Multivariable Functions

Calculus ยท 618 exercises

Q 0.

Read the section and make your own summary of the material.

2 step solution

Q. 53.

For the partial derivatives given in Exercises 51–54, find the

most general form for a function of two variables, , with

the given partial derivative

2fx2=0 

2 step solution

Q 1.

Explain why Definition 0.1 is general enough to include functions of two and three variables.

2 step solution

Q 1. True/False

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The domain of a function of two variables is a subset of R2.

(b) True or False: The range of a function of two variables is a subset of R2.

(c) True or False: The graph of a function of two variables is a subset of R3.

(d) True or False: The domain of a function of three variables is a subset of R.

(e) True or False: The range of a function of three variables is a subset of R.

(f) True or False: The graph of a function of three variables is a subset of R4.

(g) True or False: The graph of a linear function of two variables is a plane.

(h) True or False: If a function f : R → R is continuous on an interval [0, p] then the surface formed when the graph of f is rotated about the y-axis may be

expressed as a function of two variables.

8 step solution

Q 2.

Examples: Construct examples of the thing(s) described in the following. Try to find examples that are different than any in the reading.

(a) A function of two variables whose graph is a plane.

(b) A function of two variables whose graph is the surface of revolution formed when the graph of a function of a single variable is revolved around the y-axis.

(c) A function of two variables for which each level curve is a parabola.

4 step solution

Q 2.

Explain why Definition 0.2 is not general enough to define the domain or range of a function of two or three variables.

2 step solution

Q 3.

Let f : R → R be a function of a single variable. Explain why the graph of f is a subset of R2.

2 step solution

Q 4.

Let f:R2R be a function of two variables. Explain why the graph of f is a subset of R3.

2 step solution

Q 5.

Let f:R3R be a function of three variables. Explain why the graph of f is a subset of R4.

2 step solution

Q 6.

(a) Graph f (x) = x

(b) Graph the function f (x, y) = x + y. Explain why the graph of f (x, y) = x + y contains the origin, (0, 0, 0) 

(c) The graph of the function  f (x, y, z) = x + y + z is a hyperplane of dimension 3 in R4. Explain why “hyperplane” is a good name for the graph. (“Hyper” is from a Greek word meaning over or beyond. The Latin equivalent is super, meaning essentially the same thing.) Explain why the graph of f contains the origin, (0, 0, 0, 0)

(d) Fill in the blanks: The graph of the function  f (x1, x2, . . . , xn) = x1 + x2 +· · ·+xn is a hyperplane of dimension in .

7 step solution

Q 7.

(a) Graph the function f (x) = 1  x2

(b) Graph the function f (x, y) = 1  x2  y2 (Hint: Let z =1  x2  y2 and then square both sides of the equation.)

(c) The graph of the function f (x, y, z) =1  x 2 y2  z2 is half of a hypersphere of dimension 3. Explain why “hypersphere” is a good name for the graph and why the graph is only half of the hypersphere. What equation

defines the entire hypersphere?

(d) Fill in the blanks: The graph of the function f (x 1, x 2, . . . , x n) =1  x2 1 x2 2· · ·x2n is half of a .............of dimension......... in.........?

6 step solution

Q 8.

Find the range of the function fx,y=-8xx2+y2+1from Example 4 by finding the largest value, M, and smallest value, m, of c for which the equation -8xx2+y2+1=c 

has a solution. (Hint: Find the two values for c such that the

level “curves” are a single point. Then show that the given

equation has a solution for every value of c between those two

values.)

2 step solution

Q 9.

Let z = f(x, y) be a function of two variables. Explain why the two sets {(x, y) | (x, y,z) ∈ Graph( f )} and Domain( f ) are identical.

2 step solution

Q 10.

Let z = f(x, y) be a function of two variables. Explain why the two sets 

{z | (x, y, z) ∈ Graph( f )} and Range( f ) are identical.

2 step solution

Q 11.

Let w = f(x, y, z) be a function of three variables. Explain why the two sets {(x, y, z) | (x, y, z, w) ∈ Graph( f )} and Domain( f ) are identical.

2 step solution

Q 12.

Let w = f(x, y, z) be a function of three variables. Explain why the two sets {w | (x, y, z, w) ∈ Graph( f )} and Range( f ) are identical.

