Chapter 16

Chemistry Matter and Change · 63 exercises

Problem 7

Explain why the average rate of a reaction depends on the length of the time interval over which the rate is measured.

4 step solution

Problem 8

Describe the relationship between activation energy and the rate of a reaction.

6 step solution

Problem 9

Summarize what happens during the brief existence of an activated complex.

4 step solution

Problem 10

Apply collision theory to explain why collisions between two reacting particles do not always result in the formation of a product.

4 step solution

Problem 12

Calculate the average rate of a reaction between hypothetical molecules \(A\) and \(B\) if the concentration of \(A\) changes from 1.00\(M\) to 0.50\(M\) in 2.00 s.

5 step solution

Problem 14

Explain how collision theory accounts for the effect of concentration on reaction rate.

4 step solution

Problem 15

Explain the difference between a catalyst and an inhibitor.

3 step solution

Problem 16

Describe the effect on the rate of a reaction if one of the reactants is ground to a powder rather than used as a single chunk.

3 step solution

Problem 17

Infer If increasing the temperature of a reaction by 10 K approximately doubles the reaction rate, what would be the effect of increasing the temperature by 20 K?

4 step solution

Problem 18

Research how catalysts are used in industry, in agriculture, or in the treatment of contaminated soil, waste, or water. Write a short report summarizing your findings about the role of a catalyst in one of these applications.

5 step solution

Problem 19

Write the rate law for the reaction \(a A \rightarrow b B\) if the reaction is third order in \(A\) . \([B]\) is not part of the rate law.

3 step solution

Problem 20

The rate law for the reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}] \rightarrow 2 \mathrm{NO}_{2}(\mathrm{g})\) is first order in \(\mathrm{O}_{2}\) and third order overall. What is the rate law for the reaction?

4 step solution

Problem 23

MAIN Idea Explain what the rate law for a chemical reaction tells you about the reaction.

5 step solution

Problem 24

Apply the rate-law equations to show the difference between a first-order reaction with a single reactant and a second-order reaction with a single reactant.

5 step solution

Problem 25

Explain the function of the specific rate constant in a rate-law equation.

5 step solution

Problem 26

Explain Under what circumstance is the specific rate constant (k), not a constant. What does the size of \(k\) indicate about the rate of a reaction?

3 step solution

Problem 27

Suggest a reason why, when given the rate of a chemical reaction, it is important to know that the reaction rate is an average reaction rate.

3 step solution

Problem 29

Determine the overall reaction order for a reaction between \(A\) and \(B\) for which the rate law is rate \(=k[A]^{2}[B]^{2}\) .

3 step solution

Problem 36

Define a reaction mechanism and an intermediate

4 step solution

Problem 37

Distinguish between an intermediate and an activated complex.

5 step solution

Problem 38

Relate the size of the activation energy of an elementary step in a complex reaction to the rate of that step.

3 step solution

Problem 39

Calculate A reaction between \(A\) and \(B\) to form AB is first order in \(A\) and first order in B. The rate constant, \(k,\) equals 0.500 \(\mathrm{mol} /(\mathrm{L} \cdot \mathrm{s}) .\) What is the rate of the reaction when \([\mathrm{A}]=2.00 \times 10^{-2} M\) and \([\mathrm{B}]=1.50 \times 10^{-2} \mathrm{M?}\)

4 step solution

Problem 40

What happens to the concentrations of the reactants and products during the course of a chemical reaction?

5 step solution

Problem 41

Explain what is meant by the average rate of a reaction.

4 step solution

Problem 43

What is the role of the activated complex in a chemical reaction?

3 step solution

Problem 46

In the gas-phase reaction, \(\mathrm{I}_{2}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{ICl},\left[\mathrm{I}_{2}\right]\) changes from 0.400 \(\mathrm{M}\) at 0.00 min to 0.300 \(\mathrm{M}\) at 4.00 \(\mathrm{min.}\) Calculate the average reaction rate in moles of \(\mathrm{I} 2 \mathrm{con}\) . sumed per liter per minute.

5 step solution

Problem 47

In the gas-phase reaction, \(\mathrm{I}_{2}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{ICl},\left[\mathrm{I}_{2}\right]\) changes from 0.400 \(\mathrm{M}\) at 0.00 \(\mathrm{min}\) to 0.300 \(\mathrm{M}\) at 4.00 \(\mathrm{min.}\) Calculate the average reaction rate in moles of 12 con- sumed per liter per minute.

4 step solution

Problem 48

In a reaction \(\mathrm{Mg}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{H}_{2}(\mathrm{g})+\mathrm{MgCl}_{2}(\mathrm{aq}),\) 6.00 \(\mathrm{g}\) of Mg was present at 0.00 \(\mathrm{min}\) . After 3.00 \(\mathrm{min}\) , 4.50 gof Mg remained. Express the average rate as mol Mg consumed/min.

4 step solution

Problem 49

If a chemical reaction occurs at the rate of \(2.25 \times 10^{-2}\) moles per liter per second at 322 \(\mathrm{K}\) , what is the rate expressed in moles per liter per minute?

4 step solution

Problem 50

What role does the reactivity of the reactants play in determining the rate of a chemical reaction?

