a) input voltage cannot be AC voltage, but a DC voltage.
(b) maximum input voltage is \(220 \mathrm{~V}\)
(c) the meter reads not \(v\) but \(
5 step solution
Problem 50
A \(60 \mu \mathrm{F}\) capacitor is connected to a \(110 \mathrm{~V}, 60 \mathrm{~Hz} \mathrm{AC}\) supply. Determine the \(\mathrm{rms}\) value of the current in the circuit. (a) \(2.5 \mathrm{~A}\) (b) \(2.1 \mathrm{~A}\) (c) \(3.1 \mathrm{~A}\) (d) \(3.5 \mathrm{~A}\)
5 step solution
Problem 50
Assertion Inductance coil are made of copper. Reason Induced current is more in wire having less resistance.
4 step solution
Problem 51
A \(60 \mu \mathrm{F}\) capacitor is connected to a \(110 \mathrm{~V}, 60 \mathrm{~Hz} \mathrm{AC}\) supply. Determine the \(\mathrm{rms}\) value of the current in the circuit. (a) \(2.5 \mathrm{~A}\) (b) \(2.1 \mathrm{~A}\) (c) \(3.1 \mathrm{~A}\) (d) \(3.5 \mathrm{~A}\)
4 step solution
Problem 52
Assertion The armature current in DC motor maximum when the motor has just started. Reason Armature current is given by \(i=\frac{E-e}{R_{\alpha}}\), where \(e=\) the back emf and \(R_{a}=\) resistance of armature.
4 step solution
Problem 53
The turns ratio of transformer is given as \(2: 3 .\) If the current passing through the primary coil is \(3 \mathrm{~A}\). Find the current through the load resistance. (a) \(4.5 \mathrm{~A}\) (b) \(1.5 \mathrm{~A}\) (c) \(2 \mathrm{~A}\) (d) \(\mid \mathrm{A}\) The \(\bar{n}\) tuxe 4
5 step solution
Problem 54
The primary winding of a transformer has 200 turns and its secondary winding has 50 turns, If the current in the secondary winding is \(40 \mathrm{~A}\), the current in the primary is (a) \(10 \mathrm{~A}\) (b) \(80 \mathrm{~A}\) (c) \(160 \mathrm{~A}\) (d) \(800 \mathrm{~A}\)
5 step solution
Problem 55
The number of turns in a secondary coil is twice the number of turns in primary. A leclanche cell of \(1.5 \mathrm{~V}\) is connected across the primary. The voltage across secondary is (a) \(1.5 \mathrm{~V}\) (b) \(3.0 \mathrm{~V}\) (c) \(240 \mathrm{~V}\) (d) zero
4 step solution
Problem 55
Assertion In a series \(R-L-C\) circuit the voltage across resistor, inductor and capacitor are \(8 \mathrm{~V}, 16 \mathrm{~V}\) and \(10 \mathrm{~V}\) respectively. The resultant emf the circuit is \(10 \mathrm{~V}\). Reason Resultant emf of the circuit is given by the relation \(E=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}}\)
5 step solution
Problem 56
A step-up transformer is used on a \(120 \mathrm{~V}\) line to provide a potential difference of \(2400 \mathrm{~V}\). If the primary coil has 75 turns, the number of turns in the secondary coil is (a) 150 (b) 1200 (c) 1500 (d) 1575
5 step solution
Problem 56
Assertion In a series \(R-L-C\) circuit the voltage across resistor, inductor and capacitor are \(8 \mathrm{~V}, 16 \mathrm{~V}\) and \(10 \mathrm{~V}\) respectively. The resultant emf the circuit is \(10 \mathrm{~V}\). Reason Resultant emf of the circuit is given by the relation \(E=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}}\)
5 step solution
Problem 57
The ratio of turns in primary and secondary coils of a transformer is \(1: 20 .\) The ratio of currents in primary and secondary coils will be (a) \(1: 20\) (b) \(20: 1\) (c) \(1: 400\) (d) \(400: 1\) A
4 step solution
Problem 57
Assertion In series \(L-C-R\) circuit resonance can take place. Reason Resonance takes place if inductive and capacitive reactances are equal and opposite.
