Chapter 20
A Complete Resource Book in Mathematics for JEE Main · 90 exercises
Problem 62
The orbit of the earth is an ellipse with eccentricity \(\frac{1}{60}\) with the sum at one focus, the major axis being approximately \(186 \times 10^{6}\) miles in length. The shortest and longest distance of the earth from the sun is (A) \(9145 \times 10^{4}\) miles, \(9455 \times 10^{4}\) miles (B) \(9147 \times 10^{4}\) miles, \(9457 \times 10^{4}\) miles (C) \(9145 \times 10^{6}\) miles, \(9455 \times 10^{6}\) miles (D) none of these
6 step solution
Problem 63
\(\mathrm{PN}\) is the ordinate of any point \(P\) on the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) and \(A A^{\prime}\) is its transverse axis. If \(Q\) divides \(A P\) in the ratio \(a^{2}: b^{2}\), then \(N Q\) is (A) \(\perp\) to \(A^{\prime} P\) (B) parallel to \(A^{\prime} P\) (C) \(\perp\) to \(O P\) (D) none of these
7 step solution
Problem 64
An ellipse has eccentricity \(\frac{1}{2}\) and one focus at the point \(P\left(\frac{1}{2}, 1\right) .\) Its one directrix is the common tan gent, nearer to the point \(P\), to the circle \(x^{2}+y^{2}=1\) and the hyperbola \(x^{2}-y^{2}=1\). The equation of the ellipse in the standard form is (A) \(\frac{\left(x-\frac{1}{3}\right)^{2}}{\frac{1}{9}}+\frac{(y-1)^{2}}{\frac{1}{12}}=1\) (B) \(\frac{\left(x-\frac{1}{3}\right)^{2}}{\frac{1}{12}}+\frac{(y-1)^{2}}{\frac{1}{9}}=1\) (C) \(\frac{(x-1)^{2}}{\frac{1}{9}}+\frac{\left(y-\frac{1}{3}\right)^{2}}{\frac{1}{12}}=1\) (D) none of these
5 step solution
Problem 65
A variable straight line of slope 4 intersects the hyperbola \(x y=1\) at two points. The locus of the point which divides the line segment between these two points in the ratio \(1: 2\) is (A) \(16 x^{2}+10 x y+y^{2}=2\) (B) \(16 x^{2}-10 x y+y^{2}=2\) (C) \(16 x^{2}+10 x y+y^{2}=4\) (D) none of these
7 step solution
Problem 66
If the parabola \(x^{2}=a y\) makes an intercept of length \(\sqrt{40}\) on the line \(y-2 x=1\), then \(a\) is equal to (A) 1 (B) \(-2\) (C) \(-1\) (D) 2
6 step solution
Problem 67
The asymptotes of the hyperbola \(x y-3 x+4 y+2=0\) are (A) \(x=-4\) (B) \(x=4\) (C) \(y=-3\) (D) \(y=3\)
5 step solution
Problem 68
If the line \(a x+b y+c=0\) is a normal to the hyperbola \(x y=1\), then (A) \(a>0, b<0\) (B) \(a>0, b>0\) (C) \(a<0, b<0\) (D) \(a<0, b>0\)
6 step solution
Problem 69
Consider a circle with its centre lying on the focus of the parabola \(y^{2}=2 p x\) such that it touches the directrix of the parabola. Then, a point of intersection of the circle and the parabola is (A) \(\left(\frac{p}{2}, p\right)\) (B) \(\left(\frac{p}{2},-p\right)\) (C) \(\left(-\frac{p}{2}, p\right)\) (D) \(\left(-\frac{p}{2},-\frac{p}{2}\right)\)
8 step solution
Problem 71
Let \(R(h, k)\) be the middle point of the chord \(P Q\) of the parabola \(y^{2}=4 a x\). Equation of \(P Q\) is $$ (y-k)=m(x-h) $$ where \(m\) is the slope of \(P Q\) \(\because R\) lies on the diameter \(y=\frac{2 a}{m}\) bisecting \(P Q\), $$ \therefore k=\frac{2 a}{m} \Leftrightarrow m=\frac{2 a}{k} $$ Subsituting this value of \(m\) in (1), we have \(y-k=\frac{2 a}{k}(x-h)\) or, \(k(y-k)=2 a(x-h)\) or \(k y-2 a x+\left(2 a h-k^{2}\right)=0\) which is the required equation. The locus of the middle point of chords of the parabola which subtend a constant angle \(\alpha\) at the vertex is \(\left(y^{2}-2 a x+\right.\) \(8 a^{2}\) ) \(^{2} \tan ^{2} \alpha=k a^{2}\left(4 a x-y^{2}\right)\), where \(k=\) (A) 4 (B) 8 (C) 16 (D) none of these
6 step solution
Problem 72
