Chapter 9

Advanced Engineering Mathematics · 776 exercises

Problem 11

(a) Find the image of the region \(S: 0 \leq u \leq 1,0 \leq v \leq 1\) under the transformation \(x=u-u v, y=u v\). (b) Explain why the transformation is not one-to-one on the boundary of \(S\).

5 step solution

Problem 11

Use Stokes' theorem to evaluate \(\oint_{C} \mathbf{F} \cdot d \mathbf{r}\). Assume \(C\) is oriented counterclockwise as viewed from above. $$ \begin{aligned} &\mathbf{F}=x \mathbf{i}+x^{3} y^{2} \mathbf{j}+z \mathbf{k} ; C \text { the boundary of the semi-ellipsoid }\\\ &z=\sqrt{4-4 x^{2}-y^{2}} \text { in the plane } z=0 \end{aligned} $$

5 step solution

Problem 11

Use Green's theorem to evaluate the given line integral. $$ \begin{aligned} &\oint_{C} x y d x+x^{2} d y \text { , where } C \text { is the boundary of the region }\\\ &\begin{array}{lll} \text { determined by the graphs of } x & 0, x^{2}+y^{2} & 1, x \geq 0 \end{array} \end{aligned} $$

8 step solution

Problem 11

In Problems \(7-16, \mathbf{r}(t)\) is the position vector of a moving particle. Find the tangential and normal components of the acceleration at any \(t\). $$ \mathbf{r}(t)=2 t \mathbf{i}+t^{2} \mathbf{j} $$

5 step solution

Problem 11

Sketch the region of integration for the given iterated integral. $$ \int_{-1}^{3} \int_{0}^{\sqrt{16-y^{2}}} f(x, y) d x d y $$

4 step solution

Problem 11

In Problems, determine whether the given vector field is a conservative field. If so, find a potential function \(\phi\) for \(\mathbf{F}\). $$ \mathbf{F}(x, y)=\left(4 x^{3} y^{3}+3\right) \mathbf{i}+\left(3 x^{4} y^{2}+1\right) \mathbf{j} $$

5 step solution

Problem 11

Evaluate \(\int_{C} y d x+x d y\) on the given curve \(C\) between \((0,0)\) and \((1,1)\). $$ y=x^{2} $$

5 step solution

Problem 11

In Problems \(7-16\), find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=3 x^{2} y \mathbf{i}+2 x z^{3} \mathbf{j}+y^{4} \mathbf{k} $$

5 step solution

Problem 11

Sketch the level curve or surface passing through the indicated point. Sketch the gradient at the point. $$ F(x, y, z)=\sqrt{x^{2}+y^{2}+z^{2} ;}(3,4,0) $$

5 step solution

Problem 11

$$ \begin{aligned} &\text { Graph some of the level surfaces associated with } F(x, y, z)=\\\ &x^{2}+y^{2}-z^{2} \text { for } c=0, c>0, \text { and } c<0 \end{aligned} $$

5 step solution

Problem 11

A shell is fired from ground level with an initial speed of \(480 \mathrm{ft} / \mathrm{s}\) at an angle of elevation of \(30^{\circ}\). Find: (a) a vector function and parametric equations of the shell's trajectory, (b) the maximum altitude attained, (c) the range of the shell, and (d) the speed at impact.

7 step solution

Problem 11

In Problems, find the directional derivative of the given function at the given point in the indicated direction. $$ f(x, y)=5 x^{3} y^{6} ;(-1,1), \theta=\pi / 6 $$

5 step solution

Problem 11

In Problems, find the vector function that describes the curve \(C\) of intersection between the given surfaces. Sketch the curve \(C\). Use the indicated parameter. $$ z=x^{2}+y^{2}, y=x ; x=t $$

4 step solution

Problem 11

Change the indicated order of integration to each of the other five orders. $$ \int_{0}^{2} \int_{0}^{4-2 y} \int_{x+2 y}^{4} F(x, y, z) d z d x d y $$

6 step solution

Problem 11

Determine whether the given vector field is a conservative field. If so, find a potential function \(\phi\) for \(\mathbf{F}\). $$ \mathbf{F}(x, y)=\left(4 x^{3} y^{3}+3\right) \mathbf{i}+\left(3 x^{4} y^{2}+1\right) \mathbf{j} $$

4 step solution

Problem 11

Find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=3 x^{2} y \mathbf{i}+2 x z^{3} \mathbf{j}+y^{4} \mathbf{k} $$

3 step solution

Problem 11

Graph some of the level surfaces associated with \(F(x, y, z)=\) \(x^{2}+y^{2}-z^{2}\) for \(c=0, c>0\), and \(c<0\).

