Q 33.

Question

In exercise, let

$g_{1} (t) = \sin t, g_{2} (t) = \cos t, g_{3} (t) = 1 - t, f_{1} (x, y) = x^{2} + y^{2}, f_{2} (x, y) = \frac{x^{2}}{y^{2}}, f_{3} (x, y, z) = \frac{x + y}{y + z}, r_{1} (t) = ⟨ 1 + t, t - 1 ⟩, r_{2} (t) = <t, t^{2}, t^{3}>$

Either simplify the specified composition or explain why the composition cannot be formed.

$f_{3} (g_{2} (t), g_{1} (t), g_{3} (t))$

Step-by-Step Solution

Verified

Answer

Answer is $\frac{\cos t + \sin t}{\sin t + 1 - t}$

1Step 1. Given information

2Step 2. Explanation

$\begin{array}{rcl} f_{3} (x, y, z) & = & \frac{x + y}{y + z} \\ g_{1} (t) & = & \sin t \\ g_{2} (t) & = & \cos t \\ g_{3} (t) & = & 1 - t \\ f_{3} (g_{2} (t), g_{1} (t), g_{3} (t)) & = & f_{3} (\cos t, \sin t, 1 - t) \\ = & \frac{\cos t + \sin t}{\sin t + 1 - t} \end{array}$

Q 32.

Q 34.

Other exercises in this chapter

Q 31.

In exercise, letg1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=⟨1+t,t-1⟩, r2(t)=t,

View solution

Q 32.

In exercise, letg1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=⟨1+t,t-1⟩, r2(t)=t,

View solution

Q 34.

In exercise, letg1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=⟨1+t,t-1⟩, r2(t)=t,

View solution

Q 35.

In exercise, letg1(t)=sint, g2(t)=cost, g3(t)=1-t, f1(x,y)=x2+y2,f2(x,y)=x2y2, f3(x,y,z)=x+yy+z,r1(t)=⟨1+t,t-1⟩, r2(t)=t,

View solution