Let \(R(h, k)\) be the middle point of the chord \(P Q\) of the parabola \(y^{2}=4 a x\). Equation of \(P Q\) is $$ (y-k)=m(x-h) $$ where \(m\) is the slope of \(P Q\) \(\because R\) lies on the diameter \(y=\frac{2 a}{m}\) bisecting \(P Q\), $$ \therefore k=\frac{2 a}{m} \Leftrightarrow m=\frac{2 a}{k} $$ Subsituting this value of \(m\) in (1), we have \(y-k=\frac{2 a}{k}(x-h)\) or, \(k(y-k)=2 a(x-h)\) or \(k y-2 a x+\left(2 a h-k^{2}\right)=0\) which is the required equation. The locus of the middle point of chords of the parabola which passes through the focus is (A) \(y^{2}=a(x-a)\) (B) \(y^{2}=2 a(x-a)\) (C) \(y^{2}=4 a(x-a)\) (D) none of these
7 step solution
Problem 73
Let \(R(h, k)\) be the middle point of the chord \(P Q\) of the parabola \(y^{2}=4 a x\). Equation of \(P Q\) is $$ (y-k)=m(x-h) $$ where \(m\) is the slope of \(P Q\) \(\because R\) lies on the diameter \(y=\frac{2 a}{m}\) bisecting \(P Q\), $$ \therefore k=\frac{2 a}{m} \Leftrightarrow m=\frac{2 a}{k} $$ Subsituting this value of \(m\) in (1), we have \(y-k=\frac{2 a}{k}(x-h)\) or, \(k(y-k)=2 a(x-h)\) or \(k y-2 a x+\left(2 a h-k^{2}\right)=0\) which is the required equation. The locus of the middle point of chords of the parabola which are such that the focal distances of their extremities are in the ratio \(2: 1\), is \(9\left(y^{2}-2 a x\right)^{2}=k a^{2}(2 x-a)(4 x+a)\), where \(k=\) (A) 4 (B) 8 (C) 16 (D) none of these
6 step solution
Problem 75
Let \(R(h, k)\) be the middle point of one of the chords, say \(P Q\) of the system of parallel chords of the ellipse Let \(m\) be the slope of these parallel chords. The locus of the middle point \((h, k)\) is \(y=-\frac{b^{2}}{a^{2} m} x\), which is called a diameter of the ellipse. Two diameters are said to be conjugate if each bisects all chords parallel to the other. The condition that two diameters \(y=m_{1} x\) and \(y=m_{2} x\) may be conjugate with respect to the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) is \(m_{1} m_{2}=-\frac{b^{2}}{a^{2}}\). Note that the eccentric angles of the extremities of two conjugate semi-diameters differ by a right angle. If \(C P\) and \(C D\) be any two conjugate semi-diameters of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\), then the tangents at \(P\) and \(D\) intersect on the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=k\), where \(k=\) (A) 1 (B) 2 (C) 4 (D) 16
5 step solution
Problem 77
In the following questions an Assertion \((A)\) is given followed by a Reason (R). Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason( \(\mathrm{R}\) ) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion: The combined equation of the asymptotes of the hyperbola \(2 x^{2}+5 x y+2 y^{2}+4 x+5 y+2=0\) Reason: The equation of a hyperbola and its asymptotes differ in constant terms only.
4 step solution
Problem 78
In the following questions an Assertion \((A)\) is given followed by a Reason (R). Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason( \(\mathrm{R}\) ) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion:The locus of the centre of the circle described on any focal chord of a parabola \(y^{2}=4 a x\) as diameter is \(y^{2}\) \(=2 a(x-a)\) Reason: If \(A\left(a t_{1}^{2}, 2 a t_{1}\right)\) and \(B\left(a t_{2}^{2}, 2 a t_{2}\right)\) be the extremities of a focal chord for the parabola \(y^{2}=4 a x\), then \(t_{12}=t_{2}=-1\)
5 step solution
Problem 79
In the following questions an Assertion \((A)\) is given followed by a Reason (R). Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason( \(\mathrm{R}\) ) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion: The angle of intersection between the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) and the circle \(x^{2}+y^{2}=a b\) is \(\tan ^{-1} \frac{(b-a)}{\sqrt{a b}}\) Reason: The point of intersection of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) and the circle \(x^{2}+y^{2}=a b\) is \(\left(\sqrt{\frac{a^{2} b}{a+b}},\right.\), \(\left.\sqrt{\frac{a b^{2}}{a+b}}\right)\)