4 step solution
Problem 58
The ratio of turns in primary and secondary coils of a transformer is \(1: 20 .\) The ratio of currents in primary and secondary coils will be (a) \(1: 20\) (b) \(20: 1\) (c) \(1: 400\) (d) \(400: 1\) A
4 step solution
Problem 59
A low-loss transformer has \(230 \mathrm{~V}\) applied to the primary and gives \(4.6 \mathrm{~V}\) in the secondary. Secondary is connected to a load, which draws \(5 \mathrm{~A}\) of current. The current (in ampere) in the primary is (a) \(0.1\) (b) \(1.0\) (c) 10 (d) 250
4 step solution
Problem 61
In AC series circuit, the resistance, inductive reactance and capacitive reactance are \(3 \Omega, 10 \Omega\) and \(14 \Omega\) respectively. The impedance of the circuit is [Orissa JEE 2011] (a) \(5 \Omega\) (b) \(4 \Omega\) (c) \(7 \Omega\) (d) \(10 \Omega\)
5 step solution
Problem 62
A transformer is used to light \(140 \mathrm{~W}, 24 \mathrm{~V}\) lamp from \(240 \mathrm{~V}\) AC mains, The current in the mains is \(0.7 \mathrm{~A}\). The efficiency of transformer is nearest to (a) 909 (b) 8096 (c) 7096 (d) \(60 \%\)
4 step solution
Problem 63
The reduce the resonant frequency in an \(L-C-R\) series circuit with a generator \(\quad\) [NCERT Exemplar] (a) the generator frequency should be reduced (b) another capacitor should be added in parallel to the first [c) the iron core of the inductor should be removed (d) dielectric in the capacitor should be removed
5 step solution
Problem 64
The reduce the resonant frequency in an \(L-C-R\) series circuit with a generator \(\quad\) [NCERT Exemplar] (a) the generator frequency should be reduced (b) another capacitor should be added in parallel to the first [c) the iron core of the inductor should be removed (d) dielectric in the capacitor should be removed
6 step solution
Problem 64
An AC voltage source of variable angular frequency @ and fixed amplitude \(V\) connected in series with a capacitance \(C\) and an electric bulbs of resistance \(R\) (inductance zero) when wis increased [IIT JEE 2010] (a) The bulb glows dimmer (b) The bulb glows brighter (c) Total impedence of the circuit is unchanged (d) Total impedence of the circuit increases
4 step solution
Problem 65
A transformer is having 2100 turns in primary and 4200 turns in secondary. An AC source of \(120 \mathrm{~V}, 10 \mathrm{~A}\) is connected to its primary. The secondary voltage and current are (a) \(240 \mathrm{~V}, 5 \mathrm{~A}\) (b) \(120 \mathrm{~V}, 10 \mathrm{~A}\) (c) \(240 \mathrm{~V}, 10 \mathrm{~A}\) (d) \(120 \mathrm{~V}, 20 \mathrm{~A}\)
4 step solution
Problem 65
A conducting circular loop is placed in a uniform magnetic field \(0.04 \mathrm{~T}\) with its plane perpendicular to the magnetic field. The radius of the loop starts sinking at \(2 \mathrm{mms}^{-1}\). The induced emf in the loop when the radius is \(2 \mathrm{~cm}\) is [Kerala CET 2009] (a) \(1.6 \pi \mu \mathrm{V}\) (b) \(3.2 \pi \mu \mathrm{V}\) (c) \(4.8 \pi \mu \mathrm{V}\) [d) \(0.8 \pi \mu \mathrm{V}\)
5 step solution
Problem 67
An AC voltage source has an output of \(\Delta V=(200 \mathrm{~V}) \sin 2 \pi f t\). This source is connected to a \(100 \mathrm{~W}\) resistor. Rms current in the resistance is [Kerala CET 2008] (a) \(1.41 \mathrm{~A}\) (b) \(2.41 \mathrm{~A}\) (c) \(3.41 \mathrm{~A}\) (d) \(0.71 \mathrm{~A}\)
5 step solution
Problem 68
A transformer is used to light a \(100 \mathrm{~W}-110 \mathrm{~V}\) lamp from \(220 \mathrm{~V}\) mains. If main current is \(0.5 \mathrm{~A}\), efficiency of transformer is (a) \(90 \%\) (b) 9596 (c) 9696 (d) \(99 \%\)
4 step solution
Problem 68
If the self-inductance of 500 turn coil is \(125 \mathrm{mH}\), then the self- inductance of similar coil of 800 turns is [Kerala CET 2008] (a) \(48.8 \mathrm{mH}\) (b) \(200 \mathrm{mH}\) (c) \(187.5 \mathrm{mH}\) (d) \(320 \mathrm{mH}\)
5 step solution
Problem 70
A coil of inductance \(300 \mathrm{mH}\) and resistance \(2 \Omega\) is connected to a source of voltage \(2 \mathrm{~V} .\) The current reaches half of its steady state value in [Kerala CET 2008] (a) \(0.05 \mathrm{~s}\) (b) \(0.1 \mathrm{~s}\) (c) \(0.15 \mathrm{~s}\) (d) \(0.3 \mathrm{~s}\)
6 step solution
Problem 71
The flux linked with a circuit is given by \(\phi=t^{3}+3 t-7 .\) The graph between time \((x\)-axis) and induced emf ( \(y\)-axis) will be (a) a straight line through the origin (b) straight line with positive intercept (c) straight line with negative intercept (d) parabola not through the origin
5 step solution