4 step solution

Problem 11

\(\mathbf{r}(t)\) is the position vector of a moving particle. Find the tangential and normal components of the acceleration at any \(t\). $$ \mathbf{r}(t)=2 t \mathbf{i}+t^{2} \mathbf{j} $$

5 step solution

Problem 11

Find the vector function that describes the curve \(C\) of intersection between the given surfaces. Sketch the curve \(C\). Use the indicated parameter. $$ z=x^{2}+y^{2}, y=x ; x=t $$

5 step solution

Problem 12

Use the divergence theorem to find the outward flux \(\iint_{S}(\mathbf{F} \cdot \mathbf{n}) d S\) of the given vector field \(\mathbf{F}\). $$ \begin{aligned} &\mathbf{F}=15 x^{2} y \mathbf{i}+x^{2} z \mathbf{j}+y^{4} \mathbf{k} ; D \text { the region bounded by } x+y=2\\\ &z=x+y, z=3, x=0, y=0 \end{aligned} $$

6 step solution

Problem 12

Use Stokes' theorem to evaluate \(\oint_{C} \mathbf{F} \cdot d \mathbf{r}\). Assume \(C\) is oriented counterclockwise as viewed from above. \(\mathbf{F}=z \mathbf{i}+x \mathbf{j}+y \mathbf{k} ; \boldsymbol{C}\) the curve of intersection of the plane \(x+y+z=0\) and the sphere \(x^{2}+y^{2}+z^{2}=1[\) Hint \(:\) Recall that the area of an ellipse \(x^{2} / a^{2}+y^{2} / b^{2}=1\) is \(\pi a b\). \(]\)

6 step solution

Problem 12

Use Green's theorem to evaluate the given line integral. $$ \begin{aligned} &\oint_{C} e^{x^{2}} d x+2 \tan ^{-1} x d y \text { , where } C \text { is the triangle with vertices }\\\ &(0,0),(0,1),(-1,1) \end{aligned} $$

7 step solution

Problem 12

In Problems \(7-16, \mathbf{r}(t)\) is the position vector of a moving particle. Find the tangential and normal components of the acceleration at any \(t\). $$ \mathbf{r}(t)=\tan ^{-1} t \mathbf{i}+\frac{1}{2} \ln \left(1+t^{2}\right) \mathbf{j} $$

5 step solution

Problem 12

Sketch the region of integration for the given iterated integral. $$ \int^{2} \int^{x^{2}+1} f(x, y) d y d x $$

5 step solution

Problem 12

In Problems, determine whether the given vector field is a conservative field. If so, find a potential function \(\phi\) for \(\mathbf{F}\). $$ \mathbf{F}(x, y)=2 x y^{3} \mathbf{i}+3 y^{2}\left(x^{2}+1\right) \mathbf{j} $$

2 step solution

Problem 12

Evaluate \(\int_{C} y d x+x d y\) on the given curve \(C\) between \((0,0)\) and \((1,1)\). $$ y=x $$

6 step solution

Problem 12

In Problems \(7-16\), find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=5 y^{3} \mathbf{i}+\left(\frac{1}{2} x^{3} y^{2}-x y\right) \mathbf{j}-\left(x^{3} y z-x z\right) \mathbf{k} $$

7 step solution

Problem 12

Sketch the level curve or surface passing through the indicated point. Sketch the gradient at the point. $$ F(x, y, z)=x^{2}-y^{2}+z ;(0,-1,1) $$

6 step solution

Problem 12

Given that $$ F(x, y, z)=\frac{x^{2}}{16}+\frac{y^{2}}{4}+\frac{z^{2}}{9} $$ find the \(x-, y\) -, and \(z\) -intercepts of the level surface that passes through \((-4,2,-3)\)

4 step solution

Problem 12

In Problems, find the directional derivative of the given function at the given point in the indicated direction. $$ f(x, y)=4 x+x y^{2}-5 y ;(3,-1), \theta=\pi / 4 $$

7 step solution

Problem 12

In Problems, find the vector function that describes the curve \(C\) of intersection between the given surfaces. Sketch the curve \(C\). Use the indicated parameter. $$ x^{2}+y^{2}-z^{2}=1, y=2 x ; x=t $$

5 step solution

Problem 12

Fill in the blank or answer true/false. Where appropriate, assume continuity of \(P, O\), and their first partial derivatives. In a conservative force field \(\mathrm{F}\), the work done by \(\mathrm{F}\) around a simple closed curve is zero.___

4 step solution

Problem 12

Determine whether the given vector field is a conservative field. If so, find a potential function \(\phi\) for \(\mathbf{F}\). $$ \mathbf{F}(x, y)=2 x y^{3} \mathbf{i}+3 y^{2}\left(x^{2}+1\right) \mathbf{j} $$

