Chapter 24
Master Resource Book in JEE Main Physics · 126 exercises
Problem 71
Assertion A famous painting was painted by not using brush strokes in the usual manner, but rather a myriad of small colour dots. In this painting the colour you see at any given place on the painting changes as you move away. Reason The angular separation of adjacent dots changes with the distance from the painting.
4 step solution
Problem 73
A beam of light consisting of two wavelengths 650 \(\mathrm{nm}\) and \(520 \mathrm{~nm}\) is used to illuminate the slit of a Young's double slit experiment. Then the order of the bright fringe of the longer wavelength that coincide with a bright fringe of the shorter wavelength at the least distance from the central maximum is (a) 1 (b) 2 (c) 3 (d) 4
4 step solution
Problem 73
Assertion In Young's experiment, the fringe width for dark fringes is same from that for white fringes. Reason In Young's double slit experiment, when the fringes are performed with a source of white light, then only black and bright fringes are observed.
4 step solution
Problem 74
Assertion Thin films such as soap bubble or a thin layer of oil on water show beautiful colours when illuminated by white light. Reason It happens due to the interference of light reflected from the upper surface of the thin film.
4 step solution
Problem 75
In Young's double slit experiment, the 8 th maximum with wavelength \(\lambda_{1}\) is at a distance, \(d_{1}\) from the central maximum and the 6 th maximum with wavelength \(\lambda_{2}\) is at a distance, \(d_{2}\). Then, \(d_{1} / d_{2}\) is equal to (a) \(\frac{4}{3}\left(\frac{\lambda_{2}}{\lambda_{1}}\right)\) (b) \(\frac{4}{3}\left(\frac{\lambda_{1}}{\lambda_{2}}\right)\) (c) \(\frac{3}{4}\left(\frac{\lambda_{2}}{\lambda_{1}}\right)\) (d) \(\frac{3}{4}\left(\frac{\lambda_{1}}{\lambda_{2}}\right)\)
4 step solution
Problem 75
Assertion Corpuscular theory fails in explaining the velocities of light in air and water. Reason According to corpuscular theory, light should travel faster in denser media than in rarer media.
4 step solution
Problem 76
Light of wavelength \(500 \mathrm{~nm}\) is used to form interference pattern in Young's double slit experiment. A uniform glass plate of refractive index \(1.5\) and thickness \(0.1 \mathrm{~mm}\) is introduced in the path of one of the interfering beams. The number of fringes which will shift the cross wire due to this is (a) 100 (b) 200 (c) 300 (d) 400
6 step solution
Problem 77
Air has refractive index \(1.003 .\) The thickness of air column, which will have one more wavelength of yellow light \((6000 \AA)\) than in the same thickness of vacuum is (a) \(2 \mathrm{~mm}\) (b) \(2 \mathrm{~cm}\) (c) \(2 \mathrm{~m}\) (d) \(2 \mathrm{~km}\)
5 step solution
Problem 78
Air has refractive index \(1.003 .\) The thickness of air column, which will have one more wavelength of yellow light \((6000 \AA)\) than in the same thickness of vacuum is (a) \(2 \mathrm{~mm}\) (b) \(2 \mathrm{~cm}\) (c) \(2 \mathrm{~m}\) (d) \(2 \mathrm{~km}\)
5 step solution
Problem 78
Assertion No diffraction is produced in sound waves near a very small opening. Reason For diffraction to take place the aperture of opening should be of the same order as wavelength of the waves.
4 step solution
Problem 79
Plane microwaves are incident on a long slit having a width of \(5 \mathrm{~cm}\). The wavelength of the microwaves if the first minimum is formed at \(30^{\circ}\) is (a) \(2.5 \mathrm{~cm}\) (b) \(2 \mathrm{~cm}\) (c) \(25 \mathrm{~cm}\) (d) \(2 \mathrm{~mm}\)
5 step solution
Problem 79
Assertion In Young's experiment, for two coherent sources, the resultant intensity given by \(I=4 I_{0} \cos ^{2} \frac{\phi}{2}\) Reason Ratio of maximum and minimum intensity \(\frac{I_{\mathrm{max}}}{I_{\min }}=\frac{\left(\sqrt{I_{1}}+\sqrt{I_{2}}\right)^{2}}{\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}}\)
4 step solution
Problem 80
A plane wave of wavelength \(6250 \AA\) is incident normally on a slit of width \(2 \times 10^{-2} \mathrm{~cm}\). The width of the principal maximum on a screen distant \(50 \mathrm{~cm}\) will be (a) \(312.5 \times 10^{-1} \mathrm{~cm}\) (b) \(312.5 \times 10^{-4} \mathrm{~cm}\) (c) \(312 \mathrm{~cm}\) (d) \(312.5 \times 10^{-5} \mathrm{~cm}\)
6 step solution
Problem 81
A plane wave of wavelength \(6250 \mathrm{~A}\) is incident normally on a slit of width \(2 \times 10^{-2} \mathrm{~cm}\). The width of the principal maximum on a screen distant \(50 \mathrm{~cm}\) will be (a) \(312.5 \times 10^{-3} \mathrm{~cm}\) (b) \(312.5 \times 10^{-4} \mathrm{~cm}\) (c) \(312 \mathrm{~cm}\) (d) \(312.5 \times 10^{-5} \mathrm{~cm}\)
3 step solution
Problem 81
Assertion For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal. Reason The intensity of interference pattern is proportional to square of amplitude.