4 step solution

Problem 51

In general, what is the relationship between reaction rate and reactant concentration?

5 step solution

Problem 52

Apply collision theory to explain why increasing the concentration of a reactant usually increases the reaction rate.

3 step solution

Problem 53

Explain why a crushed solid reacts with a gas more quickly than a large chunk of the same solid.

4 step solution

Problem 54

Food Preservation Apply collision theory to explain why foods usually spoil more slowly when refrigerated than at room temperature.

5 step solution

Problem 55

Apply collision theory to explain why powdered zinc reacts to form hydrogen gas faster than large pieces of zinc when both are placed in hydrochloric acid solution.

3 step solution

Problem 56

Hydrogen peroxide decomposes to water and oxygen gas more rapidly when manganese dioxide is added. The manganese dioxide is not consumed in the reaction. Explain the role of the manganese dioxide.

4 step solution

Problem 60

In the method of initial rates used to determine the rate law for a chemical reaction, what is the significance of the word initial?

4 step solution

Problem 61

Why must the rate law for a chemical reaction be based on experimental evidence rather than the balanced equation for the reaction?

3 step solution

Problem 62

Why must the rate law for a chemical reaction be based on experimental evidence rather than the balanced equation for the reaction?

4 step solution

Problem 63

Consider the generic chemical reaction: \(A+B \rightarrow A B\) . Based on experimental data, the reaction is second order in Reactant A. If the concentration of \(\mathrm{A}\) is halved, and all other conditions remain unchanged, how does the reaction rate change?

4 step solution

Problem 65

Suppose that a generic chemical reaction has the rate law of rate \(=[A]^{2}[B]^{3}\) and that the reaction rate under a given set of conditions is \(4.5 \times 10^{-4} \mathrm{mol} /(\mathrm{L} \cdot \min ) .\) If the concentrations of both \(\mathrm{A}\) and \(\mathrm{B}\) are doubled and all other reaction conditions remain constant, how will the reaction rate change?

6 step solution

Problem 67

Use the data in Table 16.4 to calculate the value of the specific rate constant, \(k\). $$ \begin{array}{|c|c|c|} \hline \begin{array}{c} \text { Experiment } \\ \text { Number } \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{CH}_{3} \mathrm{~N}_{2} \mathrm{CH}_{3}\right]} \end{array} & \begin{array}{c} \text { Initial } \\ \text { Reaction Rate } \end{array} \\ \hline 1 & 0.012 M & 2.5 \times 10^{-6} \mathrm{~mol} /(\mathrm{L} \cdot \mathrm{s}) \\ \hline 2 & 0.024 M & 5.0 \times 10^{-6} \mathrm{~mol} /(\mathrm{L} \cdot \mathrm{s}) \\ \hline \end{array} $$

5 step solution

Problem 69

Distinguish between a complex reaction, a reaction mechanism, and an elementary step.

3 step solution

Problem 70

Suppose that a chemical reaction takes place in a two- step mechanism. Step \(1(\) fast \() A+B \rightarrow C\) Step \(2(\) slow \() C+D \rightarrow E\) Which step in the reaction mechanism is the rate- determining step? Explain.

4 step solution

Problem 73

Dinitrogen pentoxide decomposes in chloroform at a rate of \(2.48 \times 10^{-4} \mathrm{mol} /(\mathrm{L} \cdot \mathrm{min})\) at a particular tempera- ture according to the equation \(2 \mathrm{N}_{2} \mathrm{O}_{5} \rightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2}\) The reaction is first order in \(\mathrm{N}_{2} \mathrm{O}_{5}\) . Given an initial concentration \(0.400 \mathrm{mol} / \mathrm{L},\) what is the rate constant for the reaction? What is the approximate \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]\) after the reaction proceeds for 1.30 \(\mathrm{h} ?\)

6 step solution

Problem 74

Radioactive decay is first order in the decaying isotope. For example, strontium-90 contained in fallout from nuclear explosions decays to yttrium-90 and a beta particle. Write the rate law for the decay of strontium-90.

3 step solution

Problem 75

Evaluate the validity of this statement: You can determine the rate law for a chemical reaction by examining the mole ratio of reactants in the balanced equation. Explain your answer.

5 step solution

Problem 76

The concentration of Reactant A decreases from 0.400 mol/L at 0.00 min to 0.384 moll at 4.00 min. Calculate the average reaction rate during this time period. Express the rate in mol/(L.min).

4 step solution

Problem 78

If the concentration of a reaction product increases from 0.0882 \(\mathrm{mol} / \mathrm{L}\) to 0.1446 \(\mathrm{mol} / \mathrm{L}\) in 12.0 minutes, what is the average reaction rate during the time interval?

4 step solution

Problem 79

A two-step mechanism has been proposed for the decomposition of nitryl chloride \(\left(\mathrm{NO}_{2} \mathrm{CL}\right) .\) \begin{equation} \begin{array}{l}{\text { Step } 1 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})} \\ {\text { Step } 2 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g})+\mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})}\end{array} \end{equation} What is the overall reaction? Identify any intermediates in the reaction sequence, and explain why they are called intermediates.

3 step solution

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