4 step solution
Problem 80
The radius of the circle passing through the foci of the ellipse \(\frac{x^{2}}{16}+\frac{y^{2}}{9}=1\) and having its centre at \((0,3)\), is: (A) 4 unit (B) 3 unit (C) \(\sqrt{12}\) unit (D) \(\frac{7}{2}\) unit
5 step solution
Problem 81
The equation of the ellipse whose foci are \((\pm 2,0)\) and eccentricity is \(\frac{1}{2}\) is: (A) \(\frac{x^{2}}{12}+\frac{y^{2}}{16}=1\) (B) \(\frac{x^{2}}{16}+\frac{y^{2}}{12}=1\) (C) \(\frac{x^{2}}{16}+\frac{y^{2}}{8}=1\) (D) none of these
6 step solution
Problem 82
The equation of the chord joining two points \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right)\) on the rectangular hyperbola \(x y=c^{2}\) is : (A) \(\frac{x}{x_{1}+x_{2}}+\frac{y}{y_{1}+y_{2}}=1\) (B) \(\frac{x}{x_{1}-x_{2}}+\frac{y}{y_{1}-y_{2}}=1\) (C) \(\frac{x}{y_{1}+y_{2}}+\frac{y}{x_{1}+x_{2}}=1\) (D) \(\frac{x}{y_{i}-y_{2}}+\frac{y}{x_{1}-x_{2}}=1\)
5 step solution
Problem 84
The foci of the ellipse \(\frac{x^{2}}{16}+\frac{y^{2}}{b^{2}}=1\) and the hyperbola \(\frac{x^{2}}{144}-\frac{y^{2}}{81}=\frac{1}{25}\) coincide. Then the value of \(b^{2}\) is (A) 1 (B) 5 (C) 7 (D) 9
4 step solution
Problem 85
A point on the parabola \(y^{2}=18 x\) at which the ordinate increases at twice the rate of the abscissa is (A) \((2,4)\) (B) \((2,-4)\) (C) \(\left(\frac{-9}{8}, \frac{9}{2}\right)\) (D) \(\left(\frac{9}{8}, \frac{9}{2}\right)\)
6 step solution
Problem 86
If \(a \neq 0\) and the line \(2 b x+3 c y+4 d=0\) passes through the points of intersection of the parabolas \(y^{2}=4 a x\) and \(x^{2}=4 a y\), then (A) \(d^{2}+(2 b+3 c)^{2}=0\) (B) \(d^{f}+(3 b+2 c)^{2}=0\) (C) \(d^{2}+(2 b-3 c)^{2}=0\) (D) \(f+(3 b-2 c)^{2}=0\)
4 step solution
Problem 88
Area of the greatest rectangle that can be inscribed in the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) is (A) \(2 a b\) (B) \(a b\) (C) \(\sqrt{a b}\) (D) \(\frac{a}{b}\)
8 step solution
Problem 89
The locus of a point \(P(\alpha, \beta)\) moving under the condition that the line \(y=\alpha x+\beta\) is a tangent to the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) is (A) an ellipse (B) a circle (C) a parabola (D) a hyperbola
4 step solution
Problem 90
An ellipse has \(O B\) as semi minor axis, \(F\) and \(F^{\prime}\) its focii and the angle \(F B F^{\prime}\) is a right angle. Then the eccentricity of the ellipse is (A) \(\frac{1}{\sqrt{2}}\) (B) \(\frac{1}{2}\) (C) \(\frac{1}{4}\) (D) \(\frac{1}{\sqrt{3}}\)
5 step solution
Problem 91
In an ellipse, the distance between its foci is 6 and minor axis is 8 . Then its eccentricity is (A) \(\frac{3}{5}\) (B) \(\frac{1}{2}\) (C) \(\frac{4}{5}\) (D) \(\frac{1}{\sqrt{5}}\)
6 step solution
Problem 92
For the hyperbola \(\frac{x^{2}}{\cos ^{2} \alpha}-\frac{y^{2}}{\sin ^{2} \alpha}=1\), which of the following remains constant when \(\alpha\). varies? (A) eccentricity (B) directrix (C) abscissae of vertices (D) abscissae of foci
5 step solution
Problem 93
A focus of an ellipse is at the origin. The directrix is the line \(x=4\) and the eccentricity is \(\frac{1}{2}\), Then the length of the semi-major axis is (A) \(\frac{8}{3}\) (B) \(\frac{2}{3}\) (C) \(\frac{4}{3}\) (D) \(\frac{5}{3}\)
5 step solution
Problem 94
A parabola has the origin as its focus and the line \(x=\) 2 as the directrix. Then the vertex of the parabola is at (A) \((0,2)\) (B) \((1,0)\) (C) \((0,1)\) (D) \((2,0)\)
4 step solution
Problem 95
