Chapter 5
Elementary Algebra · 293 exercises
Problem 109
The sum of two numbers is -26. One number is 12 less than the other. Find the numbers.
6 step solution
Problem 110
The perimeter of a rectangle is 50 . The length is 5 more than the width. Find the length and width.
5 step solution
Problem 111
The perimeter of a rectangle is 60 . The length is 10 more than the width. Find the length and width.
5 step solution
Problem 112
The perimeter of a rectangle is 58 . The length is 5 more than three times the width. Find the length and width.
6 step solution
Problem 113
The perimeter of a rectangle is \(84 .\) The length is 10 more than three times the width. Find the length and width.
6 step solution
Problem 116
The measure of one of the small angles of a right triangle is 15 less than twice the measure of the other small angle. Find the measure of both angles.
6 step solution
Problem 118
Maxim has been offered positions by two car dealers. The first company pays a salary of \(\$ 10,000\) plus a commission of \(\$ 1,000\) for each car sold. The second pays a salary of \(\$ 20,000\) plus a commission of \(\$ 500\) for each car sold. How many cars would need to be sold to make the total pay the same?
3 step solution
Problem 119
Jackie has been offered positions by two cable companies. The first company pays a salary of \(\$ 14,000\) plus a commission of \(\$ 100\) for each cable package sold. The second pays a salary of \(\$ 20,000\) plus a commission of \(\$ 25\) for each cable package sold. How many cable packages would need to be sold to make the total pay the same?
5 step solution
Problem 120
Amara currently sells televisions for company \(A\) at \(a\) salary of \(\$ 17,000\) plus a \(\$ 100\) commission for each television she sells. Company B offers her a position with a salary of \(\$ 29,000\) plus a \(\$ 20\) commission for each television she sells. How televisions would Amara need to sell for the options to be equal?
4 step solution
Problem 121
Mitchell currently sells stoves for company \(A\) at a salary of \(\$ 12,000\) plus a \(\$ 150\) commission for each stove he sells. Company B offers him a position with a salary of \(\$ 24,000\) plus a \(\$ 50\) commission for each stove he sells. How many stoves would Mitchell need to sell for the options to be equal?
4 step solution
Problem 122
When Gloria spent 15 minutes on the elliptical trainer and then did circuit training for 30 minutes, her fitness app says she burned 435 calories. When she spent 30 minutes on the elliptical trainer and 40 minutes circuit training she burned 690 calories. Solve the system \(\left\\{\begin{array}{l}15 e+30 c=435 \\ 30 e+40 c=690\end{array}\right.\) for \(e,\) the number of calories she burns for each minute on the elliptical trainer, and \(c,\) the number of calories she burns for each minute of circuit training.
8 step solution
Problem 123
Stephanie left Riverside, California, driving her motorhome north on Interstate 15 towards Salt Lake City at a speed of 56 miles per hour. Half an hour later, Tina left Riverside in her car on the same route as Stephanie, driving 70 miles per hour. Solve the system \(\left\\{\begin{array}{l}56 s=70 t \\\ s=t+\frac{1}{2}\end{array}\right.\) (a) for \(t\) to find out how long it will take Tina to catch up to Stephanie. (b) what is the value of \(s,\) the number of hours Stephanie will have driven before Tina catches up to her?
5 step solution
Problem 124
Solve the system of equations \(\left\\{\begin{array}{l}x+y=10 \\\ x-y=6\end{array}\right.\) (a) by graphing. (b) by substitution. (c) Which method do you prefer? Why?
8 step solution
Problem 125
Solve the system of equations \(\left\\{\begin{array}{l}3 x+y=12 \\\ x=y-8\end{array}\right.\) by substitution and explain all your steps in words.