4 step solution

Problem 12

Find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=5 y^{3} \mathbf{i}+\left(\frac{1}{2} x^{3} y^{2}-x y\right) \mathbf{j}-\left(x^{3} y z-x z\right) \mathbf{k} $$

8 step solution

Problem 12

Find the directional derivative of the given function at the given point in the indicated direction. $$ f(x, y)=4 x+x y^{2}-5 y ;(3,-1), \quad \theta=\pi / 4 $$

5 step solution

Problem 12

\(\mathbf{r}(t)\) is the position vector of a moving particle. Find the tangential and normal components of the acceleration at any \(t\). $$ \mathbf{r}(t)=\tan ^{-1} t \mathbf{i}+\frac{1}{2} \ln \left(1+t^{2}\right) \mathbf{j} $$

5 step solution

Problem 12

Find the vector function that describes the curve \(C\) of intersection between the given surfaces. Sketch the curve \(C\). Use the indicated parameter. $$ x^{2}+y^{2}-z^{2}=1, y=2 x ; x=t $$

6 step solution

Problem 13

Evaluate the given integral by means of the indicated change of variables. $$ \begin{aligned} &\iint_{R}(x+y) d A \text { , where } R \text { is the region bounded by the graphs of }\\\ &x-2 y=-6, x-2 y=6, x+y=-1, x+y=3 ; u=x-2 y\\\ &v=x+y \end{aligned} $$

5 step solution

Problem 13

In Problems 13-16, use Stokes' theorem to evaluate \(\iint_{S}\) (curl \(\left.\mathbf{F}\right) \cdot \mathbf{n} d S\). Assume that the surface \(S\) is oriented upward. $$ \begin{aligned} &\mathbf{F}=6 y z \mathbf{i}+5 x \mathbf{j}+y z e^{x^{2}} \mathbf{k} ; S \text { that portion of the paraboloid }\\\ &z=\frac{1}{4} x^{2}+y^{2} \text { for } 0 \leq z \leq 4 \end{aligned} $$

9 step solution

Problem 13

Use Green's theorem to evaluate the given line integral. \(\oint_{C} \frac{1}{3} y^{3} d x+\left(x y+x y^{2}\right) d y\), where \(C\) is the boundary of the region in the first quadrant determined by the graphs of \(y \quad 0\), \(x \quad y^{2}, x \quad 1-y^{2}\)

7 step solution

Problem 13

In Problems \(7-16, \mathbf{r}(t)\) is the position vector of a moving particle. Find the tangential and normal components of the acceleration at any \(t\). $$ \mathbf{r}(t)=2 \cos t 1+2 \sin t \mathrm{~J} $$

5 step solution

Problem 13

Find the surface area of that portion of the sphere \(x^{2}+y^{2}+z^{2}=a^{2}\) that is bounded between \(y=c_{1}\) and \(y=c_{2}\), \(0

8 step solution

Problem 13

Evaluate the double integral over the region \(R\) that is bounded by the graphs of the given equations. Choose the most convenient order of integration. $$ \iint_{R} x^{3} y^{2} d A ; y=x, y=0, x=1 $$

6 step solution

Problem 13

In Problems, determine whether the given vector field is a conservative field. If so, find a potential function \(\phi\) for \(\mathbf{F}\). $$ \mathbf{F}(x, y)=y^{2} \cos x y^{2} \mathbf{i}-2 x y \sin x y^{2} \mathbf{j} $$

2 step solution

Problem 13

Evaluate \(\int_{C} y d x+x d y\) on the given curve \(C\) between \((0,0)\) and \((1,1)\). \(C\) consists of the line segments from \((0,0)\) to \((0,1)\) and from \((0,1)\) to \((1,1)\).

5 step solution

Problem 13

In Problems \(7-16\), find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=x e^{-z} \mathbf{i}+4 y z^{2} \mathbf{j}+3 y e^{-z} \mathbf{k} $$

6 step solution

Problem 13

Find the points on the given surface at which the gradient is parallel to the indicated vector. $$ z=x^{2}+y^{2} ; 4 \mathbf{i}+\mathbf{j}+\frac{1}{2} \mathbf{k} $$

5 step solution

Problem 13

Find the first partial derivatives of the given function. $$ z=x^{2}-x y^{2}+4 y^{5} $$

3 step solution

Problem 13

A used car is pushed off an 81 -ft-high sheer seaside cliff with a speed of \(4 \mathrm{ft} / \mathrm{s}\). Find the speed at which the car hits the water.

6 step solution

Problem 13

In Problems, find the directional derivative of the given function at the given point in the indicated direction. $$ f(x, y)=\tan ^{-1} \frac{y}{x} ;(2,-2), \mathbf{i}-3 \mathbf{j} $$

6 step solution

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