4 step solution
Problem 82
Light of wavelength \(6000 \AA\) is incident on a single slit. The first minimum of the diffraction pattern is obtained at \(4 \mathrm{~mm}\) from the centre. The screen is at a distance of \(2 \mathrm{~m}\) from the slit. The slit width will be (a) \(0.3 \mathrm{~mm}\) (b) \(0.2 \mathrm{~mm}\) (c) \(0.15 \mathrm{~mm}\) (d) \(0.1 \mathrm{~mm}\)
6 step solution
Problem 83
The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length \(1 \mathrm{~m}\). The width of slit is \(0.3 \mathrm{~mm}\). If third minimum is formed at a distance of \(5 \mathrm{~mm}\) from central maximum, then wavelength of light will be (a) \(5000 \mathrm{~A}\) (b) \(2500 \mathrm{~A}\) (c) \(7500 \AA\) (d) \(8500 \mathrm{~A}\)
4 step solution
Problem 83
In Young's double slit experiment, one of the slit is wider than other, so that amplitude of light from one slit is double of that from other slit. If, \(I_{m}\) be the maximum intensity, the resultant intensity \(I\) when they interfere at phase difference \(\phi\), is given by [AIEEE 2012] (a) \(\frac{l_{m}}{9}(4+5 \cos \phi)\) (b) \(\frac{I_{m}}{3}\left(1+\cos ^{2} \frac{\phi}{2}\right)\) (c) \(\frac{l_{\mathrm{m}}}{5}\left(1+4 \cos ^{2} \frac{\phi}{2}\right)\) (d) \(\frac{l_{m}}{9}\left(1+8 \cos ^{2} \frac{\phi}{2}\right)\)
5 step solution
Problem 84
What should be refractive index of a transparent medium to be invisible in vacuum? (a) 1 (b) \(<1\) (c) \(>1\) (d) None of these
4 step solution
Problem 85
What should be refractive index of a transparent medium to be invisible in vacuum? (a) 1 (b) \(<1\) (c) \(>1\) (d) None of these
4 step solution
Problem 86
Which of the following phenomena is not common to sound and light waves? (a) Interference (b) Diffraction (c) Coherence (d) Polarisation
3 step solution
Problem 87
Which of the following phenomena is not common to sound and light waves? (a) Interference (b) Diffraction (c) Coherence (d) Polarisation
5 step solution
Problem 87
A thin air film is formed by putting the convex surface of a pleno-convex lens over a plane glass plate. With monochromatic source of light, this film gives an interference pattern due to light reflected from the top (convex) surface and the bottom (glass plate) surface of the film. Statement I When light reflects from the air glass plate interface, the reflected want suffers a phase change of \(\pi\). Statement II The centre of the interface pattern is dark.
3 step solution
Problem 88
What is the Brewster's angle for air to glass transition? (Refractive index of glass \(=1.5\) ) \([\) NCERT] (a) \(15^{\circ} \overline{27}\) (b) \(36^{\circ} 27^{\prime}\) (c) \(50^{\circ} 16^{\prime}\) (d) \(56^{\circ} 18^{\prime}\)
4 step solution
Problem 89
An unpolarised beam of intensity \(2 \alpha^{2}\) passes through a thin polaroid. Assuming zero absorption in the polaroid, the instensity of emergent plane polarised light is (a) \(2 a^{2}\) (b) \(a^{2}\) (c) \(\sqrt{2} a^{2}\) (d) \(\frac{a^{2}}{2}\)
3 step solution
Problem 90
\(80 \mathrm{~g}\) of impure sugar, when dissolved in a litre of water gives an optical rotation of \(9.9^{\circ}\), when placed in a tube of length \(20 \mathrm{~cm}\). If, the specific rotation of sugar is \(66^{\circ}\), then concentration of sugar solution will be (a) \(80 \mathrm{gL}^{-1}\) (b) \(75 \mathrm{gL}^{-1}\) [c) \(65 \mathrm{gL}^{-1}\) (d) \(50 \mathrm{gL}^{-1}\)
7 step solution