5 step solution
Problem 126
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x+2 y=2 \\ -3 x-y=0 \end{array}\right. $$
5 step solution
Problem 127
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} -3 x+y=-9 \\ x-2 y=-12 \end{array}\right. $$
5 step solution
Problem 128
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 6 x-5 y=-1 \\ 2 x+y=13 \end{array}\right. $$
5 step solution
Problem 129
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x-y=-7 \\ 4 x+2 y=-6 \end{array}\right. $$
6 step solution
Problem 130
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} x+y=-1 \\ x-y=-5 \end{array}\right. $$
5 step solution
Problem 131
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} x+y=-8 \\ x-y=-6 \end{array}\right. $$
5 step solution
Problem 132
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x-2 y=1 \\ -x+2 y=9 \end{array}\right. $$
5 step solution
Problem 133
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} -7 x+6 y=-10 \\ x-6 y=22 \end{array}\right. $$
6 step solution
Problem 134
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x+2 y=-3 \\ -x-2 y=-19 \end{array}\right. $$
5 step solution
Problem 135
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x+2 y=1 \\ -5 x-4 y=-7 \end{array}\right. $$
5 step solution
Problem 136
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 6 x+4 y=-4 \\ -6 x-5 y=8 \end{array}\right. $$
5 step solution
Problem 137
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x-4 y=-11 \\ x-2 y=-5 \end{array}\right. $$
5 step solution
Problem 138
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x-7 y=29 \\ x+3 y=-3 \end{array}\right. $$
5 step solution
Problem 139
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 6 x-5 y=-75 \\ -x-2 y=-13 \end{array}\right. $$
5 step solution
Problem 140
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} -x+4 y=8 \\ 3 x+5 y=10 \end{array}\right. $$
6 step solution
Problem 141
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 2 x-5 y=7 \\ 3 x-y=17 \end{array}\right. $$
4 step solution
Problem 142
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x-3 y=-1 \\ 2 x-y=2 \end{array}\right. $$
5 step solution
Problem 143
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 7 x+y=-4 \\ 13 x+3 y=4 \end{array}\right. $$
5 step solution
Problem 144
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} -3 x+5 y=-13 \\ 2 x+y=-26 \end{array}\right. $$
5 step solution
Problem 145
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x-5 y=-9 \\ 5 x+2 y=16 \end{array}\right. $$
4 step solution
Problem 146
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 4 x-3 y=3 \\ 2 x+5 y=-31 \end{array}\right. $$
5 step solution
Problem 147
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 4 x+7 y=14 \\ -2 x+3 y=32 \end{array}\right. $$
5 step solution
Problem 148
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x+2 y=21 \\ 7 x-4 y=9 \end{array}\right. $$
5 step solution
Problem 149
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x+8 y=-3 \\ 2 x+5 y=-3 \end{array}\right. $$
6 step solution
Problem 150
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 11 x+9 y=-5 \\ 7 x+5 y=-1 \end{array}\right. $$
5 step solution
Problem 151
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x+8 y=67 \\ 5 x+3 y=60 \end{array}\right. $$
5 step solution
Problem 152
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 2 x+9 y=-4 \\ 3 x+13 y=-7 \end{array}\right. $$
5 step solution
Problem 153
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} \frac{1}{3} x-y=-3 \\ x+\frac{5}{2} y=2 \end{array}\right. $$
6 step solution
Problem 154
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} x+\frac{1}{2} y=\frac{3}{2} \\ \frac{1}{5} x-\frac{1}{5} y=3 \end{array}\right. $$
4 step solution
Problem 155
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} x+\frac{1}{3} y=-1 \\ \frac{1}{2} x-\frac{1}{3} y=-2 \end{array}\right. $$
6 step solution
Problem 157
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 2 x+y=3 \\ 6 x+3 y=9 \end{array}\right. $$
4 step solution
Problem 158
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} x-4 y=-1 \\ -3 x+12 y=3 \end{array}\right. $$
3 step solution
Problem 159
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} -3 x-y=8 \\ 6 x+2 y=-16 \end{array}\right. $$
4 step solution
Problem 160
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 4 x+3 y=2 \\ 20 x+15 y=10 \end{array}\right. $$
4 step solution
Problem 161
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 3 x+2 y=6 \\ -6 x-4 y=-12 \end{array}\right. $$
4 step solution
Problem 162
In the following exercises, solve the systems of equations by substitution. $$ \left\\{\begin{array}{l} 5 x-8 y=12 \\ 10 x-16 y=20 \end{array}\right. $$
2 step solution