2 step solution

Q 13.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

One level curve consists of a single point.

2 step solution

Q 14.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

One level curve consists of exactly two points.

2 step solution

Q 15.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

One level curve is a circle together with the point that is the center of the circle.

2 step solution

Q. 16

Provide a rough sketch of the graph of a function of two variables with the specified level "curve(s)." (There are many possible correct answers to each question.)
One level curve consists of all the points $$(m, n)$$

where \begin{equation} m \end{equation} and \begin{equation} n \end{equation} are both integers.

2 step solution

Q 17.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

All of the level curves are circles except one, which is a point.

2 step solution

Q 18.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

All of the level curves are circles.

2 step solution

Q 19.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

Some level curves consist of two concentric circles.

2 step solution

Q 20.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

Some level curves consist of infinitely many concentric circles.

2 step solution

Q 21.

In Exercise, provide a rough sketch of the graph of a function of two variables with the specified level “curve(s).”

All of the level curves are squares.

2 step solution

Q 22.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y=x2y3,12,43,0,π

2 step solution

Q 23.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y=x2-y2,1,5,-3,-2

2 step solution

Q 24.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

gx,y=x2+y2x+y,π,1,4,5

2 step solution

Q 25.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

gx,y=lnxy1-x,-e,-1,12,2

2 step solution

Q 26.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y=sinx-yx-y,0,π,π2,π3

2 step solution

Q 27.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y,z=x2+y2+z2,1,0,-5,12,-1,13

2 step solution

Q 28.

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y,z=x+y+zxyz,1,-2,6,-3,-2,4

2 step solution

Q 29.

In exercise, 

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the

composition cannot be formed.

f1g1t,g2t

2 step solution

Q 30.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

g1f1x,y,f2x,y

2 step solution

Q 31.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

g1g2t

2 step solution

Q 32.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

f1r1t

2 step solution

Q 33.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

f3g2t,g1t,g3t

2 step solution

Q 34.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

f1f2x,y,f3x,y,z

2 step solution

Q 35.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

r2g3t

2 step solution

Q 36.

In exercise, let

g1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=1+t,t-1, r2(t)=t,t2,t3

Either simplify the specified composition or explain why the composition cannot be formed.

r2f3x,y,z

2 step solution

Q 37.

In Exercise, sketch the surface of revolution formed when the given function on the specified interval is revolved around the z-axis and find a function of two variables with the surface as its graph.

fx=x,0,3

2 step solution

Q. 38.

In Exercises 37–42, sketch the surface of revolution formed

when the given function on the specified interval is revolved

around the z-axis and find a function of two variables with the

surface as its graph.

f(x)=x,[0,4] 

3 step solution

Q. 39.

In Exercises 37–42, sketch the surface of revolution formed

when the given function on the specified interval is revolved

around the z-axis and find a function of two variables with the

surface as its graph.

f(x)=x2 ,0,2

3 step solution

Q. 40.

In Exercises 37–42, sketch the surface of revolution formed

when the given function on the specified interval is revolved

around the z-axis and find a function of two variables with the

surface as its graph.

f(x)=x3/2 ,0,1

3 step solution

Q. 41.

In Exercises 37–42, sketch the surface of revolution formed

when the given function on the specified interval is revolved

around the z-axis and find a function of two variables with the

surface as its graph.

f(x)=sinx ,0,π2 

3 step solution

Q. 42.

In Exercises 37–42, sketch the surface of revolution formed

when the given function on the specified interval is revolved

around the z-axis and find a function of two variables with the

surface as its graph.

f(x)=cosx ,0,π2 

3 step solution

Q. 43.

In Exercises 43–52, sketch the level curvesc=-3,-2,-1,0,1,2,3

 if they exist for the specified function

f(x, y)=x+y 

3 step solution

Q 44.

Sketch the level curves c = 3, 2, 1, 0, 1, 2, 3 if they exist for the specified function. f (x, y) = 3xy

3 step solution

Q 45.

Sketch the level curves c = 3, 2, 1, 0, 1, 2, 3 if they exist for the specified function. f (x, y) = 3xy2

3 step solution

Q 46.

Sketch the level curves c = 3, 2, 1, 0, 1, 2, 3 if they exist for the specified function. f (x, y) = xy

3 step solution

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