Problem 79
Question
A two-step mechanism has been proposed for the decomposition of nitryl chloride \(\left(\mathrm{NO}_{2} \mathrm{CL}\right) .\) \begin{equation} \begin{array}{l}{\text { Step } 1 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})} \\ {\text { Step } 2 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g})+\mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})}\end{array} \end{equation} What is the overall reaction? Identify any intermediates in the reaction sequence, and explain why they are called intermediates.
Step-by-Step Solution
Verified Answer
The overall reaction is \( 2 \text{NO}_2 \text{Cl (g)} \rightarrow 2 \text{NO}_2 \text{ (g)} + \text{Cl}_2 \text{ (g)} \). The intermediate is \( \text{Cl (g)} \).
1Step 1: Write Out Given Mechanism Steps
The given reaction mechanism has two steps: \( \text{Step 1: NO}_2 \text{Cl (g)} \rightarrow \text{NO}_2 \text{ (g)} + \text{Cl (g)} \) and \( \text{Step 2: NO}_2 \text{Cl (g)} + \text{Cl (g)} \rightarrow \text{NO}_2 \text{ (g)} + \text{Cl}_2 \text{ (g)} \). These steps represent the proposed pathway for the decomposition of nitryl chloride.
2Step 2: Identify and Summarize the Overall Reaction
To find the overall reaction, sum the reactants and products from the two steps. Cancel out any species that appear on both sides. \( \text{Step 1 produces Cl (g) which is consumed in Step 2; thus, cancel } \text{Cl (g)} \). The overall reaction is \( 2 \text{NO}_2 \text{Cl (g)} \rightarrow 2 \text{NO}_2 \text{ (g)} + \text{Cl}_2 \text{ (g)} \).
3Step 3: Identify the Intermediates
An intermediate is a species that is formed in one step and consumed in a subsequent step, not appearing in the overall reaction. Here, \( \text{Cl (g)} \) is produced in Step 1 and consumed in Step 2. Therefore, \( \text{Cl (g)} \) is the intermediate.
Key Concepts
Chemical DecompositionIntermediate SpeciesOverall Reaction EquationNitryl Chloride Decomposition
Chemical Decomposition
Chemical decomposition refers to the process where a single compound breaks down into two or more simpler substances. This process is often influenced by factors such as heat, light, or a catalyst.
There are several key points to remember about chemical decomposition:
There are several key points to remember about chemical decomposition:
- It involves a chemical change, as new substances are formed.
- The original compound, or reactant, is separated into smaller molecules, atoms, or ions.
- Energy often needs to be absorbed to break the bonds in the original compound.
Intermediate Species
In a chemical reaction, intermediate species play a crucial role but are not seen in the final reaction's equation. They are quite fascinating because they only appear in the early part of a reaction and are used up before the reaction finishes.
To understand intermediates better, consider the following characteristics:
To understand intermediates better, consider the following characteristics:
- They are produced in one step and consumed in another.
- Intermediates are typically unstable or have a short lifetime.
- They don't appear in the overall chemical equation.
Overall Reaction Equation
The overall reaction equation provides a snapshot of the net change from reactants to products for a chemical process. It summarizes the entire process, excluding any intermediate species.
Here's how you can determine the overall reaction equation:
Here's how you can determine the overall reaction equation:
- Combine all individual reaction steps, listing out reactants and products.
- Cancel out intermediate species, which appear on both sides of the equation.
- Rearrange and simplify the reaction components to reflect the complete journey from start to finish.
Nitryl Chloride Decomposition
The decomposition of nitryl chloride showcases an intriguing chemical process where one compound breaks down into others via a specific pathway. This decomposition is neatly explained by a two-step mechanism:
- Step 1: \( \text{NO}_2 \text{Cl (g)} \) breaks into \( \text{NO}_2 \text{ (g)} \) and \( \text{Cl (g)} \)
- Step 2: \( \text{NO}_2 \text{Cl (g)} \) combines with \( \text{Cl (g)} \) to form \( \text{NO}_2 \text{ (g)} \) and \( \text{Cl}_2 \text{ (g)} \)
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