The ellipse \(x^{2}+4 y^{2}=4\) is inscribed in a rectangle aligned with the coordinate axes, which in turn in inscribed in another ellipse that passes through the point \((4,0)\). Then the equation of the ellipse is (A) \(x^{2}+16 y^{2}=16\) (B) \(x^{2}+12 y^{2}=16\) (C) \(4 x^{2}+48 y^{2}=48\) (D) \(4 x^{2}+64 y^{2}=48\)
5 step solution
Problem 96
If two tangents drawn from a point \(P\) to the parabola \(y_{1}^{2}\) \(=4 x\) are at right angles, then the locus of the point \(P\) is (A) \(2 x+1=0\) (B) \(x=-1\) (C) \(2 x-1=0\) (D) \(x=1\)
5 step solution
Problem 98
An ellipse is drawn by considering a diameter of the circle \((x-1)^{2}+y^{2}=1\) as its semi-minor axis and a diameter of the circle \(x^{2}+(y-2)^{2}=4\) as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (A) \(4 x^{2}+y^{2}=4\) (B) \(x^{2}+4 y^{2}=8\) (C) \(4 x^{2}+y^{2}=8\) (D) \(x^{2}+4 y^{2}=16\)
6 step solution
Problem 99
Given: A circle, \(2 x^{2}+2 y^{2}=5\) and a parabola, \(y^{2}=4 \sqrt{5 x}\) Statement - I: An equation of a common tangent to these curves is \(y=x+\sqrt{5}\). Statement - II: If the line, \(y=m x+\frac{\sqrt{5}}{m}(m \neq 0)\) is their common tangent, then \(m\) satisfies \(m^{4}-3 m^{2}+2=0\). (A) Statement - \(I\) is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I (B) Statement \(-\mathrm{I}\) is True; Statement -II is False. (C) Statement -I is False; Statement -II is True (D) Statement \(-\mathrm{I}\) is True; Statement -II is True; Statement-II is a correct explanation for Statement-I
6 step solution
Problem 100
The circle passing through the foci of the ellipse \(\frac{x^{2}}{16}+\frac{y^{2}}{4}=1\) with center at \((0,3)\) has equation (A) \(x^{2}+y^{2}-6 y+7=0\) (B) \(x^{2}+y^{2}-6 y-5=0\) (C) \(x^{2}+y^{2}-6 y+5=0\) (D) \(x^{2}+y^{2}-6 y-7=0\)
5 step solution
Problem 101
The locus of the foot of the perpendicular drawn from the centre of the ellipse \(x^{2}+3 y^{2}=6\) on any tangent to it is (A) \(\left(x^{2}-y^{2}\right)^{2}=6 x^{2}+2 y^{2}\) (B) \(\left(x^{2}-y^{2}\right)^{2}=6 x^{2}-2 y^{2}\) (C) \(\left(x^{2}+y^{2}\right)^{2}=6 x^{2}+2 y^{2}\) (D) \(\left(x^{2}+y^{2}\right)^{2}=6 x^{2}-2 y^{2}\)
5 step solution
Problem 102
The slope of the line touching both the parabolas \(y^{2}=\) \(4 x\) and \(x^{2}=-32 y\) is (A) \(\frac{1}{2}\) (B) \(\frac{3}{2}\) (C) \(\frac{1}{8}\) (D) \(\frac{2}{3}\)
7 step solution
Problem 103
Let \(O\) be the vertex and \(Q\) be any point on the parabola, \(x^{2}=8 y\). If the point \(P\) divides the line segment \(O Q\) internally in the ratio \(1: 3\), then the locus of \(P\) is: (A) \(y^{2}=x\) (B) \(y^{2}=2 x\) (C) \(x^{2}=2 y\) (D) \(x^{2}=y\)
5 step solution
Problem 104
The area (in sq. units) of the quadrilateral formed by the tangents at the end points of the latus rectum to the ellipse \(\frac{x^{2}}{9}+\frac{y^{2}}{5}=1\), is: (A) 18 (B) \(\frac{27}{2}\) (C) 27 (D) \(\frac{27}{4}\)
6 step solution
Problem 105
The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between its foci, is (A) \(\sqrt{3}\) (B) \(\frac{4}{3}\) (C) \(\frac{4}{\sqrt{3}}\) (D) \(\frac{2}{\sqrt{3}}\)
6 step solution
Problem 106
Let \(P\) be the point on the parabola, \(y^{2}=8 x\) which is at a minimum distance from the cente \(C\) of the circle, \(x^{2}\) \(+(y+6)^{2}=1\). Then the equation of the circle, passing through \(C\) and having its centre at \(P\) is (A) \(x^{2}+y^{2}-4 x+9 y+18=0\) (B) \(x^{2}+y^{2}-4 x+8 y+12=0\) (C) \(x^{2}+y^{2}-x+4 y+12=0\) (D) \(x^{2}+y^{2}-\frac{x}{4}+2 y-24=0\)
8 step solution
Problem 107
The centres of those circles which touch the circle, \(x^{2}\) \(+y^{2}-8 x-8 y-4=0\), externally and also touch the \(x\)-axis, lie on (A) A parabola (B) A circle (C) An ellipse which is not a circle (D) A hyperbola
7 step solution